definition

问题 I am new to CUDA programming and don't know much about it. Can you please tell me what does 'CUDA compute capability' mean? When I use the following code on my university server, it showed me the following result. for (device = 0; device < deviceCount; ++device) { cudaDeviceProp deviceProp; cudaGetDeviceProperties(&deviceProp, device); printf("\nDevice %d has compute capability %d.%d.\n", device, deviceProp.major, deviceProp.minor); } RESULT: Device 0 has compute capability 4199672.0. Device

问题 I am new to CUDA programming and don't know much about it. Can you please tell me what does 'CUDA compute capability' mean? When I use the following code on my university server, it showed me the following result. for (device = 0; device < deviceCount; ++device) { cudaDeviceProp deviceProp; cudaGetDeviceProperties(&deviceProp, device); printf("\nDevice %d has compute capability %d.%d.\n", device, deviceProp.major, deviceProp.minor); } RESULT: Device 0 has compute capability 4199672.0. Device

问题 I came across the following problem while reading ...just cant get the logic behind this. auto int c; static int c; register int c; extern int c; It is given that the first three are definition and last one is declaration ..how come ? 回答1: The last one with extern does not define storage for c . It merely indicates that c exists somewhere and the linker should be able to resolve it to some global c defined elsewhere. If you compiled and linked a single .c file and tried to use the last c you

问题 I came across the following problem while reading ...just cant get the logic behind this. auto int c; static int c; register int c; extern int c; It is given that the first three are definition and last one is declaration ..how come ? 回答1: The last one with extern does not define storage for c . It merely indicates that c exists somewhere and the linker should be able to resolve it to some global c defined elsewhere. If you compiled and linked a single .c file and tried to use the last c you

来源： https://stackoverflow.com/questions/59707065/what-are-symbolic-tensors-in-tensorflow-and-keras

来源： https://stackoverflow.com/questions/59707065/what-are-symbolic-tensors-in-tensorflow-and-keras

来源： https://stackoverflow.com/questions/63886000/why-cant-round-bracket-be-correctly-regarded-as-a-constructor-calling

问题 While reading some groovy code of another developer I encountered the following definition: def foo=[:] What does it mean? 回答1: [:] is shorthand notation for creating a Map. You can also add keys and values to it: def foo = [bar: 'baz'] 回答2: [:] creates an empty Map. The colon is there to distinguish it from [] , which creates an empty List. This groovy code: def foo = [:] is roughly equivalent to this java code: Object foo = new java.util.LinkedHashMap(); 回答3: Quoting the doc: Notice that [:

问题 I am making a simple definition to return a list of colors based on some intervals. Unfortunately I keep getting the following error: ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all(). I have seen the following discussion on stackoverflow but only had failed attempts to make it work. Truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all() This is my code: y = 5 std = pd.Series([1,1,1,1]) values = pd

问题 I am making a simple definition to return a list of colors based on some intervals. Unfortunately I keep getting the following error: ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all(). I have seen the following discussion on stackoverflow but only had failed attempts to make it work. Truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all() This is my code: y = 5 std = pd.Series([1,1,1,1]) values = pd