declaration

Automatically separate class definitions from declarations?

痞子三分冷 提交于 2019-12-18 07:05:02
问题 I am using a library that consists almost entirely of templated classes and functions in header files , like this: // foo.h template<class T> class Foo { Foo(){} void computeXYZ() { /* heavy code */ } }; template<class T> void processFoo(const Foo<T>& foo) { /* more heavy code */ } Now this is bad because compile times are unbearable whenever I include one of those header files (and actually I include many of them in each of my compilation units). Since as a template parameter I only use one

Declaration rule in struct typedef

送分小仙女□ 提交于 2019-12-18 06:09:57
问题 I'm reading 'The C Programming Language' and encountered a problem about typedef of struct . The code is like this: typedef struct tnode *Treeptr; typedef struct tnode { /* the tree node: */ char *word; /* points to the text */ int count; /* number of occurrences */ struct tnode *left; /* left child */ struct tnode *right; /* right child */ } Treenode; By the time we write typedef struct tnode *Treeptr; tnode is still not declared yet, but we don't get any compilation error, but when we

Declaration rule in struct typedef

好久不见. 提交于 2019-12-18 06:09:34
问题 I'm reading 'The C Programming Language' and encountered a problem about typedef of struct . The code is like this: typedef struct tnode *Treeptr; typedef struct tnode { /* the tree node: */ char *word; /* points to the text */ int count; /* number of occurrences */ struct tnode *left; /* left child */ struct tnode *right; /* right child */ } Treenode; By the time we write typedef struct tnode *Treeptr; tnode is still not declared yet, but we don't get any compilation error, but when we

Generics wildcard instantiation

六眼飞鱼酱① 提交于 2019-12-18 06:08:25
问题 I was reviewing someone else's code the other day and I came across a line that raised some concern. To simplify, say I have a generic Class A and an abstract Class B. Is the following instantiation allowed and if so, why? Object obj = new A<? extends B>(); I personally have never seen an instantiation like the above, although a declaration such as A<? extends B> obj = null; would certainly hold. I've always used the wildcard in generics to declare method parameters, so I may just not have

Syntax - what does square brackets around a variable declaration mean [duplicate]

∥☆過路亽.° 提交于 2019-12-18 05:57:28
问题 This question already has answers here : Multiple assignment in javascript? What does [a,b,c] = [1, 2, 3]; mean? (4 answers) Closed 2 years ago . Take the following line of code const [component] = router.getMatchedComponents({ ...to }) Could anyone advise what the square brackets around component means here? I have tried to google this but struggling to find an answer 回答1: It's called Destructuring assignment, and it's used to unpack the values of an array and assign them to new variables.

Where can I legally declare a variable in C99?

陌路散爱 提交于 2019-12-18 05:27:06
问题 When I was first introduced to C I was told to always declare my variables at the top of the function. Now that I have a strong grasp of the language I am focusing my efforts on coding style, particularly limiting the scope of my variables. I have read about the benefits to limiting the scope and I came across an interesting example. Apparently, C99 allows you to do this... for (int i = 0; i < 10; i++) { puts("hello"); } I had thought that a variables scope was limited by the inner-most

Scope of declarations in the body of a do-while statement

你说的曾经没有我的故事 提交于 2019-12-18 04:50:55
问题 In Why can't you declare a variable inside a do while loop? the OP asks why a declaration in the while-condition of a do-while loop isn't in scope in the do-statement. That would be very unnatural as C/C++ generally follow a "declaration-at-top-of-scope" pattern. But what about the converse - why not extend the scope of any declaration in the do-statement to the while-condition. That would allow int i; do { i = get_data(); // whatever you want to do with i; } while (i != 0); to be shortened

where is stdin defined in c standard library?

℡╲_俬逩灬. 提交于 2019-12-18 04:45:17
问题 I found this line in stdio.h : extern struct _IO_FILE *stdin; Based on this 'extern' keyword, i assume this is just a declaration. I wonder where is stdin defined and initialized? 回答1: It's defined in the source code of your C library. You typically only need the headers for compilation, but you can find the source code for many open-source standard libraries (like glibc). In glibc, it's defined in libio/stdio.c as like this: _IO_FILE *stdin = (FILE *) &_IO_2_1_stdin_; Which is in turn

How to Access String Variable in One View Controller to Another view Controller

依然范特西╮ 提交于 2019-12-18 04:23:27
问题 I am new to iphone development, Now i want to access the string variable in all the view controller, but i know to declare the variables in delegate method, but i cant access it, please help me out. Mainviewcontroller-->Viewcontroller1_-->viewcontroller2-->viewcontroller3-->subwebview. i have created one main view controller and the subview class are Viewcontroller1,viewcontroller2,viewcontroller3. And the subwebview is the subclass of all the three viewcontrollers(Viewcontroller1

Objective C: Why do we declare ivars in the .h member area if @property seems to do it automatically?

夙愿已清 提交于 2019-12-18 04:01:30
问题 In implementing an interface it seems the common method in tutorials and literature is to declare an ivar and then set the @property then @synthesize . @interface MyClass : NSObject { NSString *myString; } @property (nonatomic, retain) NSString *myString; @end However, omitting the explicit declaration and just putting @property has the same effect. @interface MyClass: NSObject { } @property (nonatomic, retain) NSString *myString; @end So how come most people use @property and an explicit