duplicates

drop_duplicates not working in pandas?

只谈情不闲聊 提交于 2019-11-26 23:38:56
问题 The purpose of my code is to import 2 Excel files, compare them, and print out the differences to a new Excel file. However, after concatenating all the data, and using the drop_duplicates function, the code is accepted by the console. But, when printed to the new excel file, duplicates still remain within the day. Am I missing something? Is something nullifying the drop_duplicates function? My code is as follows: import datetime import xlrd import pandas as pd #identify excel file paths

Remove duplicate and original from list - python

二次信任 提交于 2019-11-26 23:38:52
问题 given a list of string (i am not aware of list), i want to remove the duplicate and original word. for example: lst = ['a', 'b', 'c', 'c', 'c', 'd', 'e', 'e'] the output should should remove the duplicates so something like this ['a', 'b', 'd'] I do not need to preserve the order. 回答1: Use a collections.Counter() object, then keep only those values with a count of 1: from collections import counter [k for k, v in Counter(lst).items() if v == 1] This is a O(N) algorithm; you just need to loop

row not consolidating duplicates in R when using multiple months in Date Filter

旧街凉风 提交于 2019-11-26 23:37:11
问题 I am using the following code to summarize my data by a column library(data.table, warn.conflicts = FALSE) library(lubridate, warn.conflicts = FALSE) ################ ## PARAMETERS ## ################ # Set path of major source folder for raw transaction data in_directory <- "C:/Users/NAME/Documents/Raw Data/" # List names of sub-folders (currently grouped by first two characters of CUST_ID) in_subfolders <- list("AA-CA", "CB-HZ") # Set location for output out_directory <- "C:/Users/NAME

What is the best way to remove duplicates in an Array in Java?

瘦欲@ 提交于 2019-11-26 22:52:55
I have an Array of Objects that need the duplicates removed/filtered. I was going to just override equals & hachCode on the Object elements, and then stick them in a Set... but I figured I should at least poll stackoverflow to see if there was another way, perhaps some clever method of some other API? brabster I would agree with your approach to override hashCode() and equals() and use something that implements Set . Doing so also makes it absolutely clear to any other developers that the non-duplicate characteristic is required. Another reason - you get to choose an implementation that meets

Cloning a record in rails, is it possible to clone associations and deep copy?

假如想象 提交于 2019-11-26 22:52:45
问题 I'm .clone -ing a record in rails... new_blerg = Blerg.find(1).clone This record has loads and loads of associations, and those associations even have associations. Is there a way to deep-copy a record and clone it so it is cloned with all of those associations too? 回答1: You may get some good use out of the Amoeba gem for ActiveRecord 3.2. It supports easy and automatic recursive duplication of has_one , has_many and has_and_belongs_to_many associations, field preprocessing and a highly

How to check if exists any duplicate in Java 8 Streams?

我怕爱的太早我们不能终老 提交于 2019-11-26 22:52:02
问题 In java 8, what's the best way to check if a List contains any duplicate? My idea was something like: list.size() != list.stream().distinct().count() Is it the best way? 回答1: Your code would need to iterate over all elements. If you want to make sure that there are no duplicates simple method like public static <T> boolean areAllUnique(List<T> list){ Set<T> set = new HashSet<>(); for (T t: list){ if (!set.add(t)) return false; } return true; } would be more efficient since it can give you

Oracle Equivalent to MySQL INSERT IGNORE?

大憨熊 提交于 2019-11-26 22:50:27
I need to update a query so that it checks that a duplicate entry does not exist before insertion. In MySQL I can just use INSERT IGNORE so that if a duplicate record is found it just skips the insert, but I can't seem to find an equivalent option for Oracle. Any suggestions? Check out the MERGE statement. This should do what you want - it's the WHEN NOT MATCHED clause that will do this. Do to Oracle's lack of support for a true VALUES() clause the syntax for a single record with fixed values is pretty clumsy though: MERGE INTO your_table yt USING ( SELECT 42 as the_pk_value, 'some_value' as

Java HashSet contains duplicates if contained element is modified

荒凉一梦 提交于 2019-11-26 22:47:06
Let's say you have a class and you create a HashSet which can store this instances of this class. If you try to add instances which are equal, only one instance is kept in the collection, and that is fine. However if you have two different instances in the HashSet, and you take one and make it an exact copy of the other (by copying the fields), the HashSet will then contain two duplicate instances. Here is the code which demonstrates this: public static void main(String[] args) { HashSet<GraphEdge> set = new HashSet<>(); GraphEdge edge1 = new GraphEdge(1, "a"); GraphEdge edge2 = new GraphEdge

How to select records without duplicate on just one field in SQL?

送分小仙女□ 提交于 2019-11-26 22:40:44
问题 I have a table with 3 columns like this: +------------+---------------+-------+ | Country_id | country_title | State | +------------+---------------+-------+ There are many records in this table. Some of them have state and some other don't. Now, imagine these records: 1 | Canada | Alberta 2 | Canada | British Columbia 3 | Canada | Manitoba 4 | China | I need to have country names without any duplicate. Actually I need their id and title , What is the best SQL command to make this? I used

TransformException duplicate entry for common.annotations.Beta

邮差的信 提交于 2019-11-26 22:39:07
This started when I added google-api-services-calendar . I am getting this error when trying to build: Error:Execution failed for task ':app:transformClassesWithJarMergingForDebug'. com.android.build.transform.api.TransformException: java.util.zip.ZipException: duplicate entry: com/google/common/annotations/Beta.class This is part of the output when running ./gradlew app:dependencies : compile - Classpath for compiling the main sources. +--- com.google.android.gms:play-services-measurement:8.1.0 | +--- com.google.android.gms:play-services-base:8.1.0 | | \--- com.google.android.gms:play