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问题 Is there any difference between with() and compact() ? Which one is more efficient ? 回答1: with() is a Laravel function and compact() is a PHP function and have totally different purposes. with() allows you to pass variables to a view and compact() creates an array from existing variables given as string arguments to it. See compact() for more info on this matter. 回答2: with() is a method made available by method from one of their classes while compact() is a method that is available by default

问题 I have to dataset, one with some location (lat,lon), that's test, and one with the lat/lon information of all zip codes in NYC, that's test2. test <- structure(list(trip_count = 1:10, dropoff_longitude = c(-73.959862, -73.882202, -73.934113, -73.992203, -74.00563, -73.975189, -73.97448, -73.974838, -73.981377, -73.955093), dropoff_latitude = c(40.773617, 40.744175, 40.715923, 40.749203, 40.726158, 40.729824, 40.763599, 40.754135, 40.759987, 40.765224)), row.names = c(NA, -10L), class = c("tbl

问题 I needed to access a Google's service, i.e. Google Analytics, from my Symfony 2 application, so I had to use the Google api client (version 2). Before accessing Google Analytics' info, I had to create either a api key, a client id or a service account in the Google API Console. At the end, I created a service account, and a file was downloaded. This file is used by the Google api client to grant access to my Google Analytics account and its respective collected info. My question are: What are

问题 How i can find the difference between two time stamps in minutes . for example:- timestamp1=2016-04-06 21:26:27 timestamp2=2016-04-07 09:06:02 difference = timestamp2-timestamp1 = 700 minutes (approx) 回答1: Using the datetime module: from datetime import datetime fmt = '%Y-%m-%d %H:%M:%S' tstamp1 = datetime.strptime('2016-04-06 21:26:27', fmt) tstamp2 = datetime.strptime('2016-04-07 09:06:02', fmt) if tstamp1 > tstamp2: td = tstamp1 - tstamp2 else: td = tstamp2 - tstamp1 td_mins = int(round(td

问题 How i can find the difference between two time stamps in minutes . for example:- timestamp1=2016-04-06 21:26:27 timestamp2=2016-04-07 09:06:02 difference = timestamp2-timestamp1 = 700 minutes (approx) 回答1: Using the datetime module: from datetime import datetime fmt = '%Y-%m-%d %H:%M:%S' tstamp1 = datetime.strptime('2016-04-06 21:26:27', fmt) tstamp2 = datetime.strptime('2016-04-07 09:06:02', fmt) if tstamp1 > tstamp2: td = tstamp1 - tstamp2 else: td = tstamp2 - tstamp1 td_mins = int(round(td

问题 This question already has answers here : Calculate Pandas DataFrame Time Difference Between Two Columns in Hours and Minutes (3 answers) Closed 6 months ago . I have two df columns with string values: df['starttime'] df['endtime'] 0 2015-10-06 18:35:33 0 2015-10-06 18:35:58 1 2015-10-08 17:51:21.999000 1 2015-10-08 17:52:10 2 2015-10-08 20:51:55.999000 2 2015-10-08 20:52:21 3 2015-10-05 15:16:49.999000 3 2015-10-05 15:17:00 4 2015-10-05 15:16:53.999000 4 2015-10-05 15:17:22 5 2015-10-05 15:17

问题 This question already has answers here : Calculate Pandas DataFrame Time Difference Between Two Columns in Hours and Minutes (3 answers) Closed 6 months ago . I have two df columns with string values: df['starttime'] df['endtime'] 0 2015-10-06 18:35:33 0 2015-10-06 18:35:58 1 2015-10-08 17:51:21.999000 1 2015-10-08 17:52:10 2 2015-10-08 20:51:55.999000 2 2015-10-08 20:52:21 3 2015-10-05 15:16:49.999000 3 2015-10-05 15:17:00 4 2015-10-05 15:16:53.999000 4 2015-10-05 15:17:22 5 2015-10-05 15:17

问题 This question already has answers here : Calculate Pandas DataFrame Time Difference Between Two Columns in Hours and Minutes (3 answers) Closed 6 months ago . I have two df columns with string values: df['starttime'] df['endtime'] 0 2015-10-06 18:35:33 0 2015-10-06 18:35:58 1 2015-10-08 17:51:21.999000 1 2015-10-08 17:52:10 2 2015-10-08 20:51:55.999000 2 2015-10-08 20:52:21 3 2015-10-05 15:16:49.999000 3 2015-10-05 15:17:00 4 2015-10-05 15:16:53.999000 4 2015-10-05 15:17:22 5 2015-10-05 15:17

问题 df have id measure t1 t2 t3 1 savings 1 2 5 1 income 10 15 14 1 misc 5 5 5 2 savings 3 6 12 2 income 4 20 80 2 misc 1 1 1 df want- add a new row to the measure for each id, called spend, calculated by subtracting measure=income - measure=savings, for each of the periods t1,t2,t3, for each id id measure t1 t2 t3 1 savings 1 2 5 1 income 10 15 14 1 misc 5 5 5 1 spend 9 13 9 2 savings 3 6 12 2 income 4 20 80 2 misc 1 1 1 2 spend 1 14 68 Trying: df.loc[df['Measure'] == 'spend'] = df.loc[df[

问题 df have id measure t1 t2 t3 1 savings 1 2 5 1 income 10 15 14 1 misc 5 5 5 2 savings 3 6 12 2 income 4 20 80 2 misc 1 1 1 df want- add a new row to the measure for each id, called spend, calculated by subtracting measure=income - measure=savings, for each of the periods t1,t2,t3, for each id id measure t1 t2 t3 1 savings 1 2 5 1 income 10 15 14 1 misc 5 5 5 1 spend 9 13 9 2 savings 3 6 12 2 income 4 20 80 2 misc 1 1 1 2 spend 1 14 68 Trying: df.loc[df['Measure'] == 'spend'] = df.loc[df[