divide-by-zero | 易学教程

divide emu 8086 assembly error [duplicate]

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问题 Possible Duplicate: ASM x86 integer overflow I get a divide error- overflow and am not sure why. Here is the complete code that reproduces the error include emu8086.inc org 100h mov ax, 2 mov bx, 10 div bx mov ax, 2 mov bx, 2 div bx ret 回答1: Try adding xor dx, dx before each div and see if that doesn't help. Since you're specifying a 16-bit target, div divides dx:ax by that target. If dx starts out containing a large number (more accurately, anything but quite a small number), the result will

PowerShell - Why “Divide By Zero Exception” is not being Caught?

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问题 On my Machine each one of the following code snippets throws and exception instead of printing to the standard output "1" and "2" Why the exception is not being Caught? try { [int]$a = 1/0 } catch { write 1 } finally { write 2 } try { [int]$a = 1/0 } catch [System.Exception] { write 1 } finally { write 2 } 回答1: As you are using constants, the interpreter tries to precompute the result and fails with a division by zero error. Your code does not even get executed so there's nothing to trap. You

How does Java handle division by zero? [duplicate]

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问题 This question already has answers here : In java, “5/0” statement doesn't fire SIGFPE signal on my Linux machine, why? (6 answers) Closed 5 years ago . Does it simply check if divisor is different from zero every time there is division done (even in JIT-ed code)? I mean how VM manages to throw an exception without being previously killed by the OS? 回答1: In an Unix environment, in which division-by-zero is signal led via SIGFPE , the JVM will have installed a signal handler which traps the

Why does C# allow dividing a non-zero number by zero in floating-point type?

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Why C# allows: 1.0 / 0 // Infinity And doesn't allow: 1 / 0 // Division by constant zero [Compile time error] Mathematically, is there any differences between integral and floating-point numbers in dividing by zero? SethO According to Microsoft, "Floating-point arithmetic overflow or division by zero never throws an exception, because floating-point types are based on IEEE 754 and so have provisions for representing infinity and NaN (Not a Number)." More on this here . Mathematically, there is no difference. With computers, however, only the standard IEEE-754 floating-point specification has

c++ division by 0

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I am running long simulations. I record the results into a vector to compute statistics about the data. I realized that, in theory, those samples could be the result of a division by zero; this is only theoretical, I am pretty sure it's not the case. In order to avoid rerunning the simulation after modifying the code, I was wondering what happens in that case. Would I be able to realize whether a division by 0 has occurred or not? Will I get error messages? (Exceptions are not being handled at the moment). Thanks etarion For IEEE floats, division of a finite nonzero float by 0 is well-defined

Best way to prevent/handle divide by 0 in javascript

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What is the best way to prevent divide by 0 in javascript that is accepting user inputs. If there is no particular way to achieve this what would be the best way to handle such a situation so as to not prevent other scripts from executing? Any insights are much appreciated. There is no way to do that with the normal / and /= operators. The best way to do what you want is with guards: function notZero(n) { n = +n; // Coerce to number. if (!n) { // Matches +0, -0, NaN throw new Error('Invalid dividend ' + n); } return n; } and then do division like numerator / notZero(denominator) Alternatively

Division by zero: Undefined Behavior or Implementation Defined in C and/or C++?

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问题 Regarding division by zero, the standards say: C99 6.5.5p5 - The result of the / operator is the quotient from the division of the first operand by the second; the result of the % operator is the remainder. In both operations, if the value of the second operand is zero, the behavior is undefined. C++03 5.6.4 - The binary / operator yields the quotient, and the binary % operator yields the remainder from the division of the first expression by the second. If the second operand of / or % is

try-catch for division by zero

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问题 My question is about try-catch blocks on a simple division by zero example. You see the first line of try? If I cast any of those two variables to the double the program does not recognize the catch block. In my opinion, whether I cast or not only the catch block must be executed. What is wrong on this code? public static void main(String[] args) { int pay=8,payda=0; try { double result=pay/(double)payda; // if I cast any of the two variables, program does not recognize the catch block, why

Why does integer division by zero result in a floating point exception?

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问题 Division by zero in a C program results in abnormal termination with the error message Floating point exception (core dumped) . This is unsurprising for floating point division, but why does it say this when integer division by zero occurs? Does integer division actually use the FPU under the hood? (This is all on Linux under x86, by the way.) 回答1: Does integer division actually use the FPU under the hood? No, Linux just generates SIGFPE in this case too (it's a legacy name whose usage has

How should I throw a divide by zero exception in Java without actually dividing by zero?

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问题 I have an I2C device that wants two inputs: a denominator and a numerator. Both are written to separate addresses, so no actual calculation ( numerator/denominator ) is done. The problem with this is that a divide by zero could occur on the I2C device, so a divide by zero error needs to be checked for. Ideally, exactly the same thing would happen if the dividing were done by the java code. At the moment, I've bodged an unused variable that does the division, but I'm worried it'll get