division

How to divide each row of a calculated column by the total of another calculated column?

和自甴很熟 提交于 2019-12-02 05:46:15
I can't get a division correct with this sample data: Calculated column Another calc. column 48 207 257 370 518 138 489 354 837 478 1,005 648 1,021 2,060 1,463 2,164 2,630 1,818 2,993 2,358 3,354 3,633 4,332 5,234 4,885 6,108 4,514 6,008 4,356 6,888 4,824 7,382 7,082 5,988 7,498 6,059 4,865 4,192 3,816 2,851 2,768 2,093 2,207 770 397 149 178 336 167 124 18 What I'm trying to do is to create a new calculated column. For each row I want to get the value of Calculated column and divide it by the Total of Another calc. column . The Total of Another calc. column = 82826 This is the desired output

Division operation is giving me the wrong result

不问归期 提交于 2019-12-02 05:17:41
I'm trying to divide one number by another in Processing, and I keep getting the wrong answer. float a; a = 3/2; println(a); gives me 1.0 when then answer should be 1.5. Trying a different number, float a; a = 2/3; println(a); gives me 0.0 when the answer should be 0.666666.... Is there something I'm missing? I looked over the Processing documentation for division and it seems like I'm using the right syntax. Like others have said, you're using integer division. Remember that int values can't hold decimal places. So if you do a calculation that would result in decimal places, those values are

Division on the fly [duplicate]

北慕城南 提交于 2019-12-02 03:53:01
This question already has an answer here: Trouble with calling method [duplicate] 2 answers I'm trying to make a small program in Java which converts Fahrenheit to Celsius. It involves deducting 32 and multiplying by 5/9. So I did this. double Fahrenheit = 100; double celsius = (Fahrenheit - 32) * (5/9); System.out.println(celsius); But for some reason that 5/9 returns zero which ruins it all, even double s = 5/9; returns zero and I don't know why. The only way I found I can do it is if I declare everything and do it slowly, step by step. double x = 5, p = 9, n = (x/p), Fah = 100; double Cel =

Implementing long division using a generator function in python

北战南征 提交于 2019-12-02 03:51:34
问题 As an exercise to try to understand generator functions I am trying to write a function that simulates long division and returns the number one digit at a time. I have written this function and it doesn't seem to work. However if I step through it line by line in the shell it does exactly what I want it to do so I'm not sure what to do going forward. I've read through posts on the internet about generator functions here: and from what I understand I just replace the return statement with a

How to let GCC compiler turn variable-division into mul(if faster)

戏子无情 提交于 2019-12-02 03:30:29
int a, b; scanf("%d %d", &a, &b); printf("%d\n", (unsigned int)a/(unsigned char)b); When compiling, I got ... ::00401C1E:: C70424 24304000 MOV DWORD PTR [ESP],403024 %d %d ::00401C25:: E8 36FFFFFF CALL 00401B60 scanf ::00401C2A:: 0FB64C24 1C MOVZX ECX,BYTE PTR [ESP+1C] ::00401C2F:: 8B4424 18 MOV EAX,[ESP+18] ::00401C33:: 31D2 XOR EDX,EDX ::00401C35:: F7F1 DIV ECX ::00401C37:: 894424 04 MOV [ESP+4],EAX ::00401C3B:: C70424 2A304000 MOV DWORD PTR [ESP],40302A %d\x0A ::00401C42:: E8 21FFFFFF CALL 00401B68 printf Will it be faster if the DIV turn into MUL and use an array to store the mulvalue? If

Binary divisibility by 10

时光总嘲笑我的痴心妄想 提交于 2019-12-02 03:07:51
How to check if a binary number can be divided by 10 (decimal), without converting it to other system. For example, we have a number: 1010 1011 0100 0001 0000 0100 How we can check that this number is divisible by 10? First split the number into odd and even bits (I'm calling "even" the bits corresponding to even powers of 2): 100100110010110000000101101110 0 1 0 1 0 0 1 0 0 0 1 1 0 1 0 even 1 0 0 1 0 1 1 0 0 0 0 0 1 1 1 odd Now in each of these, add and subtract the digits alternately, as in the standard test for divisibility by 11 in decimal (starting with addition at the right):

Why are the results of integer division and converting to an int after division different for large numbers?

血红的双手。 提交于 2019-12-02 02:54:21
print(10**40//2) print(int(10**40/2)) Output of the codes: 5000000000000000000000000000000000000000 5000000000000000151893014213501833445376 Why different values? Why the output of the second print() looks so? The floating point representation of 10**40//2 is not accurate: >>> format(float(10**40//2), '.0f') '5000000000000000151893014213501833445376' That's because floating point arithmetic is only ever an approximation, especially when you go beyond what your CPU can accurately model (as floating point is handled in hardware). The integer division never has to represent the 10**40 number as a

Implementing long division using a generator function in python

谁都会走 提交于 2019-12-02 01:43:01
As an exercise to try to understand generator functions I am trying to write a function that simulates long division and returns the number one digit at a time. I have written this function and it doesn't seem to work. However if I step through it line by line in the shell it does exactly what I want it to do so I'm not sure what to do going forward. I've read through posts on the internet about generator functions here: and from what I understand I just replace the return statement with a yield statement. Is this not the case? Can anybody please tell me what I am doing wrong? Any help is

Why byte and short division results in int in Java?

僤鯓⒐⒋嵵緔 提交于 2019-12-02 00:47:54
问题 In Java, if we divide byte s, short s or int s, we always get an int . If one of the operands is long , we'll get long . My question is - why does byte or short division not result in byte or short ? Why always int ? Apparently I'm not looking for the "because JLS says so" answer, I am asking about the technical rationale for this design decision in the Java language. Consider this code sample: byte byteA = 127; byte byteB = -128; short shortA = 32767; short shortB = -32768; int intA =

Dividing two numbers always equals zero?

爱⌒轻易说出口 提交于 2019-12-02 00:34:21
In my Xna game, I am trying to have my playfield scale to the screen that it is running on. To do this, I use proportions to find the percent that the real window is scaled relative to my playfield. To do this, I divide the real width by the virtual width: float _percent = _realViewport.Width / this._viewport.Width; I always get 0, though, in the _percent variable. I set up a debug stop point at that line in my code, and analyzed the variables. this._viewport.Width equals 640, and _realViewport.Width equals 1280. So, using my calculator, 640 / 1280 SHOULD equal 0.5, but in my code I always get