flatten

Just as the title says. This code only works Using: x = Flatten()(x) Between the convolutional layer and the dense layer. import numpy as np import keras from keras.models import Sequential, Model from keras.layers import Dense, Dropout, Flatten, Input from keras.layers import Conv2D, MaxPooling2D from keras.optimizers import SGD # Generate dummy data x_train = np.random.random((100, 100, 100, 3)) y_train = keras.utils.to_categorical(np.random.randint(10, size=(100, 1)), num_classes=10) #Build Model input_layer = Input(shape=(100, 100, 3)) x = Conv2D(32, (3, 3), activation='relu')(input_layer)

Say I have a val s: Option[Option[String]] . It can thus have the following values: Some(Some("foo")) Some(None) None I want to reduce it so that the first becomes Some("foo") while the two others become None . Obviously there are many ways to accomplish this, but I'm looking for a simple, perhaps built-in, less-than-one-liner. It's a shame that flatten doesn't exist. It should. Flatten does exist now. As before, s getOrElse None (in addition to the other answers) will also do the same thing. You could use scalaz join to do this, as this is one of the monadic operations: doubleOpt.join Here it

This is #7 of of 99 Lisp problems : transform a list, possibly holding lists as elements into a `flat' list by replacing each list with its elements (recursively). I have tried several solutions, e.g from # 2680864 or from here . They all work, but I run into a problem if I am flattening a list containing a quoted element. E.g.: > '(a 'b c) (A 'B C) > '(a (quote b) c) (A 'B C) > (flatten '(a 'b c)) (A QUOTE B C) In the latter case I would like to get: (A 'B C) It seems that the internal representation of ' gets in the way for this task! SBCL, CLISP, ECL, ... they all behave the same way.

Can anyone help with the general format for flattening a 3D array using MPI? I think I can get the array 1 dimensional just by using (i+xlength*j+xlength*ylength*k), but then I have trouble using equations that reference particular cells of the array. I tried chunking the code into chunks based on how many processors I had, but then when I needed a value that another processor had, I had a hard time. Is there a way to make this easier (and more efficient) using ghost cells or pointer juggling? You have two options at least. The simpler one is to declare a preprocessor macro that hides the

I was reading the book On Lisp by Paul Graham. In Chapter 4, Utility Functions, he gives examples of small functions that operate on lists, which would be helpful while writing a larger program. One of them is flatten . Given a nested list at any arbitrary level as argument, flatten will remove all the nested elements and put them on the top level. Below is my attempt at implementing flatten: (defun flatten (lst) (labels ((rflatten (lst1 acc) (dolist (el lst1) (if (listp el) (rflatten el acc) (push el acc))) acc)) (reverse (rflatten lst nil)))) But the above function does not flatten lists

is there a way to flatten tuples of arbitrary size in F# without explicitly mapping them? (fun ((((a0,a1),a2),b),c) -> (a0,a1,a2,b,c)) As a note I'm getting these kind of tuples from FParsec but the capability would be convenient if it was available generally. thanks, Sean You can't do it easily, but with a bit of reflection it is possible: let isTuple tuple = Microsoft.FSharp.Reflection.FSharpType.IsTuple(tuple.GetType()) let tupleValues (tuple : obj) = Microsoft.FSharp.Reflection.FSharpValue.GetTupleFields tuple |> Array.toList let rec flatten tupleFields = tupleFields |> List.collect(fun