designer

Custom Designer for a Control

北城以北 提交于 2019-11-30 07:24:50
I've got a custom class which derives from SplitContainer: namespace Builder.Components { public partial class ProjectSidebar : SplitContainer { public ProjectSidebar() { InitializeComponent(); } } } Now when I right-click and select View Designer I'd like to see the SplitContainer and edit it, like I would with the default controls (drop a panel in it, etc.). All I see is a message to add controls and switch to Code view . How to achieve this? Jeff Yates In order to add design-time functionality like additional operations (known as Action Lists and Verbs depending on how they are provided),

What's the purpose of the components IContainer generated by the Winforms designer?

这一生的挚爱 提交于 2019-11-30 04:45:25
When you create a new form in Visual Studio, the designer generates the following code in the .Designer.cs file: /// <summary> /// Required designer variable. /// </summary> private System.ComponentModel.IContainer components = null; /// <summary> /// Clean up any resources being used. /// </summary> /// <param name="disposing">true if managed resources should be disposed; otherwise, false.</param> protected override void Dispose(bool disposing) { if (disposing && (components != null)) { components.Dispose(); } base.Dispose(disposing); } What is the purpose of the components variable? My

How can I find a control looking at windows designer in visual studio 2012?

让人想犯罪 __ 提交于 2019-11-30 02:58:41
问题 I have very old code with a lot of controls. On code behind I can find the name of the control. Now I would like easily by it's name find the placement of it on designer view in Visual Studio (or other tool). Is there any possibility to do it? No list on mine VS: 回答1: Use the document outline pane ( Ctrl + Alt + T ) which will include searching a little in the document tree, or the ComboBox in the top of properties pane, which is sorted alphabetically. Screenshot of ComboBox of properties

Visual studio 2012 XAML designer invalid markup

别等时光非礼了梦想. 提交于 2019-11-30 01:47:43
I've got a project that contains usercontrols. For some reason, the design view for the window which uses the said controls has stopped functioning and insists on "Invalid Markup" - the error given is that some members of the usercontrols are not recognized or not accessible. The project however compiles and executes just fine. Loading it up in VS2010, the editor works fine, no errors whatsoever - the same even in Expression Blend. So far I have tried the typical clean, rebuild, manually deleting stuff from obj, updating the .xaml and rebuilding, tried starting VS2012 with /resetuserdata and

Design-time-only background color in WPF?

拥有回忆 提交于 2019-11-29 22:57:53
In WPF XAML there is the convenient DesignHeight and DesignWidth , for instance in code as <UserControl ... d:DesignHeight="500" d:DesignWidth="500" ... /> which is great because I can build the layout with a representative , but not locked-in , control size. However, I'm often building dark UIs, where labels and so forth need to be white, but my controls still need a transparent background color. This creates a design-time inconvenience because white seems to be the default background color for transparent controls in the designer, leading to unreadable white-on-white labels. Is there a way

How do I enable phpMyAdmin's Designer view?

谁都会走 提交于 2019-11-29 22:15:51
I am running phpMyAdmin locally and I am trying to enable the Designer tool. How do you enable designer view for phpMyAdmin? I have read quite a few tutorials on how to enable the Designer view for phpMyAdmin and they all have different directions that never seem to actually get it working. I am using version 4.0.7 The following steps will enable the Designer in phpMyAdmin 4+ assuming that phpMyAdmin is inside the folder phpMyAdmin : Open phpMyAdmin/config.inc.php and phpMyAdmin/config.sample.inc.php . Locate the phpMyAdmin configuration storage settings in config.sample.inc.php (lines 38-66

SQLite 1.0.82.0 (latest) in Visual Studio 2012 not showing in Designer Data Source

你说的曾经没有我的故事 提交于 2019-11-29 21:13:59
问题 I am using the latest version, 1.0.82.0 (sqlite-netFx40-setup-bundle-x86-2010-1.0.82.0.exe), and am using the released version of Visual Studio 2012 with all the latest everything. I do not see the SQLite in the Designer Data Source in Source Explorer (new Connections). The download on SQLite states, "This setup package is capable of installing the design-time components for Visual Studio 2010". I presume the "Visual Studio 2010" part is why I do not see the designer in VS2012, which is what

How to change background color of XAML designer in vs2012?

◇◆丶佛笑我妖孽 提交于 2019-11-29 20:25:36
I just try to view the result after XAML code in Designer. However, it's hard to recognize the black letters when I use a dark theme in vs2012. My question is how to change designer background to white color without modifying the dark theme. Seems to change several options in tools? Thanks Please skim over all the answers . All have different approaches and it may be that the later ones will suit your needs better. VisualStudioEspresso In VS 2013 you can change XAML designer background. Go to: Tools -> Options -> Environment -> Fonts and Colors In the combobox at the top of the panel, select:

XAML Designer Window won't load for “Universal Windows” app - even in new project

拈花ヽ惹草 提交于 2019-11-29 17:36:35
I seem to recall running into this before but can't for the life of me recall how I got around it and no depth of Googleing seems to help. Here's the problem: When I open VS2015 (Community version) with a "Universal Windows" project, new or old, even without changing a single thing, I get an Exception in the designer window. The XAML code shows up fine, but the designer window gives me "error 0X80070005: While processing the request, the system failed to register the windows.capability extension due to the following error: Access is denied." This is followed by a wall of text I'll include

How do I stop my ViewModel code from running in the designer?

為{幸葍}努か 提交于 2019-11-29 17:11:59
问题 I'm developing a networked WPF application with the MVVM pattern and it seems that it's running and connecting to servers in the designer. I know about the IsInDesignMode property, but I'm not sure how to access it in a ViewModel. 回答1: DependencyObject dep = new DependencyObject(); if (DesignerProperties.GetIsInDesignMode(dep)) { ... } 回答2: Just to add to these suggestions, you probably want to optimize for production deployment. If you need to check the design mode in the ViewModel, you