distance

问题 Friends, could you help me to insert the distance between coordinates in my shiny. Basically my shiny has a sliderInput that corresponds to the desired number of clusters, followed by an option of which cluster he wants to see on the map, and the second option which industry of the selected cluster he wants to see. So far it is working properly. Note that on the map there is always a location point and an industry, because for the generation of the map I am joining database df with database

问题 Friends, could you help me to insert the distance between coordinates in my shiny. Basically my shiny has a sliderInput that corresponds to the desired number of clusters, followed by an option of which cluster he wants to see on the map, and the second option which industry of the selected cluster he wants to see. So far it is working properly. Note that on the map there is always a location point and an industry, because for the generation of the map I am joining database df with database

问题 I have a numpy 1D array of z values, and I want to calculate the difference between all combinations of the entries, with the output as a square matrix. I know how to calculate this as a distance between all combinations of the points using cdist, but that does not give me the sign: So for example if my z vector is [1,5,8] import numpy as np from scipy.spatial.distance import cdist z=np.array([1, 5, 8]) z2=np.column_stack((z,np.zeros(3))) cdist(z2,z2) gives me: array([[0., 4., 7.], [4., 0., 3

问题 I was wondering what the most efficient method of calculating the distance in miles between two US zipcode columns would be using R. I have heard of the geosphere package for computing the difference between zipcodes but do not fully understand it and was wondering if there were alternative methods as well. For example say I have a data frame that looks like this. ZIP_START ZIP_END 95051 98053 94534 94128 60193 60666 94591 73344 94128 94128 94015 73344 94553 94128 10994 7105 95008 94128 I

问题 I have a problem with soft keyboard overlapping parts of EditTexts. When I click my EditTexts the soft keyboard appears just below the text, which means that a part of the text box is not shown as the soft keyboard overlaps it. Any ideas how to increase the distance between EditText and Soft keyboard? 回答1: There will be certain Solutions available that some times works and some times not what I am using is working and will handle your scenario Use the following Step by step 1- Add Scroll view

问题 In my code being able to successfully get the distance between the two coordinate (lAT and LNG) but my listview returns the value for only one of the list of values. Kindly find my code below. String lat = ""; String lng = ""; Double distanceInKilometers = ""; Future getDistance() async { distanceInMeters = await Geolocator().distanceBetween( currentLocation.latitude, currentLocation.longitude, double.parse(lat), double.parse(lng)); distanceInKilometers = distanceInMeters.toInt() / 1000; }

问题 I would like to pick the closest previous owner within a set distance only after the first search condition isn't met. The locations are called reflo (reference location), and they have a corresponding x and y coordinates (called locx and locy , respectively). The conditions: if lifetime_census$reflo==owners$reflo.x[i] then condition is met if lifetime_census$reflo!=owners$reflo.x[i] , then find next closest record (within 30 meters) if there is no record within 30 meters, then assign NA

问题 I have two numpy arrays A and B. Shape of A is (m,3) and shape of B is (n, 3). Those matrix look like this: A #output array([[ 9.227, -4.698, -95.607], [ 10.294, -4.659, -94.606], [ 11.184, -5.906, -94.675], ..., [ 19.538, -91.572, -45.361], [ 20.001, -92.655, -45.009], [ 19.271, -92.726, -45.79 ]]) So it contains for each row the coordinates x,y,z of a 3D point. B follows the same format. I have this function (np is numpy): def compute_dist(point1, point2): squared = (point1-point2)**2

问题 I would like to generate a 2d Array like this using Python and Numpy: [ [0, 1, 2, 3, 4, 4, 3, 4], [1, 2, 3, 4, 4, 3, 2, 3], [2, 3, 4, 4, 3, 2, 1, 2], [3, 4, 4, 3, 2, 1, 0, 1], [4, 5, 5, 4, 3, 2, 1, 2] ] Pretty much the the numbers spread left and right starting from the zeros. This matrix allows to see the distance of any point to the closest zero. I thought this matrix was common, but I couldn't found anything on the web, even its name. If you have a code to efficiently generate such a

问题 Suppose we have three points, a, b, c. b and c are linked to become a line. how to use R to calculate the distance from a to this line? Is there any function? Thanks a lot 回答1: It has to be distinguished whether we are dealing with a two-dimensional or a three-dimensional case. 2D case If the problem is two-dimensional, the position of the points a , b and c can be defined by pairs of numbers which represent the points' x and the y coordinates. The following function can be used to calculate