cut

echo output not getting assigned to a variable in shell script

由 淺唱寂寞╮ 提交于 2020-03-25 19:24:12
问题 end=echo $FSDB_FILE_NAME | rev | cut -d'_' -f 2 |rev begin=echo $FSDB_FILE_NAME | rev | cut -d'_' -f 3 |rev echo $end echo $begin echo abc_11204.00_15713.00_.csv | rev | cut -d'_' -f 2 |rev ---- This works But echo $end is not printing anything I even tried: set end=echo abc_11204.00_15713.00_.csv | rev | cut -d'_' -f 2 |rev echo $end This prints empty Please help me with this Sample input : abc_123.00_345.00_xyz.csv Output : end=345.00 begin=123.00 回答1: Could you please try following. Easy

Implementing copy, cut and paste

由 依然范特西╮ 提交于 2020-03-23 06:58:08
问题 I want to implement copy, cut and paste in my drawing program (copy part of an image that is selected) I don't know how to start Any Ideas? 回答1: to copy: take the selected rectangle, create a new image of that size, take a copy of the current image and place it on the new rectangle, offset by the topleft of the selected rectangle 回答2: in short there are two ways exists 1) your own clipboard 2) system-wide clipboard in second case use must use standard format for storing your data. read MSDN

Linux命令-cut

由 邮差的信 提交于 2020-02-04 06:59:27
cut命令用于通过列来提取文本字符 格式：cut [参数] 文本 将/etc/paswd文件以：分割（-d:），获取第七列的内容(-f1) [root@localhost test]# cut -d: -f7 /etc/passwd /bin/bash /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /bin/sync /sbin/shutdown /sbin/halt /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /bin/bash /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin/nologin /sbin

Use cut to create 24 categories for a time variable

由 爷，独闯天下 提交于 2020-01-30 10:58:46
问题 Here I import the data, do some manipulations to it (this is likely not going to be where the issue/fix lies) The first two lines set my parameters for my cut. lab_var_num <- (0:24) times_var <-c(0,100,200,300,400,500,600,700,800,900,1000,1100,1200,1300,1400,1500,1600,1700,1800,1900,2000,2100,2200,2300,2400,2500) all_files_ls <- read_csv("~/Desktop/bioinformatic_work/log_parse_files/sorted_by_habitat/all_trap/all_files_la_selva_log.csv") #Eliminate bad data and capture in separate dataframe-

Find and cut out a python substring

由 吃可爱长大的小学妹 提交于 2020-01-25 06:30:06
问题 Here is what I'm trying to do: I have a long string: s = asdf23rlkasdfidsiwanttocutthisoutsadlkljasdfhvaildufhblkajsdhf I want to cut out the substring: iwanttocutthisout I will be iterating through a loop and with each iteration the value of s will change. The only thing that will stay the same with each iteration is the begining and end of the substring to be cut out: iwant and thisout. How can I cut out the substring, given these parameters? Thanks for your help! 回答1: You can do a slice

How to use regex with cut at the command line?

由 爱⌒轻易说出口 提交于 2020-01-24 10:09:27
问题 I have some output like this from ls -alth : drwxr-xr-x 5 root admin 170B Aug 3 2016 .. drwxr-xr-x 5 root admin 70B Aug 3 2016 .. drwxr-xr-x 5 root admin 3B Aug 3 2016 .. drwxr-xr-x 5 root admin 9M Aug 3 2016 .. Now, I want to parse out the 170B part, which is obviously the size in human readable format. I wanted to do this using cut or sed , because I don't want to use tools that are any more complicated/difficult to use than necessary. Ideally I want it to be robust enough to handle the B ,

Bash: How to trim whitespace before using cut

由 浪尽此生 提交于 2020-01-22 17:50:06
问题 I have a line of output from a command like this: []$ <command> | grep "Memory Limit" Memory Limit: 12345 KB I'm trying to pull out the 12345. The first step - separating by the colon - works fine []$ <command> | grep "Memory Limit" | cut -d ':' -f2 12345 KB Trying to separate this is what's tricky. How can I trim the whitespace so that cut -d ' ' -f1 returns "12345" rather than a blank? 回答1: Pipe your command to awk, print the 3rd column, a space and the 4th column like this <command> | awk

How to grep rows that have value less than 0.2 in a specific column?

由 谁都会走 提交于 2020-01-22 12:15:52
问题 ID RT EZ Z0 Z1 Z2 RHO PHE 1889 UN NA 1.0000 0.0000 0.0000 0.8765 -1 1890 UN NA 1.0000 0.0000 0.0000 0.4567 -1 1891 UN NA 1.0000 0.0000 0.0000 0.0012 -1 1892 UN NA 1.0000 0.0000 0.0000 0.1011 -1 I would like to grep all the IDs that have column 'RHO' with value less than 0.2, and the other columns are included for the selected rows. 回答1: Use awk directly by saying awk '$field < value' : $ awk '$7<0.2' file 1891 UN NA 1.0000 0.0000 0.0000 0.0012 -1 1892 UN NA 1.0000 0.0000 0.0000 0.1011 -1 As

Unix cut except last two tokens

由 Deadly 提交于 2020-01-12 11:47:38
问题 I'm trying to parse file names in specific directory. Filenames are of format: token1_token2_token3_token(N-1)_token(N).sh I need to cut the tokens using delimiter '_' , and need to take string except the last two tokens. In above examlpe output should be token1_token2_token3 . The number of tokens is not fixed. I've tried to do it with -f#- option of cut command, but did not find any solution. Any ideas? 回答1: With cut: $ echo t1_t2_t3_tn1_tn2.sh | rev | cut -d_ -f3- | rev t1_t2_t3 rev

Manipulation on levels produced by cut R function

由 送分小仙女□ 提交于 2020-01-05 13:50:25
问题 I want to do some manipulation on levels produced by cut R function. I want to have exp(Labs) in my MWE. set.seed(12345) Y <- rnorm(n = 50, mean = 500, sd = 1) Y1 <- cut(log(Y), 5) Labs <- levels(Y1) Labs [1] "(6.21,6.212]" "(6.212,6.213]" "(6.213,6.215]" "(6.215,6.217]" "(6.217,6.219]" exp(cbind(lower = as.numeric( sub("\\((.+),.*", "\\1", Labs) ), upper = as.numeric( sub("[^,]*,([^]]*)\\]", "\\1", Labs) ))) lower upper [1,] 497.7013 498.6976 [2,] 498.6976 499.1966 [3,] 499.1966 500.1960 [4,
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