distance

问题 float curpos = player.transform.position.magnitude; float targetpos=GameObject.Find ("target").transform.position.magnitude; float percentDist = (curCarpos / targetpos) * 100; What I want to do is calculate percentage along the way from current point which is always moving to end point, starting from zero and once it reaches it should be 100. For some reason it is starting from 14% decreasing to 0% and then starting from 0%-99%. 回答1: You do it all wrong. Vectors magnitude in this case it is

问题 I asked a question like this. But that is a simple one. Which has been resolved. how to merge strings that have substrings in common to produce some groups in a data frame in Python. But here, I have an advanced version of the similar question: I have a sample data: a=pd.DataFrame({'ACTIVITY':['b,c','a','a,c,d,e','f,g,h,i','j,k,l','k,l,m']}) What I want to do is merge some strings if they have sub strings in common. So, in this example, the strings 'b,c','a','a,c,d,e' should be merged

问题 I asked a question like this. But that is a simple one. Which has been resolved. how to merge strings that have substrings in common to produce some groups in a data frame in Python. But here, I have an advanced version of the similar question: I have a sample data: a=pd.DataFrame({'ACTIVITY':['b,c','a','a,c,d,e','f,g,h,i','j,k,l','k,l,m']}) What I want to do is merge some strings if they have sub strings in common. So, in this example, the strings 'b,c','a','a,c,d,e' should be merged

问题 I have a sample data: a=pd.DataFrame({'ACTIVITY':['b,c','a','a,c,d,e','f,g,h,i','j,k,l','k,l,m']}) What I want to do is merge some strings if they have sub strings in common. So, in this example, the strings 'b,c','a','a,c,d,e' should be merged together because they can be linked to each other. 'j,k,l' and 'k,l,m' should be in one group. In the end, I hope I can have something like: group 'b,c', 0 'a', 0 'a,c,d,e', 0 'f,g,h,i', 1 'j,k,l', 2 'k,l,m' 2 So, I can have three groups and there is

问题 if possible to convert a data frame to an object of class "dist" is it possible to do just the opposite? convert class "dist" to data frame? for example < dist(hasil) 1 2 3 4 2 0.088814413 3 0.084929382 0.030413813 4 0.063245553 0.029120440 0.044418465 5 0.061983869 0.027018512 0.036400549 0.009055385 and the result in data frame < col row distance 1 2 0.088814413 1 3 0.084929382 1 4 0.063245553 1 5 0.061983869 2 3 0.030413813 2 4 0.029120440 2 5 0.027018512 3 4 0.044418465 3 5 0.036400549 4

问题 I'm using my iPhone as an iBeacon device, and on the other side I have an Android 4.4.2 device scanning for the Bluetooth LE iBeacon signal from the iPhone. I searched for a good and easy way to calculate the distance between iBeacons and my Android phone, but I couldn't find anything that can help me with this. Could you help me on this matter? 回答1: We built a distance estimation formula into the Android Beacon Library of the form: d=A*(r/t)^B+C , where d is the distance in meters, r is the

问题 I'm using my iPhone as an iBeacon device, and on the other side I have an Android 4.4.2 device scanning for the Bluetooth LE iBeacon signal from the iPhone. I searched for a good and easy way to calculate the distance between iBeacons and my Android phone, but I couldn't find anything that can help me with this. Could you help me on this matter? 回答1: We built a distance estimation formula into the Android Beacon Library of the form: d=A*(r/t)^B+C , where d is the distance in meters, r is the

问题 I would like to know if there is any way to optimize the distance calculation process below. I left a small example below, however I am working with a spreadsheet with more than 6000 rows, and it takes considerable time to calculate the variable d. It would be possible to somehow adjust this to have the same results, but in an optimized way. library(rdist) library(tictoc) library(geosphere) time<-tic() df<-structure(list(Industries=c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19), Latitude

问题 I would like to know if there is any way to optimize the distance calculation process below. I left a small example below, however I am working with a spreadsheet with more than 6000 rows, and it takes considerable time to calculate the variable d. It would be possible to somehow adjust this to have the same results, but in an optimized way. library(rdist) library(tictoc) library(geosphere) time<-tic() df<-structure(list(Industries=c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19), Latitude

问题 Could you fully explain the big difference in using the distm function or the distVincentyEllipsoid function to calculate the distance of geodesic coordinates in R? I noticed that using distm for this calculation, it takes much longer. Could you please explain to me beyond the difference, why does this happen? Thank you! 回答1: Following on from your previous question here: Distance calculation optimization in R The speed relates to the level of computation required to produce the returned