divide-by-zero

Summary: I'm looking for the fastest way to calculate (int) x / (int) y without getting an exception for y==0 . Instead I just want an arbitrary result. Background: When coding image processing algorithms I often need to divide by an (accumulated) alpha value. The most simple variant is plain C code with integer arithmetic. My problem is that I typically get a division by zero error for result pixels with alpha==0 . However this are exactly the pixels where the result doesn't matter at all: I don't care about color values of pixels with alpha==0 . Details: I'm looking for something like:

Possible Duplicate: ASM x86 integer overflow I get a divide error- overflow and am not sure why. Here is the complete code that reproduces the error include emu8086.inc org 100h mov ax, 2 mov bx, 10 div bx mov ax, 2 mov bx, 2 div bx ret Try adding xor dx, dx before each div and see if that doesn't help. Since you're specifying a 16-bit target, div divides dx:ax by that target. If dx starts out containing a large number (more accurately, anything but quite a small number), the result will overflow. Even if it doesn't overflow, your result won't just be ax / bx as you apparently intend. 来源：

Why should the following code in Java System.out.println(new Integer(1)/ new Double(0)); print 'Infinity' and not undefined. Isn't that mathematically wrong? In mathematics, there are many different structures that support arithmetic. The most prominent ones, such as the natural numbers, the integers, and the real numbers, do not include infinity. In those systems, division by zero is not supported. Other systems do include at least one infinity. See, for example, the real projective line . It does permit division by zero. There is only one way to know what is mathematically defined or

This question already has an answer here: In java, “5/0” statement doesn't fire SIGFPE signal on my Linux machine, why? 6 answers Does it simply check if divisor is different from zero every time there is division done (even in JIT-ed code)? I mean how VM manages to throw an exception without being previously killed by the OS? In an Unix environment, in which division-by-zero is signal led via SIGFPE , the JVM will have installed a signal handler which traps the SIGFPE and in turn throw s an ArithmeticException . If you're interested in the internals, see e.g. man signal What I believe the OP

My question is about try-catch blocks on a simple division by zero example. You see the first line of try? If I cast any of those two variables to the double the program does not recognize the catch block. In my opinion, whether I cast or not only the catch block must be executed. What is wrong on this code? public static void main(String[] args) { int pay=8,payda=0; try { double result=pay/(double)payda; // if I cast any of the two variables, program does not recognize the catch block, why is it so? System.out.println(result); System.out.println("inside-try"); } catch (Exception e) { System

Regarding division by zero, the standards say: C99 6.5.5p5 - The result of the / operator is the quotient from the division of the first operand by the second; the result of the % operator is the remainder. In both operations, if the value of the second operand is zero, the behavior is undefined. C++03 5.6.4 - The binary / operator yields the quotient, and the binary % operator yields the remainder from the division of the first expression by the second. If the second operand of / or % is zero the behavior is undefined. If we were to take the above paragraphs at face value, the answer is

Division by zero in a C program results in abnormal termination with the error message Floating point exception (core dumped) . This is unsurprising for floating point division, but why does it say this when integer division by zero occurs? Does integer division actually use the FPU under the hood? (This is all on Linux under x86, by the way.) Does integer division actually use the FPU under the hood? No, Linux just generates SIGFPE in this case too (it's a legacy name whose usage has now been extended). Indeed, the Single Unix Specification defines SIGFPE as " Erroneous arithmetic operation "

I have a function for statistic issues: import numpy as np from scipy.special import gamma as Gamma def Foo(xdata): ... return x1 * ( ( #R is a numpy vector ( ((R - x2)/beta) ** (x3 -1) ) * ( np.exp( - ((R - x2) / x4) ) ) / ( x4 * Gamma(x3)) ).real ) Sometimes I get from the shell the following warning: RuntimeWarning: divide by zero encountered in... I use the numpy isinf function to correct the results of the function in other files, so I do not need this warning. Is there a way to ignore the message? In other words, I do not want the shell to print this message. I do not want to disable all