div

使几个DIV在同一行并排显示,有间隙的情况的处理方案

好久不见. 提交于 2020-02-21 04:24:01
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>让块级标签并排显示并且设置间隙</title> <style> *{margin:0;padding:0} .father{ height: 460px; width:460px; border: 1px solid gray; } .son{ height:100px; width: 100px; } </style> </head> <body> <div class="father"> <div style="background-color: red;" class="son">son1</div> <div style="background-color: gold;" class="son">son2</div> <div style="background-color: green;" class="son">son3</div> <div style="background-color: blue;" class="son">son4</div> </div> </body> </html> 上面的代码是没有设置时的代码。 设置完成后的效果图 如果只对父元素和子元素设置width和height

jquery div拖动效果示例代码

女生的网名这么多〃 提交于 2020-02-20 12:39:34
div拖动效果想必大家都有见到过吧,实现的方法也是有很多的,下面为大家将介绍使用jquery是如何实现的,感兴趣的朋友不要错过 复制代码 代码如下: <%@ page language="java" contentType="text/html; charset=utf-8" pageEncoding="utf-8"%> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>拖动DIV-www.jbxue.com</title> <style type="text/css"> .show{ background:#7cd2f8; width:100px; height:100px; text-align:center; position:absolute; z-index:1; left:100px; top:100px; } </style>

jquery实现DIV层拖动

拟墨画扇 提交于 2020-02-20 12:00:19
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" " http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd "> <html xmlns=" http://www.w3.org/1999/xhtml "> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>拖动DIV</title> <style type="text/css"> .show{ background:#7cd2f8; width:100px; height:100px; text-align:center; position:absolute; z-index:1; left:100px; top:100px; } </style> <script type="text/javascript" src="js/jq.js"></script> <script type="text/javascript"><!-- $(document).ready(function() { $(".show").mousedown(function(e)//e鼠标事件 { $(this

asp.net div弹出式登录窗口

末鹿安然 提交于 2020-02-19 12:00:12
<html xmlns=" http://www.w3.org/1999/xhtml "> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/> <title>兼容IE,FF的弹出层登陆界面 - 中国asp之家</title> <style type="text/css"> * { margin:0; padding:0; font-size:12px; font-weight:normal; font-family:verdana, tahoma, helvetica, arial, sans-serif, "宋体"; font-style:normal; list-style-type:none; text-decoration:none; } div#body input#fnbtn { width:78px; height:39px; border:none; cursor:pointer; position:absolute; top:40px; left:100px; background:transparent url('200814122558235.png') 0 -70px no-repeat; } div#mask { position:absolute; top

用DIV模拟弹出窗口--窗体滚动跟随--丁学

做~自己de王妃 提交于 2020-02-19 11:54:50
复制以下代码直接写到记事本里保存成html文件即可看到效果 IE6、IE7、FF2兼容,其他浏览器未测试 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="zh-CN"> <head> <title>丁学-博客园-http://www.cnblogs.com/dingxue</title> <script> function getPosition() { var top = document.documentElement.scrollTop; var left = document.documentElement.scrollLeft; var height = document.documentElement.clientHeight; var width = document.documentElement.clientWidth; return {top:top,left:left,height:height,width:width}; } function showPop(){

Codeforces Round #621 (Div. 1 + Div. 2)B. Cow and Friend

拜拜、爱过 提交于 2020-02-19 07:21:51
B. Cow and Friend time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output Bessie has way too many friends because she is everyone’s favorite cow! Her new friend Rabbit is trying to hop over so they can play! More specifically, he wants to get from (0,0) to (x,0) by making multiple hops. He is only willing to hop from one point to another point on the 2D plane if the Euclidean distance between the endpoints of a hop is one of its n favorite numbers: a1,a2,…,an. What is the minimum number of hops Rabbit needs to get from (0,0) to (x,0)? Rabbit

Codeforces Round #620 (Div. 2)_D. Shortest and Longest LIS(C++_最长上升子序列)

旧街凉风 提交于 2020-02-17 21:06:46
Gildong recently learned how to find the longest increasing subsequence (LIS) in O(nlogn) time for a sequence of length n. He wants to test himself if he can implement it correctly, but he couldn’t find any online judges that would do it (even though there are actually many of them). So instead he’s going to make a quiz for you about making permutations of n distinct integers between 1 and n, inclusive, to test his code with your output. The quiz is as follows. Gildong provides a string of length n−1, consisting of characters ‘<’ and ‘>’ only. The i-th (1-indexed) character is the comparison

Codeforces Round #619 (Div. 2)

守給你的承諾、 提交于 2020-02-17 18:57:50
A. Three Strings 思维题 题目大意 :给你三个长度相等的字符串s1,s2,s3,现在要求你的每一位进行如下操作: i - s1用 i - s3 替换 或 i - s2 用 i - s3 替换。问进行完操作后能否使s1=s2; 解题思想: 如果能进行操作的话,每一位必有 i - s1 = i - s3 或 i - s2 = i - s3;因为,存在i - s1 = i - s3 或 i - s2 = i - s3的话,可以将对方串与s3进行替换,这样就使得s1=s2。 AC代码: # include <bits/stdc++.h> using namespace std ; typedef long long ll ; const double PI = acos ( - 1.0 ) ; int main ( ) { ios :: sync_with_stdio ( false ) ; int t ; cin >> t ; while ( t -- ) { bool flag = 0 ; string s1 , s2 , s3 ; cin >> s1 >> s2 >> s3 ; for ( int i = 0 ; i < s1 . size ( ) ; ++ i ) { if ( s1 [ i ] == s3 [ i ] || s2 [ i ] == s3 [ i ]

让div高度撑满屏幕的方法

时光怂恿深爱的人放手 提交于 2020-02-17 16:11:59
在body只有一个div的时候,可以通过这样的方式让div撑满整个屏幕。 1.给div设置定位。 复习一下—— css中position有五种属性: static:默认值,没有定位 absolute:绝对定位,相对于父级元素进行定位 relative:相对定位 fixed:固定定位,相对于浏览器窗口进行定位 inherit:从父元素继承定位信息 除了默认值static和inherit之外,添加其他三种都可以实现窗口自适应。 在这里插入代码片 <style> 2 *{ 3 margin: 0; 4 padding: 0; 5 } 6 div{ 7 width:100%; 8 height: 100%; 9 background: yellow; 10 position: absolute; 11 } 12 13 </style> 14 15 16 <body> 17 18 <div></div> 19 20 </body> ---------- 2.通过将html设为高度百分百 <style> 2 *{ 3 margin: 0; 4 padding: 0; 5 } 6 html,body{ 7 width: 100%; 8 height: 100%; 9 } 10 div{ 11 width:100%; 12 height: 100%; 13 background: yellow;

Codeforces Round #620 (Div. 2) A. Two Rabbits

无人久伴 提交于 2020-02-16 11:31:52
Being tired of participating in too many Codeforces rounds, Gildong decided to take some rest in a park. He sat down on a bench, and soon he found two rabbits hopping around. One of the rabbits was taller than the other. He noticed that the two rabbits were hopping towards each other. The positions of the two rabbits can be represented as integer coordinates on a horizontal line. The taller rabbit is currently on position x x , and the shorter rabbit is currently on position y y ( x < y x<y ). Every second, each rabbit hops to another position. The taller rabbit hops to the positive direction