filepath

问题 I'm trying the following. $woohoo = "c:\temp\shabang" New-Item -ItemType File $woohoo This creates a file at desired location. However, I'd like to split the $woo and $hoo and go something like this. $woo = "c:\temp" $hoo = "shabang" New-Item -ItemType File ($woo + $hoo) This doesn't work and I need a hint on how to make it fly. This suggestion nor this on worked out when applied to my situation. Apparently - given path format is unsupported. Suggestions? Edit This is what it looks like: Edit

问题 I want to use the QString.split(' ') method to split a input command into the command QStringList commandList = command.split(' '); however command has a UNIX path at the end of it. i.e. it looks something like QString command = new QString("caommand -a -b /path/to\ specific/file"); the path command is specified by the user at runtime(the user escapes any spaces in the path). For some reason command.split(' '); does not escape the spaces. I am new to QT, how does it escape spaces? Thanks for

问题 My file structure is this: main.swf /swf/child.swf /video/testvideo.flv When I compile the child.swf by itself, it loads and plays video just fine (using netStream.play(../video/testvideo.flv). However, when I compile the main.swf, which at some point loads child.swf, I get this error when trying to play the video: Error #2044: Unhandled IOErrorEvent:. text=Error #2035: URL Not Found. How am I supposed to configure the path so that it can be seen when I compile the main swf? I've tried

问题 I have written a on-the-fly thumbnail creator by an htaccess file looking to see if the requested file exists and if not sending the user to a php page to create it. My htaccess file looks like this: # Check the formatting (this works) RewriteCond %{SCRIPT_FILENAME}%{QUERY_STRING} /([a-zA-Z0-9-]+).(jpg|gif|png)w=([0-9]+)&h=([0-9]+)(&c=(true|false)) # Only forward to thumbnail.php if file doesn't exist #RewriteCond %{REQUEST_FILENAME} !-f #this works but not for the correct filename!

问题 I am trying to get filenames(and also the filepath), from a Garmin device which acts as a usb mass storage. Connecting the device to the computer, the filepath is G:\Garmin. Connecting that to the android tablet using OTG and Explorer(i have check the app setting - the package name is : com.android.rk), the filepath is USB/Garmin. Using ES File Explorer, I have seen that the file path is mnt/usb_storage/Garmin. So in the code, as I am trying to parse the system.xml from the file path usb

问题 More Code - The String Created here is R.string.c#### - c.#### is a pre-defined string i want to run as a setText. int Q1 = question1.getmCounter(); int Q2 = question2.getmCounter(); int Q3 = question3.getmCounter(); int Q4 = question4.getmCounter(); int qTotal = Q1 + Q2 + Q3 + Q4; String Test5 = "R.string.c" + qTotal; This is how i am now getting the "string" i want to feed. textOut = (TextView) findViewById(R.id.ChmpNametxt); textOut.setText(Test5); This is where i want to feed it. 回答1: You

问题 I'm trying to work with some long file paths (Windows) in Python and have come across some problems. After reading the question here, it looks as though I need to append '\\?\' to the front of my long file paths in order to use them with os.stat(filepath). The problem I'm having is that I can't create a string in Python that ends in a backslash. The question here points out that you can't even end strings in Python with a single '\' character. Is there anything in any of the Python standard

问题 I have a view (with one or more images) that I also want to use as the body of an email message. The Model serving the view uses Url.Content() to retrieve the absolute image path. This approach works fine for web pages, but when I render the exact same view as the body of the email, then the image can not be found which is suggested by the incomplete path from the rendered html. <img src="/Media/fe882a1d-3b77-4264-ab91-cade985ecbed.JPG"/> I know that this problem can be fixed if I could

问题 I am trying to display image from the path. I can display the image if i move the image to drawable but i want to display am image from he image Path. I tried using imageBitMap with GetImageBitmapFromUrl("image path") but it only display a blank screen. The seconded way i tried is Android.Net.Uri url = Android.Net.Uri.Parse( "the image path") namespace SetPictureUrl [Activity(Label = "SetPictureUrl", MainLauncher = true, Icon = "@drawable/icon")] public class MainActivity : Activity {

问题 I cant seem to find a solution. I have two paths, like: D:/Views/me/a.b AND D:/Views/me/a or D:/Views/me/a.b AND D:/Views/me/a.b/x/y I have to ensure, that one file/directory is not a child of the other. I have tried Contains but it does not work for me in this case? 回答1: Try using startsWith api of String: String str1 = "D:/Views/me/a.b"; String str2 = "D:/Views/me/a"; if (str1.startsWith(str2 + ".") || str1.startsWith(str2 + "/")) { System.out.println("Yes it is"); } str1 = "D:/Views/me/a/c