django-urls

问题 I am following this tutorial. At the moment I am at this point but when I start my server with python manage.py runserver 0.0.0.0:8000 and open the url in my browser, I receive following Error: name 'IndexView' is not defined This is my urls.py from django.conf.urls import include, url from django.contrib import admin from django.conf.urls import patterns from rest_framework_nested import routers from authentication.views import AccountViewSet router = routers.SimpleRouter() router.register(r

问题 I don't know if it's possible but I'd like to add few parameters at the end of the URL using middleware. Can it be done without redirect after modyfing requested URL? ie. user clicks: .../some_link and middleware rewrites it to: .../some_link?par1=1&par2=2 Other way is to modify reponse and replace every HTML link but it's not something I'd like to do. Thanks 回答1: I think this really depends on your problem and what exactly you are trying to do. You cannot change the URL without redirecting

问题 I have form details in this question Django: Adding files to a form gives multiple argument error How to download the uploaded file. When i go to edit view of the form, i can see uploaded file url, but its not downloading. What setting to be changed for development and production mode? Error upon clicking link: Page not found (404) Request Method: GET Request URL: http://127.0.0.1:8000/media/Certificate.docx Using the URLconf defined in tiktant.urls, Django tried these URL patterns, in this

问题 I have djando login url, after user loggedin, its getting called as bellow: (r'^$', RedirectView.as_view(url= '/home/')), I want to pass loggedin username in above url , such as (r'^$', RedirectView.as_view(url= '<username>')), Please suggest. 回答1: Would recommend deriving the RedirectView class in a view, like this: class HomeRedirectView(RedirectView): pattern_name = 'home' def get_redirect_url(self, *args, **kwargs): return "/user/{}/".format(self.request.user) In urls.py : (r'^$',

问题 I tried this, url ('', views.notfound, name='notfound') But seems it doesn't work properly, for example, I have another url pattern define, url(r'^login/$', views.login, name='login'), So, if I go for http://example.com/login/ , this works, but if i go for http://example.com/login/?help=1 , then it falls into notfound category. How can I handle that? 回答1: If you just want to create a page that is displayed when a URL is not found (i.e. a Http404 exception is thrown) you can create a template

问题 I'm new to Django and I'm working on an app that display the objects of a primary key. The server runs fine but I get an error on the browser that says: 'master_courses' objects has no attribute 'masterCourses_slug' The code looks like this: from django.shortcuts import render, redirect from .models import master_courses, course_category, course_series def single_slug(requests, single_slug): categories = [c.course_slug for c in course_category.objects.all()] if single_slug in categories:

问题 I am learing Django on Django at a glance | Django documentation | Django When introducing URLconf It reads: To design URLs for an app, you create a Python module called a URLconf. A table of contents for your app, it contains a simple mapping between URL patterns and Python callback functions. Nevertheless, a callback function is not called. mysite/news/urls.py from django.conf.urls import url from . import views urlpatterns = [ url(r'^articles/([0-9]{4})/$', views.year_archive), ] print(

问题 My urls.py : urlpatterns = [ ... url(r'^profile/$', profile.profile, name='profile'), ] My model : class Reg(models.Model): name = models.CharField(max_length=32, primary_key=True) user = models.OneToOneField(settings.AUTH_USER_MODEL, on_delete=models.PROTECT, related_name='%(app_label)s_%(class)s_reg', null=True) ... def get_absolute_url(self): return reverse('core:profile', ???) My views : @login_required def profile(request): context_dict = {} u = User.objects.get(username=request.user)

问题 Following the tutorial at djangoproject, I have tried to have urls.py filter out the polls with no choices with the urlpattern below. urlpatterns = patterns('', url(r'^$', ListView.as_view( queryset=Poll.objects.filter(choice__choice_text__isnull=False) \ .filter(pub_date__lte=timezone.now) \ .order_by('-pub_date')[:5], context_object_name='latest_polls', template_name='polls/index.html'), name='index'), url(r'^(?P<pk>\d+)/$', DetailView.as_view( queryset=Poll.objects.filter(choice__choice

问题 I'm developing a site that have two types of User, and the project's owners want two different home (templates) after the user is authenticated, so, I tried this: url # home a url(r'^home/$', HomeAView.as_view(), name='home-a'), # home b url(r'^home/$', HomeBView.as_view(), name='home-b'), And some like that at into my log_in view: if user.typeUser == "HA": print('Go to Home A') return redirect(reverse('sesion:home-a')) else: print('Go to Home B') return redirect(reverse('sesion:home-b')) So