exponent

I'd searching many websites trying to understand how does RSA works. I have a modulus "A89F25A56FA6DA258C8CA8B40427D927B4A1EB4D7EA326BBB12F97DED70AE5E4480FC9C5E8A972177110A1CC318D06D2F8F5C4844AC5FA79A4DC470BB11ED635699C17081B90F1B984F12E92C1C529276D8AF8EC7F28492097D8CD5BECEA16FE4088F6CFAB4A1B42328A1B996F9278B0B7E3311CA5EF856C2F888474B83612A82E4E00D0CD4069A6783140433D50725F" and exponent "03" and i have to decrypt information formated in hex bytes. My questions are: How do i create a public key? Once i have the public key do i have to encode in base64 or the public key is ready to decrypt?

I'm converting code between delphi and c#. Values are stored as strings in a text file from the delphi app. An example of the stored value is : '4.42615029219009E-5' Now in my c# app I need to read in that string value and then later have the capability to write out the value again. Initially I used code similar to: string stringField = "4.42615029219009E-5"; double someMoneyVar = Convert.ToDouble(stringField) later if I need to recreate the text file with the value of someMoneyVar then using a simple: string.Format("{0}", someMoneyVar) would output: 4.42615029219009E-05 // note the 0 Lastly,

Possible Duplicate: The most efficient way to implement an integer based power function pow(int, int) How can I calculate powers with better runtime? E.g. 2^13. I remember seeing somewhere that it has something to do with the following calculation: 2^13 = 2^8 * 2^4 * 2^1 But I can't see how calculating each component of the right side of the equation and then multiplying them would help me. Any ideas? Edit: I did mean with any base. How do the algorithms you've mentioned below, in particular the "Exponentation by squaring", improve the runtime / complexity? Omnifarious There is a generalized

Using this code to retrieve the public key bytes... var pubKey = AppDomain.CurrentDomain.DomainManager.EntryAssembly .GetName().GetPublicKey(); What is this common structure at the start (first 32 bytes) of the key? It's not ASN.1 and it might not be variable. I can google it and get repeats. // 00 24 00 00 04 80 00 00 94 00 00 00 06 02 00 00 00 24 00 00 52 53 41 31 Is it all reversed or just part of it (e.g. the modulus at the end)? 52 53 41 31 is a string of RSA1 . My key's modulus is 1024 bit, so I was looking for something that described the length. 0x0400 ( 00 04 B.E.) would be 1024 (bits

What is the best way to calculate sum of matrices such as A^i + A^(i+1) + A^i+2........A^n for very large n? I have thought of two possible ways: 1) Use logarithmic matrix exponentiation(LME) for A^i, then calculate the subsequent matrices by multiplying by A. Problem : Doesn't really take advantage of the LME algorithm as i am using it only for the lowest power!! 2)Use LME for finding A^n and memoize the intermediate calculations. Problem: Too much space required for large n. Is there a third way? Notice that: A + A^2 = A(I + A) A + A^2 + A^3 = A(I + A) + A^3 A + A^2 + A^3 + A^4 = (A + A^2)(I

This question already has an answer here: How to calculate modulus of large numbers? 10 answers I have two numbers A and B where A and B can be in the range 1<= A,B <=100^100000 How can we find the value of A^B modulo some M in C++ ?? Floris In the duplicate I pointed out, the solution I particularly like is https://stackoverflow.com/a/8972838/1967396 (see there for attribution and references) For your convenience I reproduce the code here (wrapped into an SCCE - but using C, not C++): #include <stdio.h> int modular(int base, unsigned int exp, unsigned int mod) { int x = 1; int i; int power =