form-submit

I have 4 forms on a page. Form 1 must be submitted with either form 2,3 or 4 depending on user selection. jQuery's .submit() can only do one form. ajax posting the forms is not an option i can only think of adding the content of Form 1 to the other form as before submitting the latter form. is there any other way to do it? UPDATE: The reason for the 4 forms instead of just 1 is that I am validating each form independently, since the 2 of the 3 forms are hidden from view. If one form relies on two other forms, it sounds like they're really part of the same form, and the backend should just

I have this PS script it logins to a site and then it navigate's to another page. I want to save whole source for that page. but for some reason. some parts of source code is not coming across. $username = "myuser" $password = "mypass" $ie = New-Object -com InternetExplorer.Application $ie.visible=$true $ie.navigate("http://www.example.com/login.shtml") while($ie.ReadyState -ne 4) {start-sleep -m 100} $ie.document.getElementById("username").value = "$username" $ie.document.getElementById("pass").value = "$password" $ie.document.getElementById("frmLogin").submit() start-sleep 5 $ie.navigate(

I have a form generated dynamically with the method .append() of jQuery. I can add any number of new input, textbox, cmbbox, etc... But the problem is that when I do the sumbit of the form, the PHP target does not receive the new input added, but just the vars connected to the input already in the form before the append(). Any ideas? The javascript: $("#button").live('click',function add(){ $("#list").append( '<li style="height:20px;">' +'<input type="text" class="text" id="prova" name="prova[]" value="prova">'+ '</li>' ); }); The Html: <input type="submit" id="button" value="Add input"> <form

Is there a reason that the form is still submitting? The validation checks work but if it everything is input correctly, the form submits and the ajax request does not fire. $("#formRegister").submit(function () { // Start problem var mode = $("registerMode").val(); // End problem var username = $("#registerUsername").val(); var password = $("#registerPassword").val(); var passwordConfirm = $("#registerPasswordConfirm").val(); var avatar = $("#registerAvatar").val(); if (username == 'Username') { $("#registerError").html('You must enter a username'); } else if (password == 'Password') { $("

Ok somehow im having the hardest time figuring this out so i want to do an call ajax with a form and im using jquery to serialize it with .serialize(). The data being sent to php looks something like this key1=value&key2=value2&key3=value3 And im using a post request. It looks simple enough, but somehow im having a really hard time figuring out how to access these key/value pairs, i cant use explode() on & because that will give me [0] => key1=value1 [1] => key2=value2 [2] => key3=value3 and i cant use $_POST['key1'] or $_GET['key1'] in php to access these values. What should i do!!! Thanks

I use jquery's .submit() to intercept user's submit event, however I found a problem. When the user single click the submit button, the form is submitted normally, but if a user deliberately fast click it multiple times, it will submit multiple times, which will cause duplicated data in the database. What's the solution for this kind of problem ? Update: Well, I see some of the advice said disabling the submit button. This should prevent the form being submitted multiple times, but the problem is the form element in my page isn't refreshed, if I disable it the user won't be able to submit it