datetime

问题 I’ve discovered this morning that bulk of timestamp formats in R seem to be posix.ct class based, which seems to be risky for use with nano second timestamps due to rounding and accumulation errors. Is this true? If so, What packages and processing steps are needed to safely import timestamps in nano seconds precision - probably from csv files? (Preferably staying with packages within tidyverse) Output Visual tools used currently are ggplot2 , plotly, and d3 回答1: We wrote a package for that:

问题 I’ve discovered this morning that bulk of timestamp formats in R seem to be posix.ct class based, which seems to be risky for use with nano second timestamps due to rounding and accumulation errors. Is this true? If so, What packages and processing steps are needed to safely import timestamps in nano seconds precision - probably from csv files? (Preferably staying with packages within tidyverse) Output Visual tools used currently are ggplot2 , plotly, and d3 回答1: We wrote a package for that:

问题 I have the below data. I need to fill in the data for the remaining months I need only the first day [day one] of the month to be filled in. Wherever there is no data, I need the value to be filled with '0'. For example below is the existing data uname month_first msg_count 0 ArtCort0324 2017-06-01 9 I need output in below way. 回答1: Create a multiindex from combination of unman and date range and reindex the data df.month_first = pd.to_datetime(df.month_first) dates = pd.date_range(datetime

问题 I've been struggling to convert two columns in a pandas. The frame contains many columns, and 2 columns with dates: 'datelog'(is a date) and 'Timeofday' (is a time). The column datelog is a string. The column Timeofday is a datetime.time() format. The dateframe display is as folows: datelog Timeofday 0 30-APR-15 14:15:43 1 30-APR-15 14:16:13 2 30-APR-15 14:16:43 3 30-APR-15 14:17:13 4 30-APR-15 14:17:43 5 30-APR-15 14:18:13 6 30-APR-15 14:18:43 7 30-APR-15 14:19:13 8 30-APR-15 14:19:43 9 30

问题 I've been struggling to convert two columns in a pandas. The frame contains many columns, and 2 columns with dates: 'datelog'(is a date) and 'Timeofday' (is a time). The column datelog is a string. The column Timeofday is a datetime.time() format. The dateframe display is as folows: datelog Timeofday 0 30-APR-15 14:15:43 1 30-APR-15 14:16:13 2 30-APR-15 14:16:43 3 30-APR-15 14:17:13 4 30-APR-15 14:17:43 5 30-APR-15 14:18:13 6 30-APR-15 14:18:43 7 30-APR-15 14:19:13 8 30-APR-15 14:19:43 9 30

问题 I am trying to convert the string to Date like the following: val inputFormat = SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss", Locale.getDefault()) val s = "Mon, 14 Oct 2019 07:10:28" val time = inputFormat.parse(s) Log.d("HttpTools", "time server:$time") But it show the error java.text.ParseException: Unparseable date: "Mon, 14 Oct 2019 07:10:28" Did I missing something ? Thanks in advance. 回答1: Use this format: EEE, dd MMM yyyy hh:mm:ss 回答2: The format is wrong. According to the

问题 I have the following table structure that has day wise shifts. At only C shift, time is shared by two days. As you can C Shift starts at 20:30 and ends the next's days 06:00 . The Table structure and data as follows create table `machine_shifts` ( `date` date , `shift_start_time` time , `shift_end_time` time , `shift` varchar (60), `updated_on` timestamp ); insert into `machine_shifts` (`date`, `shift_start_time`, `shift_end_time`, `shift`, `updated_on`) values('2010-01-01','06:00:00','14:30

问题 I have the following table structure that has day wise shifts. At only C shift, time is shared by two days. As you can C Shift starts at 20:30 and ends the next's days 06:00 . The Table structure and data as follows create table `machine_shifts` ( `date` date , `shift_start_time` time , `shift_end_time` time , `shift` varchar (60), `updated_on` timestamp ); insert into `machine_shifts` (`date`, `shift_start_time`, `shift_end_time`, `shift`, `updated_on`) values('2010-01-01','06:00:00','14:30

问题 I have the following table structure that has day wise shifts. At only C shift, time is shared by two days. As you can C Shift starts at 20:30 and ends the next's days 06:00 . The Table structure and data as follows create table `machine_shifts` ( `date` date , `shift_start_time` time , `shift_end_time` time , `shift` varchar (60), `updated_on` timestamp ); insert into `machine_shifts` (`date`, `shift_start_time`, `shift_end_time`, `shift`, `updated_on`) values('2010-01-01','06:00:00','14:30

问题 I want to subtract 5.30 hours from a date, for example, I have a date: Fri Jan 15 2016 00:00:00 after subtraction, it should be something like, Thu Jan 14 2016 19:30:00 How I can achieve this. Any help will be appreciated. 回答1: try var date = new Date("Fri Jan 15 2016 00:00:00"); date.setHours(date.getHours()-5); date.setMinutes(date.getMinutes()-30); 来源： https://stackoverflow.com/questions/35450110/want-to-substract-5-30-hours-from-a-date-javascript