django-settings

I am new to Python decorators so perhaps I am missing something simple, here is my situation: This works for me: def test_something(self): settings.SETTING_DICT['key'] = True #no error ... But this throws a "SyntaxError: keyword can't be an expression": @override_settings(SETTING_DICT['key'] = True) #error def test_something(self): ... Just to be clear, normal use of override settings works: @override_settings(SETTING_VAR = True) #no error def test_something(self): ... Is there a way to use the decorator with a settings dictionary, or am I doing something wrong? Thanks in advance! You should

I am following a Django Tutorial where you are required to construct some image thumbnails once an image is saved in admin. I am also using Python's tempfile module to save a temporary file name. However I keep running into the following error: "Type: IOError" "Value: [Errno 13] Permission denied: 'c:\\docume~1\\myname\\locals~1\\temp\\somefilename'" Here is the code I am using Settings MEDIA_ROOT = '/home/myname/projectname/media/' MEDIA_URL = 'http://127.0.0.1:8000/media/'enter code here models.py from string import join import os from PIL import Image as PImage from settings import MEDIA

Looking in django.conf I noticed that settings are implemented like this: class LazySettings(LazyObject): ... What is the rationale behind making settings objects lazy? Michael Mior Check out this section of the Django coding style. The reason is explained in there (quoted below). In addition to performance, third-party modules can modify settings when they are imported. Accessing settings should be delayed to ensure this configuration happens first. Modules should not in general use settings stored in django.conf.settings at the top level (i.e. evaluated when the module is imported). The

Note the settings/dev.py instead of one settings.py file and the script.py in my_app in the following Django(1.4.3) project: . ├── my_project │ ├── my_app │ │ ├── __init__.py │ │ ├── models.py │ │ ├── tests.py │ │ ├── views.py │ │ └── script.py │ ├── __init__.py │ ├── settings │ │ ├── dev.py │ │ ├── __init__.py │ │ └── prod.py │ ├── urls.py │ └── wsgi.py ├── manage.py └── requirements.txt When I only had one settings.py file in place of the settings folder I was able to run the following script without any errors : script.py: ###################################################################

I am getting problem in Django project setting with POSTGRESQL. Here is my setting.py database setting DATABASES = { 'default':{ 'ENGINE':'django.db.backends.postgresql_psycopg2', # '.postgresql_psycopg2', '.mysql', or '.oracle' 'NAME':'indivo', # Required to be non-empty string 'USER':'indivo', # Required to be non-empty string 'PASSWORD':'ritvik', 'HOST':'', # Set to empty string for localhost. 'PORT':'', # Set to empty string for default. }, } Now in postgres backend what I have done is . rohit@rohit-desktop:~$ sudo su - postgres postgres@rohit-desktop:~$ createuser --superuser indivo #

I have a template that renders an image: {% load staticfiles %} <img src="{% static "img/logo.png" %}" alt="My image"/> The image link is broken, but it points to: localhost/static/img/logo.png What are values I need to set for static_root, static_url, and STATICFILES_DIRS to get this image to show up correctly? This is my directory structure: myprojectname (top level) --- myprojectname --- --- myproectname --- --- --- settings --- --- --- --- base.py (setting.py) --- --- static --- --- --- img This is my static configuration in settings: STATIC_ROOT = '/Users/myuser/myprojectname