definition

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . I want to create a procedure to clone SQL Server database using T-SQL . I'm using cursors to clone objects (tables, procedures, functions ,...). How can i get user-defined-table-type definition from System Catalog Views ? 回答1: Here is your answer. Below query gives the result of all types as a text. You can

问题 So this section of the standard gives this example (My questions are inline): template<class T, class U> struct Outer { template<class X, class Y> struct Inner; // Where are X and Y from? Is this defining a struct? template<class Y> struct Inner<T, Y>; // Is this defining a struct specialization? If so what is Y? template<class Y> struct Inner<T, Y> { }; // I feel like this is a redefinition of the line above, could it ever not be? template<class Y> struct Inner<U, Y> { }; }; Admittedly I can

问题 I'm still very new to Haskell, and I'm curious as to how I would merge two Hand 's together, so that, the first hand is placed on top of the second hand. I want it to be an infix operator, namely (<+). Here's some code to assist you. I keep getting an error saying "The type signature for ‘<+’ lacks an accompanying binding". data Rank = Numeric Integer | Jack | Queen | King | Ace data Suit = Hearts | Spades | Diamonds | Clubs data Card = Card Rank Suit data Hand = Empty | Add Card Hand (<+) ::

问题 Just started with K & R and on the 2nd chapter, there is the line: Declarations list the variables to be used and state what type they have and perhaps what their initial values are . So: int x = 42 is a definition . and int x is a declaration but also a definition since every definition is a declaration . But when we assign an intial value like K & R say, doesn't that make the declaration a definition ? 回答1: You confuse two things: A declaration states ( declares ) what an object's* type,

问题 As an example, say I have a variable defined where there may be multiple from __ import * from ____ import * etc. Is there a way to figure out where one of the variables in the namespace is defined? edit Thanks, but I already understand that import * is often considered poor form. That wasn't the question though, and in any case I didn't write it. It'd just be nice to have a way to find where the variable came from. 回答1: This is why it is considered bad form to use from __ import * in python

问题 Why is it that: Function definitions can use definitions defined after it while variable definitions can't. For example, a) the following code snippet is wrong: ; Must define function `f` before variable `a`. #lang racket (define a (f)) (define (f) 10) b) While the following snippet is right: ; Function `g` could be defined after function `f`. #lang racket (define (f) (g)) ; `g` is not defined yet (define (g) 10) c) Right too : ; Variable `a` could be defined after function `f` #lang racket

问题 I think this is not possible, but maybe I'm wrong. So I ask you, if it is possible. ;-) If I define a annotation that accept only class references which extends some interface or class that is possible: Class<? extends ServiceProviderIF> serviceIFProvider(); At this annotation I only can add some class which extends ServiceProviderIF. My question: is such a definition also possible for another annotation? That means with pseudocode something like this Class<? contains AnnotationXYZ>

问题 What is the difference between the code snippets labeled "version 1" and "version 2" in the following code section: int main() { using namespace std; typedef istream_iterator<int> input; // version 1) //vector<int> v(input(cin), input()); // version 2) input endofinput; vector<int> v(input(cin), endofinput); } As far as I understand "version 1" is treated as function declaration. But I don't understand why nor what the arguments of the resulting function v with return type vector<int> are.

问题 If definition stands for assigning memory. How come a class definition in C++ has no memory assigned until an object is instantiated. 回答1: C++ Class definitions do not assign memory. class is like typedef and struct . Where did you get the idea that "definition stands for assigning memory"? Can you provide a quote or reference? C++ Object creation (via new ) assigns memory. 回答2: The class definition gets compiled down into code. That code is part of the process image. The process image does

问题 I'd like to know what this code means in Scheme: (define ((K x) y) x) (define (((S x) y) z) ((x z) (y z))) The whole file is here. Is this legal Scheme? Is (K x) a parametrized function, something like generic functions in Java? I looked up the MIT Scheme reference, there seems to be nothing mentioned for definition of this kind. 回答1: Trying it in MIT Scheme works (define ((K x) y) x) ;Value: k ((k 3) 4) ;Value: 3 Apparently, these are the definitions for K and S combinators from a