datasource

The goal is to create a UIPageViewController that can only navigate forward. I am using a data source to provide the content for the UIPageViewController. The direction is set to UIPageViewControllerNavigationDirectionForward , the transition style is UIPageViewControllerTransitionStyleScroll . The implementation of - (UIViewController *)pageViewController:(UIPageViewController *)pageViewController viewControllerAfterViewController:(UIViewController *)viewController { // returns the next view controller } returns the next view controller, while the following should ensure navigating backwards

Is it possible to bind programatically a DataSource to Tomcat's 6 JNDI? I want to create a DataSource on the fly and then make it available through JNDI ( to ColdFusion for instance ). This is what I have: public void bindToConext(DataSource dataSource) throws NamingException, SQLException { Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup("java:/comp/env"); envContext.bind("jdbc/mydatasource", dataSource); } But I'm getting this exception: javax.naming.OperationNotSupportedException: Context is read only Is there a work around? Well it was not

I have created a JNDI data-source using my weblogic console but I am not able to access the object from my web application. Below are the details In weblogic 10.3.6, I have given the JNDI name for datasource as : jdbc/mydb To get DB connection from my web application I have written this code in my web application: Context initContext = new InitialContext(); DataSource ds = (DataSource)initContext.lookup("java:/comp/env/jdbc/mydb"); jndiConnection = ds.getConnection(); Earlier I was using Tomcat as server and I was able to get DB connection when I configured the resource details in the file

I have the following method that load products on a DataGridView private void LoadProducts(List<Product> products) { Source.DataSource = products; // Source is BindingSource ProductsDataGrid.DataSource = Source; } And now I'm trying to give me back to save them as shows below. private void SaveAll() { Repository repository = Repository.Instance; List<object> products = (List<object>)Source.DataSource; Console.WriteLine("Este es el número {0}", products.Count); repository.SaveAll<Product>(products); notificacionLbl.Visible = false; } But I get an InvalidCastException on this line: List<object>

I would like to set the delegate and datasource for 'tableView in ViewController.swift` file. I wrote this code in my viewDidLoad function, but it's not working. Code: tableView.delegate?.self tableView.dataSource?.self I'm working with CoreData and my Entity is named "Note". Hope someone can help me to solve this problem. The correct way to set the delegate and data source is: tableView.delegate = self tableView.dataSource = self adijazz91 Do this, it will work tableView.delegate = self tableView.dataSource = self 来源： https://stackoverflow.com/questions/27022136/set-delegate-and-datasource-of

I have a datasource in tomcat which has password that is encrypted using some algorithm and I want to decrypt the same when i establish connection with DB. Following is my spring config code <!--<bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiName" value="${jdbc.jndiName}"/> </bean>--> <bean id="dataSource" class="my.app.util.EncryptedDataSource"> <property name="jndiName" value="${jdbc.jndiName}"/> </bean> The above bean is a custom one that extends the JndiObjectFactoryBean public class EncryptedDataSource extends JndiObjectFactoryBean{ ... }