division

I was writing this code in C when I encountered the following problem. #include <stdio.h> int main() { int i=2; int j=3; int k,l; float a,b; k=i/j*j; l=j/i*i; a=i/j*j; b=j/i*i; printf("%d %d %f %f\n",k,l,a,b); return 0; } Can anyone tell me why the code is returning zero for the first and third variables ( k and a )? What I think you are experiencing is integer arithmetic . You correctly suppose l and b to be 2, but incorrectly assume that k and a will be 3 because it's the same operation. But it's not, it's integer arithmetic (rather than floating-point arithmetic). So when you do i / j

I've a strange issue in Python: the division is not performed correctly: print pointB[1] print pointA[1] print pointB[0] print pointA[0] print (pointB[1]-pointA[1]) / (pointB[0]-pointA[0]) These are the results: 100 50 100 40 0 thanks user225312 The above behavior is true for Python 2. The behavior of / was fixed in Python 3. In Python 2 you can use: from __future__ import division and then use / to get the result you desire. >>> 5 / 2 2 >>> from __future__ import division >>> 5 / 2 2.5 Since you are dividing two integers, you get the result as an integer. Or, change one of the numbers to a

In Python and Ruby, signed integer division truncates towards negative infinity, and signed integer modulus has the same sign the second operand: >>> (-41) / 3 -14 >>> (-41) % 3 1 However, in C and Java, signed integer division truncates towards 0, and signed integer modulus has the same sign as the first operand: printf("%d\n", (-41) / 3); /* prints "-13" */ printf("%d\n", (-41) % 3); /* prints "-2" */ What is the simplest and most efficient way in C to perform the same kind of division and modulus as in Python and Ruby? Ville Laurikari The direction for rounding with signed integer division