fgetc

问题 Everywhere I see "it is practically identical", or something similar... From The GNU C Programming Tutorial : There is another function in the GNU C Library called fgetc. It is identical to getc in most respects, except that getc is usually implemented as a macro function and is highly optimised, so is preferable in most situations. (In situations where you are reading from standard input, getc is about as fast as fgetc, since humans type slowly compared to how fast computers can read their

问题 Everywhere I see "it is practically identical", or something similar... From The GNU C Programming Tutorial : There is another function in the GNU C Library called fgetc. It is identical to getc in most respects, except that getc is usually implemented as a macro function and is highly optimised, so is preferable in most situations. (In situations where you are reading from standard input, getc is about as fast as fgetc, since humans type slowly compared to how fast computers can read their

问题 I was trying to understand some basic code and got slightly confused by following code int main () { FILE *fp; int c; int n = 0; fp = fopen("file.txt","r"); if (fp == NULL) { perror("Error in opening file"); return(-1); } do { c = fgetc(fp); if ( feof(fp) ) { break ; } printf("%c", c); } while(1); fclose(fp); return(0); } Can someone explain me why c is of type integer, even though it is defined by fgetc(fp) which, from my knowledge, gets just the next character? 回答1: Given the precise way

问题 I am working in C and have a text file that is 617kb that I am trying to read with fgetc . For some reason fgetc is starting randomly within the file. I have tried moving the file pointer to get beginning with fseek with no success. I can get fgetc work to fine with smaller files. Any help is appreciated. Sample input is 25,000 lines of data similar to: Product 23 660 2366 3 237 09 2 3730 23734 23 773 241 46 Source: #define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include <string.h>

问题 I have this code while(1){ printf("hello world !\n"); fgetc(stdin); } when this runs and I enter a letter like this: hello world ! a it ignores the fgetc(stdin) in the next loop and prints hello world twice without waiting for input. hello world ! a hello world ! hello world ! a hello world ! hello world ! a hello world ! hello world ! a hello world ! hello world ! I have tried putting fflush(stdin) before or after the fgetc(stdin) but it still produces the same behaviour, what am I doing

问题 fgetc() function reads characters from a text file in Ubuntu. the last character before EoF is with code = -1. what the heck is that? in text editor file seems ok, no strange symbols at end. while (!feof(fp)) { c = fgetc(fp); printf("%c %i\n", c, c);// } 回答1: feof is meant to signal that you've tried to read past the end of file - which means that you first have to reach it. So it will only work after you try to read and the system realizes you're at the end. And what does fgetc return if you

问题 I have asked a question related to this program but now after much research and headbutting I am stuck...again. I am trying to write a program that will take the user input and store it then print out all the unique words and the number of times they each occurred for example Please enter something: Hello#@Hello# hs,,,he,,whywhyto[then the user hits enter] hello 2 hs 1 he 1 whywhyto 1 The above should be the output, of course whywhyto isn't a word but it doesn't matter in this case because I

问题 Hello i had a simple copy file program in C but i cant explain why i get different output in the destination file when i use the 2nd method. The correct output with for loop: I am the worst programmer in the world! :D And this is bla bla bla bla more bla bla bla... BUT with while loop a random char is generated in EOF: I am the worst programmer in the world! :D And this is bla bla bla bla more bla bla bla...  The code is int main() { int i; char ch; create_files(); FILE *src = fopen("best

问题 I'm writing a function that counts the number of words in a file. Words may be separated by any amount of whitespace characters. There can be integers in a file, but the program should only count words which have at least one alphabetic character. int word_count(const char *filename) { int ch; int state; int count = 0; FILE *fileHandle; if ((fileHandle = fopen(filename, "r")) == NULL){ return -1; } state = OUT; count = 0; while ((ch = fgetc(fileHandle)) != EOF){ if (isspace(ch)) state = OUT;

问题 This question already has answers here : Is it possible to confuse EOF with a normal byte value when using fgetc? (3 answers) Closed 2 years ago . I always use this approach int c; while ((c = fgetc(fp))!=EOF) { printf("%c", c); } As it seems to me more readable and robust. But to an answer of mine link, chux commented that if ( feof(fp) ) is more robust than int c; while ((c = fgetc(fp))!=EOF) As while(1) { c = fgetc(fp); if ( feof(fp) ) { break ; } printf("%c", c); } is more robust than the