extrapolation

问题 I have x array and y array. I need to predict points(points of pareto fronts) in left and right side (I don't know exactly how). That's why used in first extrapolation of points, but it gaves linear I tried to fit my data points to exponential curve, but gave me as result only straight line with coefficients A=1.0 , K=1.0 , C=232.49024883323932 . I also tried to fit my data to polynomial function with degree 3, result better, but the tail is increasing x=[263.56789586, 263.56983885, 263

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 7 years ago . Improve this question I have a time-series data for the last 20 years. The variable has been measured every year so I have 20 values. I have a tab-delimited file with first column representing year and second column the value. Here is what it looks like : 1991 438 1992 408 1993 381 1994 361 1995 338 1996 315

问题 I have a graph where the extrapolation does not match the initial interpolation. I would like the heatmap to fill the entire image. First, the interpolation code: library(akima) library(reshape2) xmin <- signif(min(CBLo2$MD1)) xmax <- signif(max(CBLo2$MD1)) ymin <- signif(min(CBLo2$MD2)) ymax <- signif(max(CBLo2$MD2)) gridint <- 100 fld <- with(CBLo2, interp(x = MD1, y = MD2, z = Abundance, xo=seq(xmin, xmax, length=gridint), yo=seq(ymin, ymax, length=gridint) )) df <- melt(fld$z, na.rm =

问题 I am doing a 2-D interpolation using interp2 . For some data values, the interp2 command returns NaN because one of the dimensions are outside of the range defined by the vector of known values. Its possible to extrapolate with the interp1 command. However, Is there a way to do this for interp2 ? Thanks Here is the code in which I am using the interp2 command: function [Cla] = AirfoilLiftCurveSlope(obj,AFdata,Rc,M) % Input: % AFdata: Airfoil coordinates. % Rc: Local Reynolds number. % M: Mach

问题 I need to extrapolate my inventory at the item level into 4-week buckets between 0 and 52 weeks. I have about 4500 unique lines as follows: Item Unit Weekly Code Description Cases Cost Mvmnt WOH Bucket 595384 PREMIUM FRYING OIL 500 $17.92 50 10 8-12 wks 546760 DARK BROWN SUGAR 650 $11.81 10 65 >1 year 598456 STEAM CORN 330 $15.42 15 22 20-24 wks 532943 CHC SEMI SWEET 240 $34.13 80 3 <4 wks The first item moves 50 cases a week, so the 500 cases in inventory represents 10 weeks on hand (WOH)

问题 class Particle{ PVector velocity, location; //PVector variables for each particle. Particle(){ //Constructor - random location and speed for each particle. velocity = new PVector(random(-0.5,0.5), random(-0.5,0.5)); location = new PVector(random(0,width),random(0,width)); } void update() { location.add(velocity); } //Motion method. void edge() { //Wraparound case for particles. if (location.x > width) {location.x = 0;} else if (location.x < 0) {location.x = width;} if (location.y > height)

问题 class Particle{ PVector velocity, location; //PVector variables for each particle. Particle(){ //Constructor - random location and speed for each particle. velocity = new PVector(random(-0.5,0.5), random(-0.5,0.5)); location = new PVector(random(0,width),random(0,width)); } void update() { location.add(velocity); } //Motion method. void edge() { //Wraparound case for particles. if (location.x > width) {location.x = 0;} else if (location.x < 0) {location.x = width;} if (location.y > height)

问题 I have a GPS on the middle of a plate as can be seen in attached picture. Clearly, the GPS gives me the Lon. and Lat of the center of the plate with no problem. My question is how can I estimate what is the Lon. and Lat at each end point (A,B,C,D) as the distance between end points and GPS is known? I believe there should be a formula for this purpose. I appreciate any idea and suggestion in advance. GPS and four points around it: ![][1] [1]: https://i.stack.imgur.com/cwWVU.jpg 回答1: Have a

问题 I'm trying to interpolate/locally extrapolate some salary data to fill out a data set. Here's the data set and a plot of the available data: experience salary 1: 1 21878.67 2: 2 23401.33 3: 3 23705.00 4: 4 24260.00 5: 5 25758.60 6: 6 26763.40 7: 7 27920.00 8: 8 28600.00 9: 9 28820.00 10: 10 32600.00 11: 12 30650.00 12: 14 32600.00 13: 15 32600.00 14: 16 37700.00 15: 17 33380.00 16: 20 36784.33 17: 23 35600.00 18: 25 33590.00 19: 30 32600.00 20: 31 33920.00 21: 35 32600.00 Given the clear

问题 I've got a 3D dataset that I want to interpolate AND extrapolate linearly. The interpolation can be done easily with scipy.interpolate.LinearNDInterpolator. The module can only fill in a constant/nan for values outside the parameter range, but I don't see why it would not offer an option to turn on extrapolation. Looking at the code, I see that the module is written in cython. With no experience in cython, it is hard to play around with the code to implement extrapolation. I can write it in