distance

I want to calculate the distance between two points in Java

不问归期 提交于 2019-12-09 04:32:38
问题 OK, so I've written most of a program that will allow me to determine if two circles overlap. I have no problems whatsoever with my program aside from one issue: the program won't accept the code I've written for the distance between the two center points. I can figure out the if/else logic to tell the user what happens depending on the value of distance later, but I want to know what's wrong now. Eclipse, the program I'm coding on, is telling me that distance should be resolved to an array,

Efficiently calculating weighted distance in MATLAB

回眸只為那壹抹淺笑 提交于 2019-12-09 03:34:08
问题 Several posts exist about efficiently calculating pairwise distances in MATLAB. These posts tend to concern quickly calculating euclidean distance between large numbers of points. I need to create a function which quickly calculates the pairwise differences between smaller numbers of points (typically less than 1000 pairs). Within the grander scheme of the program i am writing, this function will be executed many thousands of times, so even small gains in efficiency are important. The

calculate distance between regression line and datapoint

感情迁移 提交于 2019-12-09 02:14:20
问题 I wonder if there is a way to calculate the distance between a abline in a plot and a datapoint? For example, what is the distance between concentration == 40 with signal == 643 (element 5) and the abline? concentration <- c(1,10,20,30,40,50) signal <- c(4, 22, 44, 244, 643, 1102) plot(concentration, signal) res <- lm(signal ~ concentration) abline(res) 回答1: You are basically asking for the residuals . R> residuals(res) 1 2 3 4 5 6 192.61 12.57 -185.48 -205.52 -26.57 212.39 As an aside, when

distance between two Shapes/Areas in Java?

蹲街弑〆低调 提交于 2019-12-08 21:38:28
问题 If I have two java.awt.geom.Area 's made out of the union of various simple Shapes (Polygons and Ellipses), is there a method out there to find the distance (i.e. closest distance) between the two Areas? To clarify: suppose I have two arbitrary Areas, each of which is created from the union of shapes of any sort: //Define the first area Area a = new Area(new Ellipse2D.Double(50, 50, 100, 100)); a.add(new Area(new Rectangle2D.Double(100, 100, 100, 100))); //Define the second area Area b = new

MATLAB function to calculate distance between two coordinates (latitude and longitude)

我们两清 提交于 2019-12-08 15:42:52
How can I calculate distance between two world map coordinates (latitude and longitude) using MATLAB R2015a (in meters)? If you don't have access to the MATLAB Mapping toolbox then a simple approximation is to use the Haversine formula. Here is an excerpt from the link: The haversine formula is an equation important in navigation, giving great-circle distances between two points on a sphere from their longitudes and latitudes. It is a special case of a more general formula in spherical trigonometry, the law of haversines, relating the sides and angles of spherical triangles. Here is a MATLAB

Unity3D - Get smooth speed and acceleration with GPS data

倾然丶 夕夏残阳落幕 提交于 2019-12-08 13:43:29
I'm using Unity3D and I created simple distance, speed and acceleration calculator using latitude and longitude of last position. I'm calculating last distance, speed and acceleration in each GPS update (approximately once per second). But sometimes (2-3 second interval) latitude and longitude values changes rapidly (in clear weather and no obstacles). That's why speed and acceleration values gets unreal results. For example, at stable 40 km/h speed, speed value becomes 60 km/h and returns to 40 km/h within 2-3 second. I'm here to ask how can I avoid this inaccurate and rapid GPS data changes?

levenshtein distance with items in list in python

99封情书 提交于 2019-12-08 11:42:58
问题 I have two list, below, and i want to compare if words that are similar levenshtein distance of less than 2. I have a function to find the levenshtein distance, however as parameters it needs the two words. I can find which words are not in the other list, but it is not helping. And I can go index by index but as in the case below when i get to index 7 (but and except) everything is thrown off because infidelity will be index 9 and 8 and wcop88 is 9 and 10 hence those won't be compare. Is

Error in onPictureTaken(), issue is cant converting RGB to GRAY, program stop running from cvtcolor() function.?

柔情痞子 提交于 2019-12-08 08:47:20
问题 Hey guys i m getting trouble with this function, this function is called after photo capturing and now i want to use data of image for distance transform. and count the exact number of objects i know where is problem but i cant solve it, I think problem is at Imgproc.cvtColor(m, mGray, Imgproc.COLOR_BGRA2GRAY) when i debug it program stop running at this point so please answer me if you found something; Thank you in advance @Override public void onPictureTaken(byte[] data, Camera camera) {

Calculate nearest point of KML polygon for iPhone app

女生的网名这么多〃 提交于 2019-12-08 08:41:21
问题 I have a series of nature reserves that need to be plotted, as polygon overlays, on a map using the coordinates contained within KML data. I’ve found a tutorial on the Apple website for displaying KML overlays on map instances. The problem is that the reserves vary in size greatly - from a small pond right up to several hundred kilometers in size. As a result I can’t use the coordinates of the center point to find the nearest reserves. Instead I need to calculate the nearest point of the

Angular 6 How to Get Distance between two location AGM

主宰稳场 提交于 2019-12-08 08:13:01
问题 I get Direction between two points using this reference https://www.npmjs.com/package/agm-direction Now I want to get/calculate distance between two location and I'm Confusing how's do it. In my Module AgmCoreModule.forRoot({ apiKey: 'My API Key....', libraries: ['geometry'] }) In my Component getDirection() { this.origin = { lat: this.pick_latitude, lng: this.pick_longitude } this.destination = { lat: this.drop_latitude, lng: this.drop_longitude } } My Question : How I get distance between