create-view

Django Help: Resolving NOT NULL constraint failed error with CreateView

亡梦爱人 提交于 2019-12-10 16:57:37
问题 I am new to stackoverflow, python and Django, have a question on the '(NOT NULL constraint failed: sixerrapp_gig.user_id)' error I am getting when i click submit on the form. Pretty sure it is because I have not assigned a user_id value from what I have found on StackOverflow thus far, but I am not sure how to do it using the django CreateView. The project exercise is based on a clone of fiverr.com. Please see code below: in models.py: from django.db import models from django.contrib.auth

Django CreateView customise form default field based on url parameter

我怕爱的太早我们不能终老 提交于 2019-12-10 09:13:16
问题 file: Capacity/models.py class Env(models.Model): name = models.CharField(max_length=50) def get_absolute_url(self): return reverse('index') class Envhosts(models.Model): env = models.ForeignKey(Env) hostname = models.CharField(max_length=50) count = models.IntegerField() class Meta: unique_together = ("env","hostname") def get_absolute_url(self): return reverse('index') file: Capacity/views.py class EnvhostsCreate(CreateView): model = Capacity.models.Envhosts fields=['env','hostname','count'

BLOB in MySQL view instead of the proper data

好久不见. 提交于 2019-12-07 20:17:07
问题 I created a MySQL view using UNION ALL from two tables so that I would get the same column names for the same data in those tables (i.e. tbl1.author2 AS translator ... tbl2.translator AS translator ) and so on, the problem is when I try to select something from that view, half of the data comes out as BLOB , instead of the original value. The view definition is: SELECT e.id AS prod_id, e.price_vat AS price_vat, e.product AS title, e.authors AS author, e.isbn AS isbn, e.ean AS ean, e.page

Split column values into multiple columns with CREATE VIEW

谁说我不能喝 提交于 2019-12-06 16:04:55
With a MySQL query, how can I take a table like in Example A: Example A +------+---------------+----------+ | id | value | class | +------+---------------+----------+ | 1 | 33.00 | total | | 1 | 12.00 | shipping | | 2 | 45.00 | total | | 2 | 15.00 | shipping | +------+---------------+----------+ And create a view like Example B? Example B +------+---------------+---------------+ | id | value_total | value_shipping| +------+---------------+---------------+ | 1 | 33.00 | 12.00 | | 2 | 45.00 | 15.00 | +------+---------------+---------------+ You can simply use SUM() function for that: SELECT id

BLOB in MySQL view instead of the proper data

血红的双手。 提交于 2019-12-06 13:41:49
I created a MySQL view using UNION ALL from two tables so that I would get the same column names for the same data in those tables (i.e. tbl1.author2 AS translator ... tbl2.translator AS translator ) and so on, the problem is when I try to select something from that view, half of the data comes out as BLOB , instead of the original value. The view definition is: SELECT e.id AS prod_id, e.price_vat AS price_vat, e.product AS title, e.authors AS author, e.isbn AS isbn, e.ean AS ean, e.page_count AS page_count, e.publishers AS publishers, e.issue_year AS issue_year, 'e' AS type FROM ama_euromedia

django createview how to get the object that is created

人走茶凉 提交于 2019-11-28 20:12:08
i've two concatenated form. Basically user fills in the first form and then is redirected to the second one which adds value to the data of the first form. E.G. I've a form Movie (first form) and then i'm redirected to the form (actor) which add the actor to the movie. in my case the Movie = Chiamata and Actor = Offerta (i keep the italians name for what i need :D) fine. those are my urls in the urls.py url(r'^chiamata/$', ChiamataCreate.as_view(),name='chiamata_create'), url(r'^chimamata/(?P<pk>\d+)/offerta$', OffertaCreate.as_view(), name='offerta_create'), i've this create view class

grant create view on Oracle 11g

核能气质少年 提交于 2019-11-28 09:11:17
问题 I use SQL*Plus for school and I use the username Scott. I cannot create views because it says: ORA-01031: insufficient privileges; I've searched and searched, but nothing seems to get it right. Any help? 回答1: As the error states - your privileges are insufficient to create view - you will have to ask database administrator to grant you this privilege. If you can log in as database administrator you will have to execute statement(I can't guarantee correctness, no oracle database at hand) GRANT

django createview how to get the object that is created

生来就可爱ヽ(ⅴ<●) 提交于 2019-11-27 12:47:10
问题 i've two concatenated form. Basically user fills in the first form and then is redirected to the second one which adds value to the data of the first form. E.G. I've a form Movie (first form) and then i'm redirected to the form (actor) which add the actor to the movie. in my case the Movie = Chiamata and Actor = Offerta (i keep the italians name for what i need :D) fine. those are my urls in the urls.py url(r'^chiamata/$', ChiamataCreate.as_view(),name='chiamata_create'), url(r'^chimamata/(?P