问题
Can somebody pls tell me how to get the filepath using html <input type="file">
in PHP?
Here are my codes:
index.php
<form action="csv_to_database.php" method="get" >
<input type="file" name="csv_file" />
<input type="submit" name="upload" value="Upload" />
</form>
and in csv_to_database.php
<?php
if (isset($_GET['csv_file'])) {
$row = 1;
if (($handle = fopen($_GET['csv_file'], "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
echo "<p> $num fields in line $row: <br /></p>\n";
$row++;
for ($c=0; $c < $num; $c++) {
echo $data[$c] . "<br />\n";
}
}
fclose($handle);
}
}
?>
My problem is, it only works when the csv data is in the same directory as my php files. I think I need to get the file path but I don't know how to do it.
回答1:
You shouldn't just use the $_GET
you've got now. Your file is based in $_FILES["csv_file"]["tmp_name"]
.
Best you review this tutorial, that basically says you need to do something like this:
<?php
if ($_FILES["csv_file"]["error"] > 0)
{
echo "Error: " . $_FILES["csv_file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["csv_file"]["name"] . "<br />";
echo "Type: " . $_FILES["csv_file"]["type"] . "<br />";
echo "Size: " . ($_FILES["csv_file"]["size"] / 1024) . " Kb<br />";
echo "Stored in: " . $_FILES["csv_file"]["tmp_name"];
}
?>
And you can go from there. Use move_uploaded_file
if you want to move the file from the temp location, also explained in the tutorial :)
回答2:
I think you would gain a lot from taking a look at the following link: POST method uploads.
First of all, you should change your form method to post
, and add enctype="multipart/form-data"
.
Then you can get the temporary file path from $_FILES['csv_file']['tmp_name']
.
回答3:
In your call to fopen, use $_GET['csv_file']['tmp_name']
- this points to the file on the server immediately after upload.
来源:https://stackoverflow.com/questions/5814155/how-to-get-the-file-path-in-html-input-type-file-in-php