django-urls

I am wondering if it is possible to have the standard url patterns spread across multiple files (in this case the project-wide urls.py and several apps-specific urls.py ). Imagine that the project urls.py look like this (got this working): from django.conf.urls import patterns, include, url admin.autodiscover() urlpatterns = patterns('', url(r'^user/signup/', 'registration.views.signup'), url(r'^user/confirm/(?P<code>\w{20})/', 'registration.views.confirm'), url(r'^user/profile/(\d+)/', 'profile.views.show'), url(r'^user/profile/edit/', 'profile.views.edit'), ) As you can see, I have two

I am trying to overwrite ROOT_URLCONF with another url when the request contains "api" subdomain and this is what I have so far. from django.utils.cache import patch_vary_headers class SubdomainMiddleware: def process_request(self, request): path = request.get_full_path() root_url = path.split('/')[1] domain_parts = request.get_host().split('.') if (len(domain_parts) > 2): subdomain = domain_parts[0] if (subdomain.lower() == 'www'): subdomain = None else: subdomain = None request.subdomain = subdomain request.domain = domain if request.subdomain == "api": request.urlconf = "rest_api_example

I have a Django model with a large number of fields and 20000+ table rows. To facilitate human readable URLs and the ability to break down the large list into arbitrary sublists, I would like to have a URL that looks like this: /browse/<name1>/<value1>/<name2>/<value2>/ .... etc .... where 'name' maps to a model attribute and 'value' is the search criteria for that attribute. Each "name" will be treated like a category to return subsets of the model instances where the categories match. Now, this could be handled with GET parameters, but I prefer more readable URLs for both the user's sake and

models.py class Lab(Model): acronym = CharField(max_length=10) class Message(Model): lab = ForeignKey(Lab) urls.py urlpatterns = patterns('', url(r'^(?P<lab>\w+)/$', ListView.as_view( queryset=Message.objects.filter(lab__acronym='') )), ) I want to pass the lab keyword argument to the ListView queryset. That means if lab equals to TEST , the resulting queryset will be Message.objects.filter(lab__acronym='TEST') . How can I do that? You need to write your own view for that and then just override the get_queryset method: class CustomListView(ListView): def get_queryset(self): return Message

As in the title: how can I access the url hash/fragment (the part following the dash # ) from a Django view and so, I suppose, from a Django Request object? I've not found enough information on the documentation here available: http://docs.djangoproject.com/en/dev/ref/request-response/ P.S. Suppose that the fragment part is sent to the server (it is so in my specific case since it's not a browser to send the request). This is not sent to the server, by definition. From URI References: Fragment Identifiers on URIs : "The HTTP engine cannot make any assumptions about it. The server is not even

The above mentioned things are giving me almost the same results was wondering whats the main difference in them. Ofri Raviv response = HttpResponse("Here's the text of the Web page.") : will create a new HttpResponse object with HTTP code 200 (OK), and the content passed to the constructor. In general, you should only use this for really small responses (like an AJAX form return value, if its really simple - just a number or so). HttpResponseRedirect("http://example.com/") : will create a new HttpResponse object with HTTP code 302 (Found/Moved temporarily). This should be used only to

I'm looking for a good tutorial for URL namespaces in Django. I find official documentation a little too sparse - it lacks good examples. I found similar question here on stack, but the answers didn't help me to fully understand the subject either. David Eyk Agreed, the docs for this are rather confusing. Here's my reading of it (NB: all code is untested! ): In apps.help.urls : urlpatterns = [ url(r'^$', 'apps.help.views.index', name='index'), ] In your main urls.py : urlpatterns = [ url(r'^help/', include('apps.help.urls', namespace='help', app_name='help')), url(r'^ineedhelp/', include('apps