date

Function to convert PHP date format to Javascript date format (not the date itself !)

由 佐手、 提交于 2020-12-21 03:54:16
问题 I am looking for easy way to convert PHP date format (i.e. Y-m-d H:i:s) to javascript date format (respectively YYYY-mm-dd HH:mm:ss). I don't want to convert the date (there are already answers for this question), I am looking for tool/function to convert the format code (which I don't know yet, as it is defined by the user in application). User can define it in different ways defined by PHP date() i.e. 'Y/m/d H:i' or 'Y-d-m H-i' and I need to use the same format when displaying date in

Function to convert PHP date format to Javascript date format (not the date itself !)

由 邮差的信 提交于 2020-12-21 03:54:05
问题 I am looking for easy way to convert PHP date format (i.e. Y-m-d H:i:s) to javascript date format (respectively YYYY-mm-dd HH:mm:ss). I don't want to convert the date (there are already answers for this question), I am looking for tool/function to convert the format code (which I don't know yet, as it is defined by the user in application). User can define it in different ways defined by PHP date() i.e. 'Y/m/d H:i' or 'Y-d-m H-i' and I need to use the same format when displaying date in

Function to convert PHP date format to Javascript date format (not the date itself !)

由 我只是一个虾纸丫 提交于 2020-12-21 03:53:39
问题 I am looking for easy way to convert PHP date format (i.e. Y-m-d H:i:s) to javascript date format (respectively YYYY-mm-dd HH:mm:ss). I don't want to convert the date (there are already answers for this question), I am looking for tool/function to convert the format code (which I don't know yet, as it is defined by the user in application). User can define it in different ways defined by PHP date() i.e. 'Y/m/d H:i' or 'Y-d-m H-i' and I need to use the same format when displaying date in

How to make MySQL use functional index on a datetime column?

由 我的未来我决定 提交于 2020-12-16 02:23:05
问题 Say I'm running MySQL 8 with a table data containing about 1M rows. And I want to filter a datetime column on date a range (using a date index). CREATE TABLE `data` ( `rowId` int NOT NULL AUTO_INCREMENT, `data` json NOT NULL, `created` DATETIME NOT NULL, -- <-- datetime column for a date index `created_date` DATE AS (cast(`created` as date)) NOT NULL, -- <-- generated date column PRIMARY KEY (`rowId`), INDEX (`created`), -- <-- datetime index w/ cardinality ~ 1M INDEX (`created_date`) -- <--

How to make MySQL use functional index on a datetime column?

由 帅比萌擦擦* 提交于 2020-12-16 02:19:24
问题 Say I'm running MySQL 8 with a table data containing about 1M rows. And I want to filter a datetime column on date a range (using a date index). CREATE TABLE `data` ( `rowId` int NOT NULL AUTO_INCREMENT, `data` json NOT NULL, `created` DATETIME NOT NULL, -- <-- datetime column for a date index `created_date` DATE AS (cast(`created` as date)) NOT NULL, -- <-- generated date column PRIMARY KEY (`rowId`), INDEX (`created`), -- <-- datetime index w/ cardinality ~ 1M INDEX (`created_date`) -- <--

ubuntu date的用法

由 冷暖自知 提交于 2020-12-15 08:28:58
方法一： sudo date 031421302011(月日时分年) 方法二： sudo date -s 20110314 //先修改年月日 sudo date -s 21:30 //在修改时分 如果还需要修改BIOS时间，再执行： clock -w | hwclock -w 查看时间 date +'%F %T' echo `date +%Y-%m-%d_%H:%M:%S` date +%Y-%m-%d_%H:%M:%S 备忘 %% 一个文字的 % %a 当前locale 的星期名缩写(例如： 日，代表星期日) %A 当前locale 的星期名全称 (如：星期日) %b 当前locale 的月名缩写 (如：一，代表一月) %B 当前locale 的月名全称 (如：一月) %c 当前locale 的日期和时间 (如：2005年3月3日 星期四 23:05:25) %C 世纪；比如 %Y，通常为省略当前年份的后两位数字(例如：20) %d 按月计的日期(例如：01) %D 按月计的日期；等于%m/%d/%y %e 按月计的日期，添加空格，等于%_d %F 完整日期格式，等价于 %Y-%m-%d %g ISO-8601 格式年份的最后两位 (参见%G) %G ISO-8601 格式年份 (参见%V)，一般只和 %V 结合使用 %h 等于%b %H 小时(00-23) %I 小时(00

How to format a date by any locale obtained from language tag with java time?

由 谁都会走 提交于 2020-12-15 06:27:07
问题 I want to get a date as string and a language tag and based on that to parse the string by the locale format. This is what I've done so far: public static String formatDateByLocale(String date, String languageTag) { Locale locale = Locale.forLanguageTag(languageTag); String datePattern = DateTimeFormatterBuilder.getLocalizedDateTimePattern(FormatStyle.LONG, FormatStyle.LONG, Chronology.ofLocale(locale), locale); DateTimeFormatter targetFormat = DateTimeFormatter.ofPattern(datePattern)

Can't get data from date to date SQLite

由 99封情书 提交于 2020-12-15 05:32:45
问题 I have an SQLite database in android and I want to Select From a table "Transactions" only data from date1 till date2. Code: SELECT * FROM Transactions WHERE DATE(substr(transactiondate,7,4) ||substr(transactiondate,4,2) ||substr(transactiondate,1,2)) BETWEEN DATE(20201030) AND DATE(20201031) Here is the database data result of query: Execution finished without errors. Result: 0 rows returned in 13ms Update: Here is how I changed my data to "year-month-day" format: val c = Calendar

Can't get data from date to date SQLite

由 余生长醉 提交于 2020-12-15 05:32:35
问题 I have an SQLite database in android and I want to Select From a table "Transactions" only data from date1 till date2. Code: SELECT * FROM Transactions WHERE DATE(substr(transactiondate,7,4) ||substr(transactiondate,4,2) ||substr(transactiondate,1,2)) BETWEEN DATE(20201030) AND DATE(20201031) Here is the database data result of query: Execution finished without errors. Result: 0 rows returned in 13ms Update: Here is how I changed my data to "year-month-day" format: val c = Calendar

Flutter - Group date wise and show under a sticky header

由 六月ゝ 毕业季﹏ 提交于 2020-12-15 05:22:07
问题 I want to group all list tiles according dates which are same and show them under sticky bar as shown in the picture. I get the dates from sqlite database. The data from the database is in format like this: 21-01-2020. It should show Today, tomorrow and date for example 28 Nov 2020 as in the picture. ListView.builder( ... return listTile( title: Text(items[position0].dates), //dates from database, returns 21-01-2020 ), ), At last I just want results like the below picture by comparing dates
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