derived-class

this thread was started here but due to lack of an altogether good example (and in order to avoid delete all that question) it is re-written here. So, in the following example, the void cppthread::ThreadedFunc() gets spawned to execute as a separate thread . Instead I would prefer void ThreadedWrite::ThreadedFunc() to be executed. How can I do that? (some more details follow after the code) cppthread.hpp #ifndef CPPTHREAD_HPP #define CPPTHREAD_HPP #include <pthread.h> using namespace std; class cppthread { public: cppthread(); virtual ~cppthread(); virtual void threadedFunc(); ///parentObj (ie

I am trying to implement good design patterns for a program I am writing. I have a class structure like this. abstract class SomeBase { public SomeObject obj { get; protected set; } protected SomeBase(SomeObject x) { obj = x; } //Other methods and fields... } public class SomeDerived : SomeBase { public SomeDerived() : base(new SomeObject(this)) { } } Now as I;m sure you now, you can't pass this in a contructor because the object hasn't bee initialized. But I was really hoping there was a workaround. It's not best practice for me to allow SomeDerived() to handle the setting of a base classes

How do we call a virtual method from another method in the base class even when the current instance is of a derived-class? I know we can call Method2 in the Base class from a method in the Derived class by using base.Method2() but what I want to do is calling it from the other virtual method in the Base class. Is it possible? using System; namespace ConsoleApplication1 { class Program { static void Main( string[] args ) { Base b = new Derived( ); b.Method1( ); } } public class Base { public virtual void Method1() { Console.WriteLine("Method1 in Base class."); this.Method2( ); // I want this

Going under the assumption that there is a legitimate reason for preventing derivation from some class, Bjarne gives a solution here for the answer to "Can I stop people deriving from my class?" However, I thought of: class final { protected: final() { } // line 3 }; class B : private virtual final { }; class D : public B { // line 9 }; int main() { B b; D d; // line 14 } When trying to compile, one gets: foo.cpp: In constructor ‘D::D()’: foo.cpp:3: error: ‘final::final()’ is protected foo.cpp:9: error: within this context foo.cpp: In function ‘int main()’: foo.cpp:14: note: synthesized method

I have a constant int variable in my base class, and I would like to initialize responding one in my derived class, with different value (taken as a parameter), is this possible? Here's what I did: // Base.h (methods implemented in Base.cpp in the actual code) class Base { public: Base(const int index) : m_index(index) {} int getIndex() const { return m_index; } private: const int m_index; }; // Derived.h class Derived : public Base { public: Derived(const int index, const std::string name) : m_name(name) {} void setName(const std::string name) { m_name = name; } std::string getName() const {

Why is this not possible? I get the following compiler-error when instantiating "DerivedClass" with a constructor-parameter: 'GenericParameterizedConstructor.DerivedClass' does not contain a constructor that takes 1 argument But calling a very similar method works. Why? class Program { static void Main(string[] args) { // This one produces a compile error // DerivedClass cls = new DerivedClass("Some value"); // This one works; DerivedClass cls2 = new DerivedClass(); cls2.SomeMethod("Some value"); } } public class BaseClass<T> { internal T Value; public BaseClass() { } public BaseClass(T value)