distribution

C++ get linux distribution name\version

本小妞迷上赌 提交于 2019-12-10 03:39:51
问题 According to the question " How to get Linux distribution name and version? ", to get the linux distro name and version, this works: lsb_release -a On my system, it shows the needed output: No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 9.10 Release: 9.10 Codename: karmic Now, to get this info in C++, Qt4's QProcess would be a great option but since I am developing without Qt using std c++, I need to know how to get this info in standard C++, i.e. the stdout of the

Fitting a pareto distribution with (python) Scipy

守給你的承諾、 提交于 2019-12-10 02:58:33
问题 I have a data set that I know has a Pareto distribution. Can someone point me to how to fit this data set in Scipy? I got the below code to run but I have no idea what is being returned to me (a,b,c). Also, after obtaining a,b,c, how do I calculate the variance using them? import scipy.stats as ss import scipy as sp a,b,c=ss.pareto.fit(data) 回答1: Be very careful fitting power laws!! Many reported power laws are actually badly fitted by a power law. See Clauset et al. for all the details (also

Fitting a distribution to data - MATLAB

天涯浪子 提交于 2019-12-09 13:13:15
问题 I am trying to fit a distribution to some data I've collected from microscopy images. We know that the peak at about 152 is due to a Poisson process. I'd like to fit a distribution to the large density in the center of the image, while ignoring the high intensity data. I know how to fit a Normal distribution to the data (red curve), but it doesn't do a good job of capturing the heavy tail on the right. Although the Poisson distribution should be able to model the tail to the right, it doesn't

Python code for counting number of zero crossings in an array

佐手、 提交于 2019-12-09 08:56:04
问题 I am looking to count the number of times the values in an array change in polarity (EDIT: Number of times the values in an array cross zero). Suppose I have an array: [80.6 120.8 -115.6 -76.1 131.3 105.1 138.4 -81.3 -95.3 89.2 -154.1 121.4 -85.1 96.8 68.2]` I want the count to be 8. One solution is to run a loop and check for greater than or less than 0, and keep a history of the previous polarity. Can we do this faster? EDIT: My purpose is really to find something faster, because I have

Python Uniform distribution of points on 4 dimensional sphere

一个人想着一个人 提交于 2019-12-09 05:51:05
问题 I need a uniform distribution of points on a 4 dimensional sphere. I know this is not as trivial as picking 3 angles and using polar coordinates. In 3 dimensions I use from random import random u=random() costheta = 2*u -1 #for distribution between -1 and 1 theta = acos(costheta) phi = 2*pi*random x=costheta y=sin(theta)*cos(phi) x=sin(theta)*sin(phi) This gives a uniform distribution of x, y and z. How can I obtain a similar distribution for 4 dimensions? 回答1: A standard way, though, perhaps

Where is my application binary in XCode?

痞子三分冷 提交于 2019-12-09 04:33:46
问题 I've built an app for the iTunes store. However, being a noob to the platform, I can't figure out how to submit the app. Where is the actual binary that I need to submit to the iTunes store? What folder does it get built in? 回答1: You could use XCode and on the left expand "Products". Highlight your .app and then go up top where it says "Action" drop that down and select "Reveal in Finder" 回答2: Look at a path something like this: "/Users/{user}/Library/Developer/Xcode/DerivedData/{appname

How to generate a list of random numbers so their sum would be equal to a randomly chosen number

♀尐吖头ヾ 提交于 2019-12-09 03:23:33
问题 I want to generate a list of random distribution of numbers so their sum would be equal to a randomly chosen number. For example, if randomly chosen number is 5, the distribution would be [1 2 2] or [2 3] or [1 1 1 2] and so on. Any suggestions are welcome! 回答1: Let n be the number you want values to add up to. Generate a random sample of random size (less than n ), consisting of values in the range 1 to n exclusive of n . Now add the endpoints 0 and n , and sort. Successive differences of

iOS Distribution Certificate expiring. what are my options?

て烟熏妆下的殇ゞ 提交于 2019-12-08 20:45:28
问题 My Current Distribution Certificate expired today. That means both my AdHoc and AppStore provisioning profiles expired as well. I have 2 apps that have already been submitted to Apple review; 1 is waiting for review, the other is 'in review'. It doesn't seem like i can generate a new Distribution Certificate as there is no option for it. Only revoke or download. I assume if I revoke it, i can then create a new Certificate. Is that correct? (1) and (2), if I do revoke it, what will happen to

xcode valid signing identity not found

我的梦境 提交于 2019-12-08 16:53:34
问题 I can't find the solution for this problem for 2 weeks!!! That is enormous. When I try to validate my app I face an error. Xcode shows: Valid signing identity for ... not found. I don't know what do and I have tried a lot. Please help. Here are the print-screens: Image1 http://img838.imageshack.us/img838/9749/20120910195154.png Full Size Image2 http://img100.imageshack.us/img100/9126/20120910195440.png Full Size 回答1: I think deleting all the certificates and re-making them should solve your

XNA game distribution questions

不想你离开。 提交于 2019-12-08 16:30:53
问题 I want to start on a 2D game using C#, so I'm checking out my options. XNA sounds good, but a few points are not very clear to me. If I use XNA, can I just build my game and distribute my game as a standalone executable from my website ? Or are there any catches ? Do people need special libraries to play my game ? Do I have to pay MS to be able to distribute my game ? Normally I'll write a program, build it, put the executable up for download and presto, anybody can download, install and use