form-submit | 易学教程

How to add a post parameter to manual form submission?

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I want to submit a form manually after some complicated checks. Because checks involve user interaction, the whole check process is not done synchronously. Here is the scenario: User clicks a button (an HTML <button id='button-id'> tag) I prevent the default action of the button (which is the form submission) I do a complicated check. Somewhere in the check process, I show a dialog and wait for the user to respond (here, the original check function proceeds and returns) I provide a callback function for that dialog, which fires and runs when the user closes it (either positive or negative

jQuery slider onChange auto submit form

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I'm using a jQuery slider as a price range selector in a form. I'd like to have the form submit automatically when one of the values has been changed. I used a couple of examples I found on SO but they didn't work with my code. <form action="itemlist.php" method="post" enctype="application/x-www-form-urlencoded" name="priceform" id="priceform" target="_self"> <div id="slider-holder"> Prices: From <span id="pricefromlabel">100 €</span> To <span id="pricetolabel">500 €</span> <input type="hidden" id="pricefrom" name="pricefrom" value="100" /> <input type="hidden" id="priceto" name="priceto"

How do I test a form submit in Jasmine?

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问题 I have a form that does some extensive Javascript stuff before finally POSTing to it's ACTION URL. I am writing some Jasmine unit tests and want to make sure the Javascript stuff happens when the form is submitted. However, I definitely don't want the page to go to the ACTION URL while I am unit testing. I saw what seemed like a good suggestion here: http://groups.google.com/group/jasmine-js/browse_thread/thread/a010eced8db17c1a?pli=1 ...but, as I am fairly new to Jasmine, I am unsure how to

angular event success when submit form it opens popup

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I have a page which post data to a ASPNET MVC page by angular $http.post(..) and when the calling finish I have to submit a form. Basically I do the following: <html ng-app> <body data-ng-controller="testController"> <form id="Checkpay" name="Checkpay" style="margin: 0" method="post" action="https://www.sandbox.paypal.com/cgi-bin/webscr" target="_blank" class="ng-pristine ng-valid"> <input type="hidden" name="quantita" id="qtytext" value="0"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="item_name" value="Le Spose di Nika"> <input type="hidden" name="business"

jQuery how to make Enter (Return) act as Tab key through input text fields but in the end trigger the submit button

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I've blocked Enter (return) key, actually, transformed it in Tab key. So when pressed inside input text fields it acts as Tab key. This is good, but I need it to trigger the submit button when pressed in the last field, below is the code for the Enter key mutation: $('input').keydown(function(event) { if(event.which == 13) { event.preventDefault(); $(this).nextAll('input:first').focus(); } }); And the form code is a sequence of input type="text" and a button type="submit" at the end [Edited] Actually the code is this one, taken from jquery: Enter to Tab trigger in specific parts . But I don't

Submit Event Listener for a form

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I've written an event listener for a form submit that is causing me a few issues. When pressing 'enter' inside the text field everything works fine. However, I have an span (with background-image) that submits the form as well via a click event. This is not working properly and I can't figure out why. Here's the basic HTML: <form name="myForm"> <input type="text" name="search" /> <span id="search-button"></span> </form> Here's the JS for the event listener: function evtSubmit(e) { // code e.preventDefault(); }; var myform = document.myForm; if (myform.addEventListener) { myform

ASP .NET MVC 3 - How to submit an ajax form nested within an html form

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I have an ASP .NET MVC 3 project and a problem with one of my 'Create' views. I have cascading drop-down fields that I have implemented with ajax forms. The view is roughly speaking - like this: @using (Html.BeginForm(...)) { @Html.MyDropDown1 using (Ajax.BeginForm(...)) { @Ajax.MyDropdown2 <input type="submit" value="Select" /> } using (Ajax.BeginForm(...)) { @Ajax.MyDropdown3 <input type="submit" value="Select" /> }  <input type="submit" value="Create" /> } The problem is that the submit buttons inside the ajax forms actually submit the outer html form. Is there any

passing data in form submission via jquery/ajax

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问题 i want to submit a form with about 10 input using jquery/ajax,but i don't know how can i pass the data to it through data parameters of ajax.should i serialize them ? 回答1: The jQuery.serialize can be helpful for you. It is important that you use name property for all fields of the form which you want to submit. The corresponding code can be about the following $("form#myFormId").submit(function() { var mydata = $("form#myFormId").serialize(); console.log(mydata); // it's only for test $.ajax(

Automatically pressing a “submit” button using python

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The bus company I use runs an awful website ( Hebrew , English ) which making a simple "From A to B timetable today" query a nightmare. I suspect they are trying to encourage the usage of the costly SMS query system. I'm trying to harvest the entire timetable from the site, by submitting the query for every possible point to every possible point, which would sum to about 10k queries. The query result appears in a popup window. I'm quite new to web programming, but familiar with the basic aspects of python. What's the most elegant way to parse the page, select a value fro a drop-down menu, and

Pass an entire model on form submission

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问题 I understand that I can use @Html.HiddenFor(m => m.parameter) and when the form is submitted, that parameter will be passed to the controller. My model has many properties. Is there a shorter way of passing the entire model at once to the controller or must I do it one by one each time? 回答1: The model will be passed to the controller in its entirety, but the values of properties that are not bound by input or hidden fields will be lost. You have to either bind the properties in the form on