currying

I'm trying to figure out a way to automatically cast something to an Action or Func and the best I can come up with is something like this: [TestFixture] public class ExecutionTest { public void BadMethod() { throw new Exception("Something bad happened"); } [Test] public void TestBadMethod() { // Want this, but it won't work!! // BadMethod.Execute().IgnoreExceptions(); // Ick ((Action)BadMethod).Exec().IgnoreExceptions(); // Still ick ((Action)BadMethod).IgnoreExceptions(); // Do not want ExtensionMethods.Exec(BadMethod).IgnoreExceptions(); // Better but still meh this.Exec(BadMethod)

Let's say I have some function: function g(a,b,c){ return a + b + c } And I'd like to turn it into its "curried" form (in quotations since it's not exactly curried per se): function h(a,b,c){ switch(true){ case (a !== undefined && b !== undefined && c !== undefined): return a + b + c case (a !== undefined && b !== undefined && c === undefined): return function(c){ return a + b + c } case (a !== undefined && b == undefined && c === undefined ): return function(b,c){ return (c === undefined) ? function(c){ return a + b + c } : a + b + c } default: return h } } The above form has the partial

I was trying to implement the function every :: (a -> IO Bool) -> [a] -> IO Bool which was the topic for this question . I tried to do this without explicit recursion . I came up with the following code every f xs = liftM (all id) $ sequence $ map f xs My function didn't work since it wasn't lazy (which was required in the question), so no upvotes there :-). However, I did not stop there. I tried to make the function point-free so that it would be shorter (and perhaps even cooler). Since the arguments f and xs are the last ones in the expression I just dropped them: every = liftM (all id) $

This question already has an answer here: Feed elements of a tuple to a function as arguments in Haskell? 3 answers Sometimes I have two functions of the form: f :: a -> (b1,b2) h :: b1 -> b2 -> c and I need the composition g. I solve this by changing h to h': h' :: (b1,b2) -> c Can you please show me (if possible) a function m, so that: (h . m . f) == (h' . f) Or another way to deal with such situations. Thanks. What you're looking to do is to take a function that operates on curried arguments, h , and apply it to the result of f , which is a tuple. This process, turning a function of two

While I understand a little about currying in the mathematical sense, partially applying an infix function was a new concept which I discovered after diving into the book Learn You a Haskell for Great Good . Given this function: applyTwice :: (a -> a) -> a -> a applyTwice f x = f (f x) The author uses it in a interesting way: ghci> applyTwice (++ [0]) [1] [1,0,0] ghci> applyTwice ([0] ++) [1] [0,0,1] Here I can see clearly that the resulting function had different parameters passed, which would not happen by normal means considering it is a curried function (would it?). So, is there any

This question already has answers here : Defining a function by equations with different number of arguments (3 answers) Closed 2 years ago . With multiple pattern-matching, different numbers of arguments are impossible, even with point-free! foo True b = b + 2 foo _ = id doesn't work for example. But foo True = (+2) foo _ = id does. Sometimes we can use point-free only in one part of the function, so... Why? Is it too hard for GHC? :'( Why? Is it too hard for GHC? No . It is not at all too hard for GHC. Actually, this is the fault of the Haskell Report. See: Haskell Report 2010 > Declarations