datagridtemplatecolumn

How to reuse a custom datagrid column code in WPF?

為{幸葍}努か 提交于 2021-02-08 05:43:20
问题 Using VS 2010 I plan to make several datagrid template columns, but they will all contain a textblock and I want to them to behave like a text column in terms of sorting, filtering, editing, etc. (For example, a column that has a textblock and an image within a stackpanel, but behavior-wise it should really be all about the text.) When using a template column, I've learned that much of the functionality associated with a normal text cell must be redone. For instance, in order to make the text

DataGridTemplateColumn Two way binding is not working

好久不见. 提交于 2020-01-30 20:15:12
问题 I've got a datagrid I've bound to a SqlDataApter. If I set up the XAML for the grid using DataTextColumn as illustrated in the code below it works perfectly <DataGrid AutoGenerateColumns="False" HorizontalAlignment="Left" Margin="27,42,0,0" Name="dataGrid1" VerticalAlignment="Top" AreRowDetailsFrozen="True"> <DataGrid.Columns> <DataGridTextColumn Binding="{Binding KEY}" Visibility="Hidden" IsReadOnly="True"></DataGridTextColumn> <DataGridTextColumn Binding="{Binding CHARACTERISTIC_CODE}"

different kinds of cells in the same column

*爱你&永不变心* 提交于 2020-01-17 11:15:17
问题 I need to render a datagrid with different kinds of cells in the same column. For example, I have a datagrid with a column "name" and a column "value". Depending on the "type" of my record, I would have different cells in the column "value" like a combobox or a simple textfield. and I don't really see how to do that programmatically... I don't know if the datagrid is the best choice. Any hint? I'm using asp.net/vb.net with framework 3.5 回答1: You can do that using the user control, where you

different kinds of cells in the same column

…衆ロ難τιáo~ 提交于 2020-01-17 11:12:06
问题 I need to render a datagrid with different kinds of cells in the same column. For example, I have a datagrid with a column "name" and a column "value". Depending on the "type" of my record, I would have different cells in the column "value" like a combobox or a simple textfield. and I don't really see how to do that programmatically... I don't know if the datagrid is the best choice. Any hint? I'm using asp.net/vb.net with framework 3.5 回答1: You can do that using the user control, where you

How can I add combo Box In a Table cell using LWUIT — J2ME?

依然范特西╮ 提交于 2020-01-15 05:47:52
问题 I want to add a combo Box in table cell to provide drag n drop option LWUIT. I have used this option for it .. private String strCmbBox[] = { "1", "2", "3", "4" }; ComboBox comboRdoBox = new ComboBox(strCmbBox); comboRdoBox.setListCellRenderer(new comboBoxRenderer()); TableModel model = new DefaultTableModel(new String[] { "Col 1", "Col 2", "Col 3" }, new Object[][] { {"Row 1",new DefaultTableModel(new String[] { "1" }, new Object[][] { { comboRdoBox }, { "lbl" } }), "Row X" }, { "Row 2",

Grabbing reference to element inside DataGridTemplateColumn

穿精又带淫゛_ 提交于 2020-01-05 18:12:39
问题 I've been struggling with this problem for a while now and can't seem to get any answers on it. I've mocked up a simple XAML file to demonstrate the problem (I'm not providing my real XAML file since it has more in it than needed for this question). Here is my question: given the following XAML file how can I get a reference in my codebehind to the selectHeight ComboBox that resides in the DataGridTemplateColumn.CellEditingTemplate DataTemplate? I need the reference so that I can change a

Grabbing reference to element inside DataGridTemplateColumn

南楼画角 提交于 2020-01-05 18:12:32
问题 I've been struggling with this problem for a while now and can't seem to get any answers on it. I've mocked up a simple XAML file to demonstrate the problem (I'm not providing my real XAML file since it has more in it than needed for this question). Here is my question: given the following XAML file how can I get a reference in my codebehind to the selectHeight ComboBox that resides in the DataGridTemplateColumn.CellEditingTemplate DataTemplate? I need the reference so that I can change a