exception

How to check in PHP if more PDO parameters provided than needed

北城以北 提交于 2020-05-29 10:20:06
问题 I have following piece of code (PHP 7.3.16) which retrieves some data from database (MySQL): // db credentials $dbhost = "localhost"; $dbuser = "user"; $dbpass = "password"; $dbname = "database"; // pdo $dsn = "mysql:host=".$dbhost.";dbname=".$dbname.";charset=utf8"; $options = [ PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION, PDO::ATTR_DEFAULT_FETCH_MODE => PDO::FETCH_ASSOC, PDO::ATTR_EMULATE_PREPARES => false ]; $pdo = new PDO($dsn, $dbuser, $dbpass, $options); // run sql query $sql = "SELECT

copy elision of return values and noexcept

江枫思渺然 提交于 2020-05-29 03:58:19
问题 I have a function template like this: template <typename T> constexpr auto myfunc() noexcept { return T{}; } Is this function template guaranteed to be noexcept because of copy elision? If an exception is thrown inside the constructor, does this happen inside or outside the function? 回答1: All that copy elision does is eliminate the actual copy or move. Everything happens "as-if" things happen without the copy-elision taking place (except for the copy itself, of course). The construction

Unlock mutex on exception

馋奶兔 提交于 2020-05-29 01:03:58
问题 mutex.lock(); try { foo(); // can throw exception } catch (...) { mutex.unlock(); throw; } mutex.unlock(); To guaranty the unlock i must call mutex.unlock() in catch block and in normal case. Is there any option to avoid duplication? Thank You 回答1: What you are looking for is a mutex wrapper like std::lock_guard: #include <mutex> std::mutex _mutex; void call_foo() { std::lock_guard<std::mutex> lock(_mutex); try { foo(); // can throw exception } catch (...) { // the mutex is unlocked here...

Prevent 'try' to catch an exception and pass to the next line in python

两盒软妹~` 提交于 2020-05-28 09:28:08
问题 I have a python function that runs other functions. def main(): func1(a,b) func2(*args,*kwargs) func3() Now I want to apply exceptions on main function. If there was an exception in any of the functions inside main, the function should not stop but continue executing next line. In other words, I want the below functionality def main(): try: func1() except: pass try: func2() except: pass try: func3() except: pass So is there any way to loop through each statement inside main function and apply

Prevent 'try' to catch an exception and pass to the next line in python

拟墨画扇 提交于 2020-05-28 09:27:29
问题 I have a python function that runs other functions. def main(): func1(a,b) func2(*args,*kwargs) func3() Now I want to apply exceptions on main function. If there was an exception in any of the functions inside main, the function should not stop but continue executing next line. In other words, I want the below functionality def main(): try: func1() except: pass try: func2() except: pass try: func3() except: pass So is there any way to loop through each statement inside main function and apply

Exception handling is ignored with try-except around a function definition

前提是你 提交于 2020-05-28 06:11:30
问题 My message "Divide by 0 error" is not going through, instead I'm getting a normal ZeroDivisionError . #!/usr/bin/python t = raw_input("do you want to play a game?[y/n]" ) #r = raw_input("Please enter a number") #e = raw_input("Please enter a number again") try: def di (a, b): return a/b except ZeroDivisionError: print "Divide by 0 Error" while t == "y": u = raw_input("Please enter / sign ") if u == "/": r = int(raw_input("Please enter a number")) try: e = int(raw_input("Please enter a number

Ignore the Tasks throwing Exceptions at Task.WhenAll and get only the completed results

ぐ巨炮叔叔 提交于 2020-05-25 10:25:13
问题 I am working on a Task parallel problem that I have many Tasks that may or may not throw Exception. I want to process all the tasks that finishes properly and log the rest. The Task.WhenAll propage the Task exception without allowing me to gather the rest results. static readonly Task<string> NormalTask1 = Task.FromResult("Task result 1"); static readonly Task<string> NormalTask2 = Task.FromResult("Task result 2"); static readonly Task<string> ExceptionTk = Task.FromException<string>(new

Ignore the Tasks throwing Exceptions at Task.WhenAll and get only the completed results

青春壹個敷衍的年華 提交于 2020-05-25 10:25:02
问题 I am working on a Task parallel problem that I have many Tasks that may or may not throw Exception. I want to process all the tasks that finishes properly and log the rest. The Task.WhenAll propage the Task exception without allowing me to gather the rest results. static readonly Task<string> NormalTask1 = Task.FromResult("Task result 1"); static readonly Task<string> NormalTask2 = Task.FromResult("Task result 2"); static readonly Task<string> ExceptionTk = Task.FromException<string>(new

How can I loop through Exception getCause() to find root cause with detail message [duplicate]

爱⌒轻易说出口 提交于 2020-05-24 08:24:08
问题 This question already has answers here : Java - find the first cause of an exception (9 answers) Closed 10 months ago . I am trying to call saveOrUpdate() in hibernate to save data. Since columns have unique index, so its throws ConstraintViolationException when I look through via Eclipse debugger. Since root cause could be different for different exception while inserting data to table. I wanted to know, how can I loop / traverse through getCause() to check what is the root cause of

Throw exception on missing function overload with std::variant instead of compile time error

笑着哭i 提交于 2020-05-17 07:20:06
问题 This is a follow up to this question Consider the following code #include <variant> int add_(int a, int b){ return a+b; } float add_(float a, float b){ return a+b; } float add_(int a, float b){ return a+b; } float add_(float a, int b){ return a+b; } using Number = std::variant<int, float>; Number add(Number const& lhs, Number const& rhs ){ return std::visit( []( auto& lhs_, auto& rhs_ )->Number { return {add_( lhs_, rhs_ )}; }, lhs, rhs ); } int main(){ Number a = 1.f; Number b = 2.f; Number