form-submit

Is there any chance to handle when form submit finished( ok or error )? I want to upload images or mulitpart data without javascript libraries . For example, user clicks submit button, after uploading data server responds with error or success response. Depending on that result I need to do something. Here is example form: <form method="post" enctype="multipart/form-data" action="/upload_file"> <input type="file" name="upload_image" /> <input type="submit" value="Submit" /> </form> Since I've not access to the server side, I need to solve this problem on the client side. That's why I couldn't

It seems like eveyone has this problem but no one has a laymans terms answer or even a proper solutions. I have a form that uses ajax to submit the form and automatically adds it to the list below the text field. The form submits twice so i have two identical (apart form the ID) records. Worse still is when you try to delete it wont renew the page because its tried to delete the same record twice. I hope someone has a great answer out there... btw im new to rails. code: index.html.erb <h1>SSCC</h1> <div id="orderline_form"> <%= render 'form' %> </div> <ul id="orderlines"> <%= render :partial =

I have two HTML selects in a form. The first is called available and contains several options: <select name="sortedby" multiple="multiple"> <option value="start"> <xsl:if test="@sortedby='start'"> <xsl:attribute name="selected">true</xsl:attribute> </xsl:if> Start time </option> <option value="thread_id"> <xsl:if test="@sortedby='thread_id'"> <xsl:attribute name="selected">true</xsl:attribute> </xsl:if> Thread Id </option> <option value="user_name"> <xsl:if test="@sortedby='user_name'"> <xsl:attribute name="selected">true</xsl:attribute> </xsl:if> Username </option> </select> The second is

I have a very simple form in HTML and I'd like to submit this form after 2000ms (of delay) from when the document is ready, without push the submit button. How can I do this with a jQuery script? <form id="my_form" action="NextPage.php" method="post"> <fieldset class="my_fieldset"> <input type="radio" name="my_radio" value="value_A" checked="checked"/>Value A<br/> <input type="radio" name="my_radio" value="value_B"/>Value B<br/> </fieldset> <input type="submit" value="Send" id="Send" tabindex="110"> </form> I can't find a command to say "when ... submit the form". You need to wait with delay()

I'm using PHP to pass a login form when required, and here is the code: $htmlForm = '<form id="frmlogin">'.'<label>'; switch(LOGIN_METHOD) { case 'both': $htmlForm .= $ACL_LANG['USERNAME'].'/'.$ACL_LANG['EMAIL']; break; case 'email': $htmlForm .= $ACL_LANG['EMAIL']; break; default: $htmlForm .= $ACL_LANG['USERNAME']; break; } $htmlForm .= ':</label>'. '<input type="text" name="u" id="u" class="textfield" />'. '<label>'.$ACL_LANG['PASSWORD'].'</label>'. '<input type="password" name="p" id="p" class="textfield" />'. '<center><input type="submit" name="btn" id="btn" class="buttonfield" value=

Is there a way to do the above? Basically, I don't want the form to be submitted again if someone presses refresh after already submitting the form once. In which case the browser asks, do you want to submit the form again. Will unset($_POST['username']) be of any help is this case? The post/redirect/get is a good option as some posters have already mentioned. One another way I can think of is to set a session in the dostuff.php page to indicate that the posting has already been done. Check this session var each time to see if the page is being loaded again because of a page refresh. <?php

The code is stuck in a loop when I try to catch a form submission. The purpose is to replace a value of the form before it goes out. $('form').submit(function(e){ e.preventDefault(); $.ajax({ type: "POST", url: 'convert.asp', data: $('form').serialize(), success: function(response){ $('input[name="field1"]').val(response); $('form').submit(); } }); return false; }); Does anyone have any ideas? UPDATE: I originally had it bound to a button click event and it was working but I wanted to preserve the [enter] key element of the submit button. Seeing that the code is kind of illogical, would

I am trying to figure out if there is a relatively simple way (I'm not very skilled at JQuery) to keep the modal open after a form submit. (The form is contained in the modal). If the form is successful or there are errors, my PHP will show them but the modal closes as soon as the submit button is pressed. If I reload the form, I can see the appropriate success or error message so all is working fine, but I'd prefer the end-user to see the message then click to close the modal afterwards. I can post my code if that helps. Thank you. <?php $success_message = "<h3 class='success'>Thank you, your

I got an image with which links to another page using <a href="..."> <img ...> </a> . How can I make it make a post like if it was a button <input type="submit"...> ? <input type="image" name="your_image_name" src="your_image_url.png" /> This will send the your_image_name.x and your_image_name.y values as it submits the form, which are the x and y coordinates of the position the user clicked the image. More generic approatch using JQuery library closest () and submit () buttons. Here you do not have to specify whitch form you want to submit, submits the form it is in. <a href="#" onclick="$