flask-sqlalchemy

class Parent(db.Model): id = db.Column(db.Integer, primary_key = True) name = db.Column(db.String(120)) def __repr_(self): return '<Parent %r>' % (self.name) admin.add_view(ModelView(Parent, db.session)) class Child(db.Model): id = db.Column(db.Integer, primary_key = True) name = db.Column(db.String(120)) parent = db.Column(db.Integer, db.ForeignKey(Parent)) admin.add_view(ModelView(Child, db.session)) Hello - The code above is an example of flask-admin page that I am trying to create. The goal is to have on Child's create page a text box for name and a drop down to select a parent. With the

After having played for a long time with Django, I'm trying a bit of Flask with SQLAlchemy, and I must say I quite like it. However there is something that I don't get: I have a small Flask / SQLAlchemy app that uses PostgreSQL. In my __init__.py file I have: from flask import Flask from flask.ext.sqlalchemy import SQLAlchemy app = Flask(__name__) app.config.from_object('settings') db = SQLAlchemy(app) I wanted to know: Is there automatic connection pooling ? Or does every call to Model.query... create a new connection to the database? If not, how can I configure it? If yes, what are the

I'm trying to get a server for an app working, but I'm getting an error upon login: [!] Object '<User at 0x7f12bc185a90>' is already attached to session '2' (this is '3') It seems the session I'm adding is already on the database. This is the snippet of code that is causing the problem: @app.route('/login', methods=['POST']) def login(): u = User.query.filter(User.username == request.form["username"]).first() if not u or u.password != request.form["password"]: return error("E1") s = Session.get_by_user(u) if s is not None: db_session.delete(s) db_session.commit() print db_session.execute(

I should first mention that I'm using SqlAlchemy through Flask-SqlAlchemy. I don't believe this affects the issue but if it does, please let me know. Here is the relevant part of the error message I'm getting when running the create_all function in SqlAlchemy InterfaceError: (InterfaceError) Error binding parameter 4 - probably unsupported type. u'INSERT INTO podcasts (feed_url, title, url, last_updated, feed_data) VALUES (?, ?, ?, ?, ?)' (u'http://example.com/feed', u'Podcast Show Title', u'http://example.com', '2012-04-17 20:28:49.117000' Here is my model: class Podcast(db.Model): import

class User(db.Model): __tablename__ = 'user' id = db.Column(db.Integer, primary_key=True) email = db.Column(db.String(64), unique=True) # 是不是应该加密下，不能明文存储？应该设置多长的空间？ 14.7.18 4：22 by lee password = db.Column(db.String(100)) nickname = db.Column(db.String(64)) school = db.Column(db.String(20)) sex = db.Column(db.String(5)) status = db.Column(db.String(10)) grade = db.Column(db.String(18)) I have a database remains. Then I add model to models.py: class PubSquare(db.Model): id = db.Column(db.Integer, primary_key=True) author_id = db.Column(db.Integer, db.ForeignKey('user.id')) author = db

I'm working with Flask-SQLAlchemy to create a many-to-many relationship using Association Objects and association_proxy , but I'm running into an issue: When I use association_proxy , I can set it up such that when I append a new instance to one side of the relationship, the Association Object will be created, but if I attempt to add an instance from the other side of the relationship, the Association Object constructor won't be passed the correct instance. Here's a simplified example where Club has many People , and People have many Club , and the Association Object is a Membership : class