evaluation

AssertionError when installing pyrouge

試著忘記壹切 提交于 2019-12-13 15:14:07
问题 pyrouge : 0.1.3 rouge : downloaded from [here][1] since http://www.berouge.com/Pages/default.aspx is not accessable. I have installed XML::DOM and set the rouge path. And I've also tried suggestion from Errors installing Pyrouge. However there are still several assertion error here. Any suggestion to work it out? ====================================================================== FAIL: test_config_file (pyrouge.tests.Rouge155_test.PyrougeTest) ----------------------------------------------

Does anyone know how to generate AUC/Roc Area based on the predition?

有些话、适合烂在心里 提交于 2019-12-13 12:17:44
问题 I know the AUC/ROC area (http://weka.wikispaces.com/Area+under+the+curve) in weka is based on the e Mann Whitney statistic (http://en.wikipedia.org/wiki/Mann-Whitney_U) But my doubt is, if I've got 10 labeled instances (Y or N, binary target attribute), by applying an algorithm (i.e. J48) onto the dataset, then there are 10 predicted labels on these 10 instances. Then what exactly should I use to calculate the AUC_Y, AUC_N, and AUC_Avg? Use the prediction's ranked label Y and N or the actual

How to control rule evaluation (or rule execution) stages in Drools?

丶灬走出姿态 提交于 2019-12-13 03:55:33
问题 I know that "salience" in Drools provides control under rule execution sequence. But above is an example of the problem when "saliences" cannot help anymore that I've faced with. Here I have three rules being executed one after another: rule "Rule 1" salience 30 when then Resource resource1 = new Resource(); resource1.setName("Resource 1"); resource1.setAmount("5"); insert(resource1); System.out.println("First"); end rule "Rule 2" salience 20 //no-loop (interesting, it doesn't lead to a loop)

How to concatenate, evaluate and stringify macros?

偶尔善良 提交于 2019-12-13 01:47:52
问题 I am trying to stringify the substitution (evaluation) of a macro concatenation. For example: #include <stdio.h> #define FOO_ONE 12 #define FOO_TWO 34 #define BAR_ONE 56 #define BAR_TWO 78 #define MAKE_MAC(mac) // ... what to do here? void main(int argc, char *argv[]) { printf("FOO: " MAKE_MAC(FOO) "\n"); printf("BAR: " MAKE_MAC(BAR) "\n"); } The result I am seeking is: FOO: 1234 BAR: 5678 I tried a few forms, I think the best attempt is this: #define STRINGIFY(mac) #mac #define CONCAT(mac1,

Predictionio evaluation fails with empty.maxBy exception and training with java.lang.OutOfMemoryError

大城市里の小女人 提交于 2019-12-12 18:18:02
问题 I have downloaded the latest update on text classification template. I created a new app and imported stopwords.json and emails.json by specifying app id $ pio import --appid <appID> --input data/stopwords.json $ pio import --appid <appID> --input data/emails.json Then I changed engine.json and given my app name in it. { "id": "default", "description": "Default settings", "engineFactory": "org.template.textclassification.TextClassificationEngine", "datasource": { "params": { "appName": "

Writing String evaluation function

你离开我真会死。 提交于 2019-12-12 11:03:56
问题 I'm trying to write a String evaluation function i.e. evaluate("4 + 1") ; // returns 5 evaluate("4 + 1 + 3") ; // returns 8 evaluate("4 + 1 * 3") ; // returns 7 (not 15) The operators are + - / and * My initial though was to use regular expressions to collect operators and digits as these can be matched. And than after finding that info, somehow figure out a way to prioritize /* ove -+ operators. Here is how I started : static String regex = "([\\+\\*-/])+"; static String digitRegex = "(\\d)+

C++ tokenise string and store in vector

吃可爱长大的小学妹 提交于 2019-12-12 04:58:10
问题 vector<string> ExprTree::tokenise(string expression){ vector<string> store; string s; std::stringstream in(expression); while(in >> s) { store.push_back(s); } return store; } When i input the arithmetic expression (5 + 5) + 5 i get the output: (5 + 5) + 5 However i want: ( 5 + 5 ) + 5 Also, the code only separates the strings between whitespaces, is it possible to tokenise a string that is written without whitespaces? i.e (5+5)+5 回答1: 2 Updates you can do to solve your problem: string s;

Erlang trying to evaluate a string

坚强是说给别人听的谎言 提交于 2019-12-12 02:48:37
问题 I'm trying to dynamically evalutate Erlang terms Start up Erlang basho-catah% erl Erlang R16B03 (erts-5.10.4) [source] [64-bit] [smp:4:4] [async-threads:10] [hipe] [kernel-poll:false] Eshell V5.10.4 (abort with ^G) Create a term 1> {a,[b,c,d]}. {a,[b,c,d]} Try to scan in the same term 2> {ok, Tokens, _ } = erl_scan:string("{a,[b,c,d]}"). {ok,[{'{',1}, {atom,1,a}, {',',1}, {'[',1}, {atom,1,b}, {',',1}, {atom,1,c}, {',',1}, {atom,1,d}, {']',1}, {'}',1}], 1} 3> Tokens. [{'{',1}, {atom,1,a}, {','

How to manually update the statistics data of tables in PostgreSQL

我们两清 提交于 2019-12-11 13:53:03
问题 The ANALYZE statement can be used in PostgreSQL to collect the statistics data of tables. However, I do not want to actually insert these data into tables, I just need to evaluate the cost of some queries, is there anyway to manually specify the statistics data of tables in PostgreSQL without actually putting data into it? 回答1: I think you are muddling ANALYZE with EXPLAIN ANALYZE . There are different things. If you want query costs and timing without applying the changes, the only real

Convert a list formatted as string in a list

大憨熊 提交于 2019-12-11 09:50:56
问题 i have this list in R: x[[82]]["PositionNormalized"] $PositionNormalized $PositionNormalized$X [1] -0.678095 $PositionNormalized$Y [1] -0.970294 I've converted it in a string like so: list=as.character(x[[82]]["PositionNormalized"]) list [1] "list(X = -0.678095, Y = -0.970294)" How can I reconvert the last string back into a list object? 回答1: As proposed by @missuse, you could use eval and parse . The latter will create an expression, which is then evaluated to return a list object. Here is a