curly-braces

I'm reading some lecture notes of my C++ lecturer and he wrote the following: Use Indentation // OK Never rely on operator precedence - Always use parentheses // OK Always use a { } block - even for a single line // not OK , why ??? Const object on left side of comparison // OK Use unsigned for variables that are >= 0 // nice trick Set Pointer to NULL after deletion - Double delete protection // not bad The 3rd technique is not clear to me: what would I gain by placing one line in a { ... } ? For example, take this weird code: int j = 0; for (int i = 0 ; i < 100 ; ++i) { if (i % 2 == 0) { j++;

I have some Java code that uses curly braces in two ways // Curly braces attached to an 'if' statement: if(node.getId() != null) { node.getId().apply(this); } // Curly braces by themselves: { List<PExp> copy = new ArrayList<PExp>(node.getArgs()); for(PExp e : copy) { e.apply(this); } } outAMethodExp(node); What do those stand-alone curly braces after the first if statement mean? The only purpose of the extra braces is to provide scope-limit. The List<PExp> copy will only exist within those braces, and will have no scope outside of them. If this is generated code, I assume the code-generator

Is there a way in Visual Studio 2008 to go from a closing brace to its opening brace? I've found a fair amount of stuff about highlighting the brace, but nothing about moving the cursor to it. (VB.NET version of this Question: Keyboard shortcut for Jumping between "If/End If" ) Tim Santeford I found this for you: Jump between braces in Visual Studio Put your cursor before or after the brace (your choice) and then press CTRL + ] . It works with parentheses ( ), brackets [ ] and braces { }. From now on you don’t need to play Where’s Waldo? to find that brace. Use CTRL + ] to switch between them.

Straight forward question: Is there an advantage or disadvantage to concatenating variables within strings or using curly braces instead? Concatenated: $greeting = "Welcome, ".$name."!"; Curly braces: $greeting = "Welcome, {$name}!"; Personally, I've always concatenated my strings because I use UEStudio and it highlights PHP variables a different color when concatenated. However, when the variable is not broken out, it does not. It just makes it easier for my eyes to find PHP variables in long strings, etc. EDIT: People are confusing this about being about SQL. This is not what this question

While watching thenewbostons tutorial on basic java, he teaches us to do if statements like this.(Notice the curly Braces) if("pie"== "pie"){ System.out.println("Hurrah!"); } So I tried removing the curly braces if("pie"== "pie") System.out.println("Hurrah!"); And it still works! Since I'm new to java, I don't know why that works. And I want to know if removing(or adding) the curly braces give any benefits/disadvantages. Habib For a single statement it will remain same, but if you want to group more than one statement in the if block then you have to use curly braces. if("pie"== "pie"){ System

First question on SO and it's a real RTM candidate. But I promise you I've looked and can't seem to find it. I'll happily do a #headpalm when it turns out to be a simple thing that I missed. Trying to figure out Zend Framework and came across the following syntax: $this->_session->{'user_id'} I have never seen the curly braces syntax used to access what appears to be a member variable. How is it different than $this->_session->user_id I'm assuming that the _session is irrelevant, but including it in the question since it may not be. Are the curly braces just a cleanliness convention that

can someone, please explain the following: I'm following Dan Abramov's lectures & doing the exercises. The code works fine, however, the tests fail when the following particular function is written with curly brackets **{ }** . case 'toggleTodo' : return ( state.map( (one) => { oneTodo( one, action ) }) ); The same code works fine without curly brackets. case 'toggleTodo' : return ( state.map( (one) => oneTodo( one, action ) ) ); Here is the JsBin . Please refer to line 31 onwards. case 'toggleTodo' : return ( state.map( (one) => oneTodo( one, action ) ) ); is equal to: case 'toggleTodo' :