eval

问题 First of all: I know that there are many questions related to escaping, but I did not found a generally working answer so far. Say I have this simple toy function for demonstration: function f(somePOJO) { var s = eval("'" + JSON.stringify(somePOJO) + "';"); // for demonstration only return JSON.parse(s); } const clone = f({a: 1, b: "c"}); Given an object literal such as {a: 1, b: "c"} (a POJO), f should return a "clone" of it. (Note that I do not really use this approach for cloning or

来源： https://stackoverflow.com/questions/56187117/await-is-only-valid-in-async-function-eval-in-async

来源： https://stackoverflow.com/questions/56372165/use-of-eval-keyword-in-kotlin

来源： https://stackoverflow.com/questions/56372165/use-of-eval-keyword-in-kotlin

来源： https://stackoverflow.com/questions/46794115/passing-a-tuple-in-args

问题 Is there a eval() like method on golang? Evaluate/Execute JavaScript code/expressions: var x = 10; var y = 20; var a = eval("x * y") + "<br>"; var b = eval("2 + 2") + "<br>"; var c = eval("x + 17") + "<br>"; var res = a + b + c; The result of res will be: 200 4 27 Is this possible in golang? and why? 回答1: Is this possible in golang? and why? No, because golang is not that kind of language. It is intended to be compiled, not interpreted, so that the runtime does not contain any “string to code

问题 Is there a eval() like method on golang? Evaluate/Execute JavaScript code/expressions: var x = 10; var y = 20; var a = eval("x * y") + "<br>"; var b = eval("2 + 2") + "<br>"; var c = eval("x + 17") + "<br>"; var res = a + b + c; The result of res will be: 200 4 27 Is this possible in golang? and why? 回答1: Is this possible in golang? and why? No, because golang is not that kind of language. It is intended to be compiled, not interpreted, so that the runtime does not contain any “string to code

问题 Is there a eval() like method on golang? Evaluate/Execute JavaScript code/expressions: var x = 10; var y = 20; var a = eval("x * y") + "<br>"; var b = eval("2 + 2") + "<br>"; var c = eval("x + 17") + "<br>"; var res = a + b + c; The result of res will be: 200 4 27 Is this possible in golang? and why? 回答1: Is this possible in golang? and why? No, because golang is not that kind of language. It is intended to be compiled, not interpreted, so that the runtime does not contain any “string to code

问题 I have heard that ast.literal_eval is much safer than eval(), but while changing my code, I am getting 'malformed string/node' errors. For example: bar = False incorrect = {"foo":bar} correct = {"foo":"bar"} ast.literal_eval(incorrect) returns the error but ast.literal_eval(correct) returns the expected {"foo":"bar"} Why doesn't the first evaluation return {"foo":False} 回答1: Because it is not meant to do that. From the documentation: Safely evaluate an expression node or a Unicode or Latin-1

问题 So I tested out a regular expression that utilizes the experimental embedded code features. My tests worked, so I expounded upon it to do a more sophisticated script, but ran into errors. I traced the errors to a simple use of a variable in the regular expression not in the embedded code. I tried doing the regex in the suggested eval, but discovered that that wouldn't work because I could not access special variables after the eval'ed regular expression. I eventually re-wrote the code to not