django-staticfiles

I was tried n I can't set-up as per official documents... I am attaching IMG here, pls give me suggestions, Where is the problem. enter image description here Or, give me simple steps for it with dictionary tree structure. Thank you. # Static files (CSS, JavaScript, Images) # https://docs.djangoproject.com/en/1.8/howto/static-files/ STATIC_URL = '/static/' STATIC_ROOT = os.path.join(BASE_DIR, 'static_root', 'static') STATICFILES_DIRS = ( os.path.join(BASE_DIR, 'static'), # '/var/www/static/', ) STATIC_ROOT = 'os.path.join(BASE_DIR, 'static_root', 'static') can't work. Try this : # define your

I have had django media images working in an existing django 1.7 project by adding the following to site urls.py: urlpatterns = patters( url(r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT, 'show_indexes': True}), ) This url structure doesn't work in django 1.10 and so I changed it to the reccommended here Django MEDIA_URL and MEDIA_ROOT : urlpatterns = [ ] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT) This fails to render any uploaded media images. Is there an equivalent media url patter for django 1.10 I can use? You can use this:

My django.contrib.staticfiles settings seems to be ok as all static files get served as expected. However, eg. /static/*.css files do not get gzipped although I have GZipMiddleware turned on. Fyi. my views html actually does get gzipped, only the files served by the staticfiles app dont. Seems these responses dont go through the middleware chain? The trick is to have the development server run with the '--nostatic' flag set: ./manage.py runserver --nostatic . One then can user a url pattern for serving the static files like so: if settings.DEBUG: static_pattern = r'^%s(?P<path>.*)$' %

I would like to use some custom CSS and images on my custom 404/500 pages that I made. Django doesn't include the STATIC_URL variable in those pages though. What would be the best way to accomplish this? I also tried making a custom 404/500 view and rendering an arbitrary HTML file but it didn't work out so great. Here's how I would do it: # urls or settings handler500 = 'mysite.views.server_error' # views from django.shortcuts import render def server_error(request): # one of the things ‘render’ does is add ‘STATIC_URL’ to # the context, making it available from within the template. response

I have been breaking my head over this for a full day but can't figure out the problem. It happened after I copied my project from one machine to another. Settings.py STATIC_URL = '/static/' STATIC_ROOT = 'staticfiles' STATICFILES_DIRS = ( os.path.join(BASE_DIR, "static"), ) Mentioned 'django.contrib.staticfiles' in INSTALLED_APPS as well. Folder structure : Django-Projects (root) project app static css home.css js manage.py Template : {% load staticfiles %} <link rel="stylesheet" href="{% static 'css/home.css' %}"> urls.py urlpatterns = patterns('', url(r'^admin/', include(admin.site.urls)),

Server returned TemplateSyntaxError at / Invalid block tag: 'static' on this line: <img src="{% static 'icon/logo.png' %}"> . The whold html file is like this (it's an html file {% include %}ed by another one): {% load staticfiles %} <div class="header"> <nav> <ul class="nav nav-pills pull-right"> <li role="presentation"><a href="{% url 'offer rank' %}">潮品榜</a></li> <li role="presentation"><a href="{% url 'user rank' %}">达人榜</a></li> <li role="presentation"><a href="#" data-toggle="modal" data-target="#start">登陆</a></li> <li role="presentation"><a href="#" data-toggle="modal" data-target="

I have a django app on heroku which serves the static files from amazon s3 bucket. I use boto library and followed the guide on the website. What can I do to speed up the file transfers? Some of the code: DEFAULT_FILE_STORAGE = 'storages.backends.s3boto.S3BotoStorage' AWS_ACCESS_KEY_ID = 'xxxx' AWS_SECRET_ACCESS_KEY = 'xxxx' AWS_STORAGE_BUCKET_NAME = 'boxitwebservicebucket' STATICFILES_STORAGE = 'storages.backends.s3boto.S3BotoStorage' STATIC_URL = 'http://' + AWS_STORAGE_BUCKET_NAME + '.s3.amazonaws.com/' the view class GetFileContent(View): def get(self,request, userName, pk): user = User