datetime-format

问题 This question already has answers here : Java LocalDate Formatting of 2000-1-2 error [duplicate] (2 answers) Closed 2 years ago . DateTimeFormatter is not giving correct format for Dec 30 and 31 2018 as per following snippet. final String DATE_FORMAT = "YYYYMM"; DateTimeFormatter dateFormat = DateTimeFormatter.ofPattern(DATE_FORMAT); LocalDateTime startDate = LocalDateTime.of(2018,12,29,5,0,0); System.out.println(startDate.format(dateFormat)); //prints 201812 LocalDateTime startDate =

问题 After asking [How to parse 🎌 Japanese Era Date string values into LocalDate & LocalDateTime], I was curious about the following case; 明治二十三年十一月二十九日 Is there a way to parse Japanese numbers on top of Japanese Calendar characters, essentially a pure Japanese date, into LocalDate ? Using only Java DateTime API. I don't want to modify the input String values, but want just API to handle the recognition. 回答1: For anyone reading along, your example date string holds an era designator, year of era

问题 After asking [How to parse 🎌 Japanese Era Date string values into LocalDate & LocalDateTime], I was curious about the following case; 明治二十三年十一月二十九日 Is there a way to parse Japanese numbers on top of Japanese Calendar characters, essentially a pure Japanese date, into LocalDate ? Using only Java DateTime API. I don't want to modify the input String values, but want just API to handle the recognition. 回答1: For anyone reading along, your example date string holds an era designator, year of era

问题 String s = "2020 Jun 31"; DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy MMM dd"); LocalDate date = LocalDate.parse(s, formatter); System.out.println(date); Output: 2020-06-30 Why does 31 turn into 30 without any warnings or exceptions? 回答1: DateTimeFormatter has a ResolverStyle that affects how strict or lenient the parser should be with invalid date and time values. To get an exception in this case you need to set the resolver style to STRICT. You also need to use u (year)

问题 I am trying to parse date string with format "HHmmssZ", OffsetTime.parse("115601Z", DateTimeFormatter.ofPattern("HHmmssZ")).toLocalTime() when i test it i get the exception : java.time.format.DateTimeParseException: Text '112322Z' could not be parsed at index 6 at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1949) at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1851) at java.time.OffsetTime.parse(OffsetTime.java:327) 回答1: All the following will

问题 I am trying to parse date string with format "HHmmssZ", OffsetTime.parse("115601Z", DateTimeFormatter.ofPattern("HHmmssZ")).toLocalTime() when i test it i get the exception : java.time.format.DateTimeParseException: Text '112322Z' could not be parsed at index 6 at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1949) at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1851) at java.time.OffsetTime.parse(OffsetTime.java:327) 回答1: All the following will

问题 I have a LocalDate object but i am struggling to find the pattern programatically using the DateTimeFormatter class in Java 8. Is there a way to do it or any 3rd party library for this? I have tried the following but I do not want to use DateFormat class as this is not recommended. LocalDateTime.parse("8/22/19 4:39 PM").format(DateTimeFormatter.ofPattern(pattern1).withLocale(Locale.getDefault())) "Prints this which is what i kind of want -> M/d/yy h:mm a (I really want 'mm/dd/yyyy h:mm')

问题 I am parsing dates like this: "Sat, 30 Jan 2016 00:03:00 +0300" But in some of the dates it throw me this exception: Caused by: java.time.DateTimeException: Conflict found: Field DayOfWeek 6 differs from DayOfWeek 2 derived from 2016-01-30 or this: java.time.format.DateTimeParseException: Text 'Tue, 30 Jan 2016 00:06:00 +0300' could not be parsed: Conflict found: Field DayOfWeek 6 differs from DayOfWeek 2 derived from 2016-01-30 Here is some of my code: DateTimeFormatter newformatter =

问题 I was using this line to set the datetime defaults. DateTimeSerializationOptions.Defaults = DateTimeSerializationOptions.LocalInstance; I get this warning. 'MongoDB.Bson.Serialization.Options.DateTimeSerializationOptions.Defaults' is obsolete: 'Create and register a DateTimeSerializer with the desired options instead. ' But i couldn't find an example to change it... how can I change this obsolute usage? 回答1: Register the date/time serializer like this: BsonSerializer.RegisterSerializer(typeof

问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 1 year ago . Improve this question I have string in next format: 2017-02-14T09:51:46.000-0600 What is the best approach to parse and convert string into timestamp? I have options to use regular expression or to write my own function for parsing, but are there any builtin methods which can