filepath

from Flask import Flask ImportError: No module named Flask

丶灬走出姿态 提交于 2019-12-06 07:28:03
问题 I am following the tutorial here. My file looks like this: from flask import Flask app = Flask(__name__) @app.route("/") def main(): return "Welcome!" if __name__ == "__main__": app.run() I run python app.py and get the following: Traceback (most recent call last): File "app.py", line 1, in <module> from flask import Flask ImportError: No module named Flask I do have flask installed. I was thinking it's a $PATH issue. I don't really know where to begin as far as troubleshooting goes. which

Regular expression for file path which doesn't allow parent directories

徘徊边缘 提交于 2019-12-06 06:53:18
I'm looking to write a regex for a file path that must start with some prefix. In this case it should start with '/tank/home/'. I also want to make sure that it contains no '/..' -- no jumping up to parent directories. I spent a while fiddling around without coming up with anything quite right. I settled on using two regexes, the first which must match and the second which must not match: '^/tank/home/' '/\.\.(/.*)?$' Does this do what I think it does? Is there an easier way? This is in a bash script, for what it's worth. You can expand Dav's regex to include an extra trailing slash: ^(?!.*/\.

Get Wine path of file

房东的猫 提交于 2019-12-06 05:56:20
问题 Is it possible to get the Wine path to a file on the current OS? Example: wine-get-path ~/foo.txt # Outputs: Z:\\Users\Tyilo\foo.txt wine-get-path ~/.wine/drive_c/windows/explorer.exe # Output: C:\\windows\\explorer.exe where wine-get-path would be the function I need. 回答1: The answer is winepath -w foofile 来源: https://stackoverflow.com/questions/7204313/get-wine-path-of-file

ASP.NET MVC3 Physical Location of View from controller

余生颓废 提交于 2019-12-05 14:16:40
What is the proper way to get the physical location of the View that will be served by a MVC action from inside the action? I need the last modified time of the file for sending response headers. The proper way to the get physical location of a view is to map its virtual path. The virtual path can be retrieved from the ViewPath property of BuildManagerCompiledView ( RazorView derive from that class, and your IView instances will therefore typically have that property). Here is an extension method that you can use: public static class PhysicalViewPathExtension { public static string

What is a macro for concatenating an arbitrary number of components to build a path in Rust?

纵然是瞬间 提交于 2019-12-05 12:23:57
In Python, a function called os.path.join() allows concatenating multiple strings into one path using the path separator of the operating system. In Rust, there is only a function join() that appends a string or a path to an existing path. This problem can't be solved with a normal function as a normal function needs to have a fixed number of arguments. I'm looking for a macro that takes an arbitrary number of strings and paths and returns the joined path. Once you read past the macro syntax, it's not too bad. Basically, we take require at least two arguments, and the first one needs to be

Java Properties, getting file path

早过忘川 提交于 2019-12-05 08:10:27
logpath = LoggerUtils.getProperties().getProperty("log.path"); System.out.println("logpath: " + logpath); The above code returns: logpath: C:UsersMauriceDesktopLogs In the properties file is: log.path C:\Users\Maurice\Desktop\Logs How do I retain the file separators? I want this to work on Linux as well and not just Windows. Actually, you need to put this in the property file: log.path C:\\Users\\Maurice\\Desktop\\Logs See this: http://docs.oracle.com/javase/6/docs/api/java/util/Properties.html more precisely the load method: http://docs.oracle.com/javase/6/docs/api/java/util/Properties.html

Escaping backslash in Postgresql

☆樱花仙子☆ 提交于 2019-12-05 08:07:48
I'm trying to write an sql function in Postgresql that will parse a file path. I want to return just the file name. I cannot get past getting an accurate text string in the function. Here is the function: Function: job_page("inputText" text) DECLARE $5 text; BEGIN $5 = quote_literal("inputText"); return $5; END When I run this: select job_page('\\CAD_SVR\CADJOBS\7512-CEDARHURST ELEMENTARY SCHOOL\7512-20.DWG') I get this result: "E'\\CAD_SVRCADJOBSé2-CEDARHURST ELEMENTARY SCHOOLé2-20.DWG'" Postgresql interprets the slash followed by certain characters as a special character. How do I escape?

Doing file path manipulations in XSLT

坚强是说给别人听的谎言 提交于 2019-12-05 05:00:36
I'd like my generated output file to contain file paths that point to a path relative to the stylesheet. The location of the stylesheet can change and I don't want to use a parameter for the stylesheet. My solution for this is to get the full stylesheet URI: <xsl:variable name="stylesheetURI" select="document-uri(document(''))" /> Now I only need to cut off the filename from $stylesheetURI . This has inspired me to write XSLT 2.0 clones of the PHP functions basename and dirname : <xsl:function name="de:basename"> <xsl:param name="file"></xsl:param> <xsl:sequence select="tokenize($file, '/')

file path return null always in lollipop android

岁酱吖の 提交于 2019-12-05 03:38:56
this is my code when i'm getting image from internal storage (gallery). In lollipop file path return always null. if (requestCode == PICK_IMAGE) { if(resultCode == RESULT_OK){ //image successfully picked // launching upload activity Uri selectedImage = data.getData(); String[] filePathColumn = { MediaStore.Images.Media.DATA }; Cursor cursor = getContentResolver().query(selectedImage,filePathColumn, null, null, null); cursor.moveToFirst(); columnindex = cursor.getColumnIndex(MediaStore.Images.Media.DATA); file_path = cursor.getString(columnindex); Log.d(getClass().getName(), "file_path"+file

What is the difference between \\ and \\\\ in file path

孤人 提交于 2019-12-05 02:30:50
What is the difference between single slash and double slash in file path for Windows operating system such as c:\\Personal\MyFolder\\MyFile.jpg and c:\Personal\MyFolder\MyFile.jpg What if I use the single or double slash because I have tried both for storing images in my code (in webconfig file) and both of them work fine. Is there any difference?? Windows ignores double backslashes. So while the second syntax with \ is correct and you should use that one, the first with \\ works too. The only exception is double-backslash at the very beginning of a path that indicates a UNC path. See