extends

Hibernate @Embeddable class which extends another @Embeddable class, Properties not found for @OneToMany mapping

橙三吉。 提交于 2019-11-30 17:29:17
We are translating old xml based configuration to Annotation based configuration Situation There is a class which is annotated as @Embeddable(ParentPk.java) , another class extends this class which is @Embeddable(ChildPk.java) , this ChildPk.java is used as composite primary key in SomeOwnerClass.java , Which have foreign relation with another class SomeChildTable.java and tends to use properties col1 and col2 which are available in parent class of ChildPk.java but when query is executed hibernate does not finds col1 and col2 rather if I copy col1 and col2 in ChildPk.java from parent class

Having 2 variables with the same name in a class that extends another class in Java

杀马特。学长 韩版系。学妹 提交于 2019-11-30 12:33:44
Following is a part of my code for a project: public class Body extends Point{ public double x, y, mass; public Body() { x = y = mass = 0; } public Body(double x, double y, double mass) { this.mass = mass; this.x = x; this.y = y; } } public class Point { public double x; public double y; public Point(double x, double y) { this.x = x; this.y = y; } } I quickly realized that doing this will create two variables inside the Body class called x and two other variables in Body called y. How is this even possible, and why on earth does Java even allow it? I assume this is the correct code of class

Extends UserManager in Symfony2 with FOSUserBundle

[亡魂溺海] 提交于 2019-11-30 09:53:50
I tried to extend the UserManager of FOS according to this link My service is correctly detected but i have an error i can't resolved : ErrorException: Catchable Fatal Error: Argument 1 passed to FOS\UserBundle\Entity\UserManager::__construct() must be an instance of Symfony\Component\Security\Core\Encoder\EncoderFactoryInterface, none given, called in MyUserManager : namespace ChoupsCommerce\UserBundle\Model; use FOS\UserBundle\Entity\UserManager; use Symfony\Component\Security\Core\Exception\UsernameNotFoundException; class MyUserManager extends UserManager { public function

How to merge objects?

僤鯓⒐⒋嵵緔 提交于 2019-11-30 06:06:03
For instance, from these two objects : var object1 = { "color": "yellow", "size": null, "age": 7, "weight": null } var object2 = { "color": "blue", "size": 51, "age": null } I want this ( object2 overrides object1 except for null properties or properties he doesn't have): { "color": "blue", "size": 51, "age": 7, "weight": null } Copy var src = { name: 'Apple', price: 5}; var dst= angular.copy(src); deep copy Extend : var mergedObject = angular.extend(dst, src1, src2, ...) shallow copy Merge : var mergedObject = angular.merge(dst, src); since angular 1.4+ deep (recursively) copy If you want to

Class extended from built-in Array in Typescript 1.6.2 does not update length while using [] operator

大城市里の小女人 提交于 2019-11-29 22:47:31
问题 it should be possible to extend build-in types in ts 1.6 as I read here: TypeScript 1.6 adds support for classes extending arbitrary expression that computes a constructor function. This means that built-in types can now be extended in class declarations. ... Some examples: // Extend built-in types class MyArray extends Array<number> { } class MyError extends Error { } ... However when extending Array, length property is not updated while using [] operator to set values. Push function works

Java why interface extends interface

人走茶凉 提交于 2019-11-29 20:48:04
I am wondering under what circumstances do we extend an interface from an interface? Because, for example interface A{ public void method1(); } interface B extends A{ public void method2(); } class C implements B{ @Override public void method1(){} @Override public void method2(){} } Isn't it equivalent to interface A{ public void method1(); } interface B{ public void method2(); } class C implements A, B{ @Override public void method1(){} @Override public void method2(){} } Are there any significant reasons behind ? Spencer Ruport The significant reasons depend entirely on what the interface is

Interface extends another interface but implements its methods

烈酒焚心 提交于 2019-11-29 20:45:58
In java when an interface extends another interface: Why does it implement its methods? How can it implement its methods when an interface can't contain a method body How can it implement the methods when it extends the other interface and not implement it? What is the purpose of an interface implementing another interface? This has major concepts in Java! EDIT: public interface FiresDragEvents { void addDragHandler(DragHandler handler); void removeDragHandler(DragHandler handler); } public interface DragController extends FiresDragEvents { void addDragHandler(DragHandler handler); void

Javascript extends class [closed]

老子叫甜甜 提交于 2019-11-29 19:25:14
What is the right/best way to extend a javascript class so Class B inherits everything from the class A (class B extends A)? Take a look at Simple JavaScript Inheritance and Inheritance Patterns in JavaScript . The simplest method is probably functional inheritance but there are pros and cons. Annabelle Douglas Crockford has some very good explanations of inheritance in JavaScript: prototypal inheritance : the 'natural' way to do things in JavaScript classical inheritance : closer to what you find in most OO languages, but kind of runs against the grain of JavaScript extend = function

Extends UserManager in Symfony2 with FOSUserBundle

吃可爱长大的小学妹 提交于 2019-11-29 15:37:30
问题 I tried to extend the UserManager of FOS according to this link My service is correctly detected but i have an error i can't resolved : ErrorException: Catchable Fatal Error: Argument 1 passed to FOS\UserBundle\Entity\UserManager::__construct() must be an instance of Symfony\Component\Security\Core\Encoder\EncoderFactoryInterface, none given, called in MyUserManager : namespace ChoupsCommerce\UserBundle\Model; use FOS\UserBundle\Entity\UserManager; use Symfony\Component\Security\Core

Struggling with understanding <? extends T> wildcard in Java

五迷三道 提交于 2019-11-29 12:12:46
I have a very basic question. The code below doesn't compile (assume Apple Extends Fruit): List<? extends Fruit> numbers = new ArrayList<>(); numbers.add(new Apple()); //compile time error When reading about why not, I understand the words but not the concept :). Let's assume first Fruit is NOT an abstract class. I understand that that since we're dealing with multiple subtypes all of which extend Fruit. Supposedly since we can't tell the exact type of fruit, we can't put anything in the collection. There's a couple things I don't understand: 1) Apparently we cannot know which fruit it is