django-urls

A solution: Found the following django snippet that seems to work fine ( http://djangosnippets.org/snippets/2445/ ) from django.utils.functional import lazy from django.core.urlresolvers import reverse #Workaround for using reverse with success_url in class based generic views #because direct usage of it throws an exception. reverse_lazy = lambda name=None, *args : lazy(reverse, str)(name, args=args) Apparently, there is now a reverse_lazy function in django trunk. Update: This error has something to do with me making a call to reverse inside a generic view: class AddObjView(CreateView): form

Whenever my django site calls "HttpResponseRedirect" in a view object to redirect to another url it strips off the sub-domain and goes back to the main site. I'm working off of the SVN branch of Django. Here is the example: #Request comes in as https://sub1.mydomain.com def view(request): return HttpResponseRedirect("/test_url") #The browser will actually get redirected to https://mydomain.com/test_url Is there a reason this is done? Should I have to redirect to the full path including the sub-domain? SmileyChris Django has some methods it always applies to a response. One of these is django

Whenever I learn a new language/framework, I always make a content management system... I'm learning Python & Django and I'm stuck with making a URL pattern that will pick the right page. For example, for a single-level URL pattern, I have: url(r'^(?P<segment>[-\w]+)/$', views.page_by_slug, name='pg_slug'), Which works great for urls like: http://localhost:8000/page/ Now, I'm not sure if I can get Django's URL system to bring back a list of slugs ala: http://localhost:8000/parent/child/grandchild/ would return parent, child, grandchild. So is this something that Django does already? Or do I

Is it possible eliminate pk from url related to UpdateView ? For example, if I have url(r'^myobj/update/(?P<pk>\d+)/$', views.UpdateMyObj.as_view(), name="update") is there any way to write it like url(r'^myobj/update/$', views.UpdateMyObj.as_view(), name="update") and then send pk as a parameter in POST or GET request? Yes it is possible you just need to override the get_object method: from django.views.generic.edit import UpdateView class UpdateMyObj(UpdateView): # ..... def get_object(self): return MyModel.objects.get(pk=self.request.GET.get('pk')) # or request.POST 来源： https:/

I have looked a lot on google for answers of how to use the 'url' tag in templates only to find many responses saying 'You just insert it into your template and point it at the view you want the url for'. Well no joy for me :( I have tried every permutation possible and have resorted to posting here as a last resort. So here it is. My urls.py looks like this: from django.conf.urls.defaults import * from login.views import * from mainapp.views import * import settings # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns

polls/urls/py from django.conf.urls import url from . import views urlpatterns = [ url('', views.index, name='index'), url('<int:question_id>/', views.detail, name='detail'), # ex: /polls/5/results/ url('<int:question_id>/results/', views.results, name='results'), # ex: /polls/5/vote/ url('<int:question_id>/vote/', views.vote, name='vote'), ] views.py from __future__ import unicode_literals from django.http import HttpResponse from .models import Question from django.template import loader # from django.shortcuts import render def index(request): latest_question_list = Question.objects.order

So I'm building a Django progressive web app with offline support using service workers. According to google's documentation , the sw.js file should be at the root of the app's url: You need to do this because the scope of a service worker (the set of urls that the ServiceWorker will load for) is defined by the directory where it resides. At the moment, I'm serving all static assets from http://example.com/static/ folder. But I need to serve this specific file at a url like: http://example.com/sw.js . Any idea how I can achieve this? I could make a specific nginx rule to do this redirection,