find

问题 While trying to experiment with mongo performance I found strange behaviour of my mongo db. First of all i filled it with the following query: for (i=0; i < 10000000; i++){db.location.insert( {_id: Math.floor((Math.random()*10000000000)+1), position: [Math.round(Math.random()*10000)/10000, Math.round(Math.random()*10000)/10000]} )} next: db.location.ensureIndex( {position: "2d"} ) Then i execute query: db.location.find( {position: { $near: [1,1], $maxDistance: 1/111.12 } } ) Whatever i try to

问题 I would love to replace all cells that is 0 with blank. Normally I would use the Excel find & replace function (Ctrl + R): Find what: 0 Replace with: But it would replace all 0s in all cells, so that 60 will become 0. Is there a way to only replace the 0s if the cell is indeed 0? Many thanks 回答1: There is a function built into Find & Replace that will only edit a cell if the entire cell value matches your parameter. Ex. ex1 1) There is my starting data where you only want to replace the cells

问题 Here is a part of my object const category = { fr: { list: [ {id: 1, label: 'coucou'}, {id: 2, label: 'moi'}, {id: 3, label: 'ici'}, {id: 4, label: 'maintenant'}, {id: 5, label: 'demain'}, ]}} const lang = fr; const anyId = 3; I don't know why when doing the following: const result = category[lang].list.find(item => item.id === anyId) console.log(result) Throws the following: // undefined category[lang].list.find(item => item.id === anyId) is not a function, or just undefined same result for

问题 I'm having trouble with the find command in bash. I'm trying to find a file that ends with .c and has a file size bigger than 2000 bytes. I thought it would be: find $HOME -type f -size +2000c .c$ But obviously that isn't correct. What am I doing wrong? 回答1: find $HOME -type f -name "*.c" -size +2000c Have a look to the -name switch in the mane page: -name pattern Base of file name (the path with the leading directories removed) matches shell pattern pattern. The metacharacters (`*', `?', and

问题 I'm trying to find a whole document with Find() command and filter a nested array with a condition. Here a piece of the used Schema : var ListSH = new Schema({ name: { type: String, unique: true, required: true}, subject : String, recipients : [ Schema({ uid : { type : ObjectId, required : true, ref:'User', unique: true}, status : { type : Number, default : 1 } },{_id: false}) ] }; Currently I do ListModel.findOne({ _id : req.params.id_list, function(err,list){...}; And Postman give me that:

问题 Please consider the following python session: >>> from BeautifulSoup import BeautifulSoup >>> s = BeautifulSoup("<p>This <i>is</i> a <i>test</i>.</p>"); myi = s.find("i") >>> myi.replaceWith(BeautifulSoup("was")) >>> s.find("i") >>> s = BeautifulSoup("<p>This <i>is</i> a <i>test</i>.</p>"); myi = s.find("i") >>> myi.replaceWith("was") >>> s.find("i") <i>test</i> Please note the missing output of s.find("i") after line 4! What's the reason for this? Is there a workaround? EDIT: Actually, the

问题 Please consider the following python session: >>> from BeautifulSoup import BeautifulSoup >>> s = BeautifulSoup("<p>This <i>is</i> a <i>test</i>.</p>"); myi = s.find("i") >>> myi.replaceWith(BeautifulSoup("was")) >>> s.find("i") >>> s = BeautifulSoup("<p>This <i>is</i> a <i>test</i>.</p>"); myi = s.find("i") >>> myi.replaceWith("was") >>> s.find("i") <i>test</i> Please note the missing output of s.find("i") after line 4! What's the reason for this? Is there a workaround? EDIT: Actually, the

问题 I am trying to list all the .hpp files but those whose path contain a word, for example : find -name '*.hpp' would give folder1/folder2/something.hpp folder1/folder3/something.hpp folder1/folder4/something.hpp I'd like to exclude the files in the folder2 in order to have only these : folder1/folder3/something.hpp folder1/folder4/something.hpp 回答1: Just negate a -path condition: find -name '*.hpp' -not -path '*/folder2/*' To exclude several directories, either repeat the condition: find -name

问题 I want to search within a table e.g. A B C D E C A H I A H C For the Values "A" and "C" and then put the Value "Value" into a cell in the rows where both Values have been found. I am fairly new to the whole topic so i searched first on the web to find pieces of code that could help me. Dim FirstAddress As String Dim SecondAddress As String Dim MyArr As Variant Dim MyArr2 As Variant Dim Rng As Range Dim Row As Range Dim I As Long Dim B As Long With Application .ScreenUpdating = False

问题 Here is what I'm trying to do: I have a long string: s = asdf23rlkasdfidsiwanttocutthisoutsadlkljasdfhvaildufhblkajsdhf I want to cut out the substring: iwanttocutthisout I will be iterating through a loop and with each iteration the value of s will change. The only thing that will stay the same with each iteration is the begining and end of the substring to be cut out: iwant and thisout. How can I cut out the substring, given these parameters? Thanks for your help! 回答1: You can do a slice