filepath

问题 Is there a easy way to get the filePath provided I know the Filename? 回答1: You can use the Path api: Path p = Paths.get(yourFileNameUri); Path folder = p.getParent(); 回答2: Look at the methods in the java.io.File class: File file = new File("yourfileName"); String path = file.getAbsolutePath(); 回答3: I'm not sure I understand you completely, but if you wish to get the absolute file path provided that you know the relative file name, you can always do this: System.out.println("File path: " + new

问题 Related to my previous question here. I have a path to an image in the asset library , for example: assets-library://asset/asset.JPG?id=1000000001&ext=JPG Now, how could I load the image from this path to a UIImage object? Here is the code: NSString *path = [occasion imagePath]; //temp NSLog(@"the 2nd occasion imagePath is: %@", path); //end if (path != nil) { //UIImage *image = [UIImage imageNamed:path]; UIImage *image = [UIImage imageWithContentsOfFile:path]; image = [image

问题 I have a file path String of the form "e:\...\xxx.jpg" How do I create a drawable from it? 回答1: You can create a Drawable or Bitmap from a string path like this: String pathName = "/path/to/file/xxx.jpg"; Drawable d = Drawable.createFromPath(pathName); For a Bitmap: String pathName = "/path/to/file/xxx.jpg"; bitmap b = BitmapFactory.decodeFile(pathName); 来源： https://stackoverflow.com/questions/5834221/android-drawable-from-file-path

问题 I'm using Python on Windows and I want a part of my script to copy a file from a certain directory (I know its path) to the Desktop. I used this: shutil.copy(txtName, '%HOMEPATH%/desktop') While txtName is the txt File's name (with full path). I get the error: IOError: [Errno 2] No such file or directory: '%HOMEPATH%/DESKTOP' Any help? I want the script to work on any computer. 回答1: You can use os.environ["HOMEPATH"] to get the path. Right now it's literally trying to find %HOMEPATH%/Desktop

问题 Can somebody pls tell me how to get the filepath using html <input type="file"> in PHP? Here are my codes: index.php <form action="csv_to_database.php" method="get" > <input type="file" name="csv_file" /> <input type="submit" name="upload" value="Upload" /> </form> and in csv_to_database.php <?php if (isset($_GET['csv_file'])) { $row = 1; if (($handle = fopen($_GET['csv_file'], "r")) !== FALSE) { while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) { $num = count($data); echo "<p> $num

问题 I have this code that writes successfully a file: ofstream outfile (path); outfile.write(buffer,size); outfile.flush(); outfile.close(); buffer and size are ok in the rest of code. How is possible put the file in a specific path? 回答1: Specify the full path in the constructor of the stream, this can be an absolute path or a relative path. (relative to where the program is run from. The the streams destructor close the file for you, explicit closes are MORE likely to introduce bugs (writing to

问题 I am looking for an efficient way to convert back slash to forward slash in R. Sometime I copy the link of the directory from the windows and I get something like this: C:\Users\jd\Documents\folder\file.txt How can I quickly change this to C:/Users/jd/Documents/folder/file.txt ? I cannot even read the above expression as character. It throws an error "\u used without hex digits in character string starting ""C:\u". I know TAB function in R helps to find the location fast, but was just

问题 I am trying to run sysprep from a vb.net application, and even though the path and file name are confirmed accurate, it is returning that it can not find the file. I've tried using process.start, declaring as a new process, declaring the path separate from the file name. Here is the code as I would like it to be written, maybe someone could try it out and see if they come up with a solution? Private Sub btnsysp_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnsysp

问题 I want to drag a file into a window and get the file path. I've tried doing this: class CSVDropper(wx.FileDropTarget): def __init__(self, data): wx.FileDropTarget.__init__(self) self.data = data def OnDropFiles(self, x, y, filenames): self.data = filenames print self.data then in the main window: # Drag & Drop self.csv_path = None self.drop_table = CSVDropper(self.csv_path) self.SetDropTarget(self.drop_table) But this does nothing. I've tried running this tutorial code, but it doesn't do

问题 My code import os.path #gets the module beginning = input("Enter the file name/path you would like to upperify: ") inFile = open(beginning, "r") contents = inFile.read() moddedContents = contents.upper() #makes the contents of the file all caps head,tail = os.path.split(beginning) #supposed to split the path new_new_name = "UPPER" + tail #adds UPPER to the file name final_name = os.path.join(head + new_new_name) #rejoins the path and new file name outFile = open(final_name, "w") #creates new