django-urls

问题 How do I nest url calls in django? For example, if I have two models defined as class Post(models.Model): title = models.CharField(max_length=50) body = models.TextField() created = models.DateTimeField(auto_now_add=True, editable=False) def __unicode__(self): return self.title @property def comments(self): return self.comment_set.all() class Comment(models.Model): comment = models.TextField() post = models.ForeignKey(Post) created = models.DateTimeField(auto_now_add=True) With the following

问题 How do I nest url calls in django? For example, if I have two models defined as class Post(models.Model): title = models.CharField(max_length=50) body = models.TextField() created = models.DateTimeField(auto_now_add=True, editable=False) def __unicode__(self): return self.title @property def comments(self): return self.comment_set.all() class Comment(models.Model): comment = models.TextField() post = models.ForeignKey(Post) created = models.DateTimeField(auto_now_add=True) With the following

问题 I was having some problems with the regex in urls.py (I am a beginner to django as well as regexes in general) Here is my original urls.py url(r'^name/(?P<name>\w+)/$', 'course.views.name'), url(r'^', 'course.views.index'), And I was trying to access it using this: http://127.0.0.1:8000/name/blah/ My view looks like: def index(request): return HttpResponse("Hello, sam. You're at the course index.") def name(request, name): return HttpResponse("Hello, %s. You're at the course index." % name)

问题 I was having some problems with the regex in urls.py (I am a beginner to django as well as regexes in general) Here is my original urls.py url(r'^name/(?P<name>\w+)/$', 'course.views.name'), url(r'^', 'course.views.index'), And I was trying to access it using this: http://127.0.0.1:8000/name/blah/ My view looks like: def index(request): return HttpResponse("Hello, sam. You're at the course index.") def name(request, name): return HttpResponse("Hello, %s. You're at the course index." % name)

问题 I have two pages, one which is to display details for a specific item and another to search for items. Let's say that the urls.py is properly configured for both of them and within views.py for my app, I have: def item(request, id): return render(request, 'item.html', data) def search(request): #use GET to get query parameters if len(query)==1: #here, I want to redirect my request to item, passing in the id return render(request, 'search.html', data) What do I do to properly redirect the

问题 I have model named Book in models.py file. And this model has slug field to display details of books Books are being displayed in home.html template and product.html template is to display details of selected book. I really don't know much about slugs, and how they work. Models.py: class Book(models.Model): id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False) title = models.CharField('Title', max_length=255) authors = models.ManyToManyField(Author, related_name='books

问题 I have model named Book in models.py file. And this model has slug field to display details of books Books are being displayed in home.html template and product.html template is to display details of selected book. I really don't know much about slugs, and how they work. Models.py: class Book(models.Model): id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False) title = models.CharField('Title', max_length=255) authors = models.ManyToManyField(Author, related_name='books

问题 In my blog website I want to open another user's profile on clicking one of the links. But it keeps on showing 404 error saying No user matches the given query. Here's that link in a base.html <a href="{% url 'blogapp:userprofile' username=view.kwargs.username %}">{{ view.kwargs.username }}</a> Here's my urls.py pattern for the function- path('userprofile/<str:username>/',views.userprofile,name='userprofile'), Here's my function views.py @login_required def userprofile(request,username): user

问题 I want to integrate elastic search with django but first I need to get a nice parameter in url http://127.0.0.1:8000/search?q=search+term urls.py (of the view) urlpatterns = [ path('?q=', SearchIndexView.as_view(), name="search-index"), ] urls.py (of the app) urlpatterns = [ path('admin/', admin.site.urls), path('', include('home.urls')), path('u/', include('user.urls')), path('search', include('search.urls')), ] That is what I have so far but I cant figure out how to make it work. I want to

问题 i am making a blog application for my website with django-2.0 when i run server i see the following error File "C:\Users\User\Desktop\djite\djite\djite\urls.py", line 7, in <module> url(r'^blog/', include('blog.urls', namespace='blog', app_name='blog')), TypeError: include() got an unexpected keyword argument 'app_name' here is my main urls.py from django.contrib import admin from django.conf.urls import url,include urlpatterns = [ url(r'^admin/', admin.site.urls), url(r'^blog/', include(