filepath

How a servlet can get the absolute path to a file outside of the servlet?

由 浪子不回头ぞ 提交于 2019-12-07 12:20:50
问题 We have been using System.getProperties("user.dir") to get the location of a properties file. Now that it has been deployed on Tomcat(via servlet), the System call is giving the location as tomcat and not at the location at where the properties file exist. How can we call the the properties file dynamically? Given: Tomcat is not the only way the app will be deployed We have no control on where the app may be placed. Relative paths will not work as that Vista is being used and Vista breaks

What is a macro for concatenating an arbitrary number of components to build a path in Rust?

由 蓝咒 提交于 2019-12-07 10:33:14
问题 In Python, a function called os.path.join() allows concatenating multiple strings into one path using the path separator of the operating system. In Rust, there is only a function join() that appends a string or a path to an existing path. This problem can't be solved with a normal function as a normal function needs to have a fixed number of arguments. I'm looking for a macro that takes an arbitrary number of strings and paths and returns the joined path. 回答1: Once you read past the macro

ASP.NET MVC3 Physical Location of View from controller

由 大憨熊 提交于 2019-12-07 08:45:53
问题 What is the proper way to get the physical location of the View that will be served by a MVC action from inside the action? I need the last modified time of the file for sending response headers. 回答1: The proper way to the get physical location of a view is to map its virtual path. The virtual path can be retrieved from the ViewPath property of BuildManagerCompiledView ( RazorView derive from that class, and your IView instances will therefore typically have that property). Here is an

Codeigniter File Paths

由 有些话、适合烂在心里 提交于 2019-12-07 08:25:26
问题 sorry to bother but I am having some confusion with filepaths within codeigniter, as you may or may not know CI lays out its file system as follows: -application: -controllers -views -models -system(contains CI framework) I have created a css file and have some images saved in the a resources folder like so: -application: -controllers -views -models -system(contains CI framework) -resources -img001 -style.css I was wondering whether someone could point me in the right direction to accessing

How to know the directory of jar file in java? [duplicate]

由 岁酱吖の 提交于 2019-12-07 07:58:36
This question already has an answer here : Getting filesystem path of class being executed [duplicate] (1 answer) Closed 4 years ago . I have an executable jar file and I want it to be able to read and write info to a txt file that is located at the same dir as the .jar file is. How can I do that? How can I get the executable jar file dir path. It only has to work on windows platform and it's a desktop application. You don't need to specify full path in order to create new files, java will create new files in current working directory by default. I have an executable jar file and I want it to

How to hide file path in URL?

由 自闭症网瘾萝莉.ら 提交于 2019-12-07 06:43:04
问题 What would be the best way to way to change my URL address to a custom one? Currently my website shows: http://nkonecny.com/_pages/_portfolio/port.html I want to change it to something like this: http://nkonecny.com/portfolio 回答1: You can use mod_rewrites. Here is a good linux/apache tutorial 回答2: .htaccess would be the best option. http://httpd.apache.org/docs/1.3/howto/htaccess.html 回答3: mod_rewrite will do rewrites of this sort, but your pages have to follow a fairly strict naming/pathing

Why doesn't os.normpath collapse a leading double slash?

由 妖精的绣舞 提交于 2019-12-07 04:37:48
问题 Under Unix, os.path.normpath collapses multiple slashes into single ones except when exactly two slashes appear that the start of the path . Why the exception? To illustrate, I get the following transformations: //double/slash/stays -> //double/slash/stays /double/slash//gone// -> /double/slash/gone/ double//slash//gone/ -> double/slash/gone ///triple/slash/gone -> /triple/slash/gone ////quad/slash/gone -> /quad/slash/gone This seems strange to me. I can vaguely imagine this is useful for SMB

Doing file path manipulations in XSLT

由 ↘锁芯ラ 提交于 2019-12-07 00:33:20
问题 I'd like my generated output file to contain file paths that point to a path relative to the stylesheet. The location of the stylesheet can change and I don't want to use a parameter for the stylesheet. My solution for this is to get the full stylesheet URI: <xsl:variable name="stylesheetURI" select="document-uri(document(''))" /> Now I only need to cut off the filename from $stylesheetURI . This has inspired me to write XSLT 2.0 clones of the PHP functions basename and dirname: <xsl:function

Scala get file path of file in resources folder

由 我怕爱的太早我们不能终老 提交于 2019-12-06 22:51:16
问题 I am using the Stanford CRFClassifier and in order to run, it requires a file that is the trained classifier model. I have put this file in the resources directory. From the Javadocs for the CRFClassifier http://nlp.stanford.edu/nlp/javadoc/javanlp/edu/stanford/nlp/ie/crf/CRFClassifier.html#getClassifier(java.lang.String) the path to the file must be an input to CRFClassifier.getClassifier() and it is a java.lang.String object. So my question is how do I tell .getClassifier() that the file is

file path return null always in lollipop android

由 懵懂的女人 提交于 2019-12-06 21:56:24
问题 this is my code when i'm getting image from internal storage (gallery). In lollipop file path return always null. if (requestCode == PICK_IMAGE) { if(resultCode == RESULT_OK){ //image successfully picked // launching upload activity Uri selectedImage = data.getData(); String[] filePathColumn = { MediaStore.Images.Media.DATA }; Cursor cursor = getContentResolver().query(selectedImage,filePathColumn, null, null, null); cursor.moveToFirst(); columnindex = cursor.getColumnIndex(MediaStore.Images
订阅 filepath