form-submit

问题 This is what I am trying to do here. I have a html form to collect data from users Displaying the output on a textarea after submitting the form Two buttons to process the textarea content :- one for downloading the content as text file second one for sending the textarea content as email using php Here, the output textarea is wrapped with a div output-main and i dont want to display the this div before the form submit. Now My HTML code : <div class="emcsaninfo-symcli-main"> <form id="main"

问题 I have a similar problem to this post when trying to convert my apps script web app to use IFRAME Sandbox. I have converted to 'input = "button"' as suggested. My web app is a simple form for students to use to sign in and out of a school library. The idea for the app is for it to be as easy as possible for students to use. Students should enter their id number and be able to either click the submit button or hit the enter key . Their ID is then validated before being stored in a spreadsheet

问题 I am looking for a way to get user data in the formEvents::SUBMIT event. I can get it in formEvents::PRE_SUBMIT using $builder->addEventListener(FormEvents::PRE_SUBMIT, function() { //... $userInput = $event->getData()); //... }); I can get it in formEvents::POST_SUBMIT using $builder->addEventListener(FormEvents::POST_SUBMIT, function() { //... $userInput = $event->getForm()->getViewData() //... }); But in formEvents::SUBMIT I cannot find where, though I read it can be accessed: Symfony2:

问题 I have a problem with a form function in jQuery. It forces me to double click in order to submit the form. <script> function pin_login(forma) { jQuery("#form_" + forma).submit(function (e) { var value_pin = jQuery(".pin_" + forma).val(); }); } </script> Every time I double click it works, but it doesn't work when I single click, it doesn't submit the form. To clarify, I want it to submit one a single click, not a double. 回答1: Because you call e.preventDefault() your form should not return

问题 The following is what I'd like to do in my JQuery script. In the submit function (4th) below, I want to decide if the form has file input and submit with either ajax or just a regular form submit without ajax. In other words, if the form has upload, do a regular submit. I wrote the question in the submit function below. That is the only thing I need to make it work. Thank you! function FindFileInput(){ // check for file input var FileInput = $('input:file'); if(FileInput.length > 0){ return

问题 I purchased a template from Template Monster and I can't figure out how to make the form work. Here's the form code: <form id="form"> <div class="success_wrapper"> <div class="success-message">Το μήνυμά σας εστάλη.</div> </div> <label class="name"> <input type="text" placeholder="Όνομα*:" data-constraints="@Required @JustLetters" /> <span class="empty-message">*Το πεδίο είναι υποχρεωτικό.</span> <span class="error-message">*Το όνομα δεν είναι έγκυρο.</span> </label> <label class="email">

问题 I have a form with 2 fields, one of which is required. I used HTML5 required attribute to check if the field is filled up during submission. <form id ='reg' name='reg' action='here.php' method='post'> <input type='text' id='name' name='name' placeholder='Name' value='' required="true" /> <input type='text' id='contactno' name='contactno' placeholder='Contact No' value='' /> <input type='submit' value='Register' name='register' id='register' /> </form> Before the form actually submits, I want

问题 I have a form with a hidden submit button. When I try to submit the form using the enter key it fails (alert doesn't display). I use the following JS: $(function() { $('div.quick-login form').submit(function() { alert('test'); return false; }); }); http://jsfiddle.net/MsFY6/ Any ideas as to why my code doesn't work? UPDATE Browser I tested it with is Chrome. 回答1: What I always do is put in a .keypress() handler which checks the keycode. $("#inputbox").keypress(function(e) { if(e.keyCode == 13

问题 I have form @using (Html.BeginForm("Register", "Account", FormMethod.Post, new {id = "registrationForm"})) {...} where i put some data(email, password, etc.) Also i have method for this form : [HttpPost] [AllowAnonymous] [ValidateAntiForgeryToken] public ActionResult Register(RegisterViewModel model) {... return RedirectToAction("Index");} In that method i manage model (try to create new user) and if all is success. redirect to action "Index". Issue : i need to show bootstrap modal with some

问题 I have this code in test.php . When I access the script just by typing it, I want to see just the form but when I click the form submit button, the next time the page loads, I want to see the form and some comment that says that the form has been submitted. For some reason, even when I click submit, I don't get the message that it's posting. Anyone can explain why? and how can I get it to work. <body> <form action="" method="post"> <input type="text" id="inp" /> <input type="submit" value=